In one experiment, you do not have the metal oxalate product as dry as possible. How might this affect the pyrolysis procedure?

Answers

Answer 1

Answer:

In one experiment, you do not have the metal oxalate productas dry as possible. This might affect the pyrolysis procedure by maybe thewater will react with the compound at very high temp; the initial weight of thesample is already incorrect that might cause error in the further calculations.

Answer 2

Answer:

Answer:

The process would not be attained completely.

Explanation:

Hello,

In chemical reactions, pyrolysis is understood as a thermochemical decomposition or breaking of organic chains at very high temperatures and under the absence of halogens and oxygen. In this case, as a metal oxalate is the organic chain, when it is a product and is not dry as possible, the reaction would not be attained to completion as the water will limit the conversion and the reaction extent.

Best regards.

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What is the mass of oxygen in 250 go of sulfiric acid, H2CO4

6.579 rounded to nearest hundreth

Answers

Answer:

6.58

Explanation:

Barium chloride + sodium phosphate 
Answer with double replacement

Answers

Answer:

Barium chloride + Sodium phosphate → barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄ → Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄ → Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.

Molecular equation:

Barium chloride + Sodium phosphate → barium phosphate + sodium chloride

Final answer:

A double replacement reaction between barium chloride and sodium phosphate results in the formation of barium phosphate and sodium chloride.

Explanation:

The given chemical equation represents a double replacement reaction. The chemical reactants are barium chloride (BaCl2) and sodium phosphate (Na3PO4). In a double replacement reaction, the cations and anions of the two reactants switch places to form two new compounds.

So here is how the reaction would proceed: BaCl2 + Na3PO4 -> Ba3(PO4)2 + NaCl.

This translates to: Barium chloride reacts with sodium phosphate to form barium phosphate and sodium chloride.

Learn more about double replacement reaction here:

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Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, this type of reaction is used to produce products such as margarine. A typical hydrogenation reaction is C10H20() + H2(g) → C10H22(5) Decene Decane How much decane can be produced in a reaction of excess decene with 2.45 g hydrogen? Give your answer in scientific notation. O *10 g decane

Answers

Answer: The mass of decane produced is $1.743* 10^2g$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

$\text{Moles of }H_2=(2.45g)/(2g/mol)=1.225mol$

The chemical equation for the hydrogenation of decene follows:

$C_(10)H_(20)(l)+H_2(g)\rightarrow C_(10)H_(22)(s)$

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = $(1)/(1)* 1.225=1.225mol$ of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

$1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\n\n\text{Mass of carbon dioxide}=(1.225mol* 142.30g/mol)=174.3g=1.743* 10^2g$

Hence, the mass of decane produced is $1.743* 10^2g$

How much is a share in namsek worth as a percent of a share in oxd group

Answers

Answer:

10% is a share in NAMSEK worth as a percentage of a share in ODX Group Inc., in year 4

EXPLANATION:give brainliest

The share of NAMSEK in year 4 is around $ shares (as given from the above table). Hence the value of one share will be $2.5/share

The share of ODX Group Inc., in year 4 is around $ shares (as given from the above table). Hence the value of one share is $

Therefore a share in NAMSEK worth as a percentage of a share in ODX Group Inc., in year 4 will be

= 0.1 or 10 %

Which two structures will provide a positive identification of a plant cell under a microscope? A.) Lysosomes, cell wall. B.) large central vacuole, cell wall. C.) large central vacuole ribosomes. D.)nucleoid, chloroplasts.

Answers

The Right Answer Is D.) Nucleoid chloroplasts.

the answer is B large central vacuole and cell wall. they are the easiest/biggest things to see under a microscope to identify a plant cell

Solve the following problem:

Answers

Answer:

Option 3.

Explanation:

Isomerism is a phenomenon where by two or more compounds have the same molecular formula but different structural patterns.

Geometric Isomerism is a type of Isomerism that occurs within a double bond i.e Geometric isomers have different arrangement within the double bond.

Considering the options given above,

The 1st option is exactly the same as the compound only, it is inverted.

The 2nd option is still the same as the compound, only it is laterally inverted.

The 3rd option satisfy geometric Isomerism as the arrangement differ from the compound in the double bond.

The 4th option is entirely a saturated compound in which geometric Isomerism is not possible.

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