What type of reaction is
CH 4 (g)+2O 2 (g) CO 2 (g)+2H 2 O(g)

Answers

Answer 1
Answer:

Answer: combustion

Explanation:

Combustion reactions can be identified by looking at the reactants and the products.

Usually, the reactants will be a hydrocarbon and oxygen. And the products will be CO2 and H2O


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Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? 3. 1. 4. 2.

Answers

The stoichiometric coefficient for aluminum, Al when the chemical equation is balanced is 2.

To obtain the stoichiometric coefficient for aluminum, we shall write and balance the equation for the reaction. This is illustrated below:

Aluminum => Al

Iron (II) chloride => FeCl₂

Aluminum chloride => AlCl₃

Iron => Fe

Aluminum + Iron (II) chloride —> Aluminum chloride + Iron

Al + FeCl₂ –> AlCl₃ + Fe

There are 3 atoms of Cl on the right side and 2 atoms on the left side. It can be balance by writing 3 before FeCl₂ and 2 before AlCl₃ as shown below:

Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 2 atoms of Al on the right side and 1 atom on the left. It can be balance by writing 2 before Al as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 3 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 3 before Fe as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + 3Fe

Now, the equation is balanced.

The coefficient of Aluminum, Al in the balanced equation is 2.

Learn more about balancing equation:

brainly.com/question/2399130

Answer:

2.

Explanation:

  • The balanced chemical equation for the reaction of aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal is:

2Al(s) + 3FeCl₂(aq) → 2AlCl₃(aq) + 3Fe(s).

It is clear that 2 mol of Al react with 3 mol of FeCl₂ to produce 2 mol of AlCl₃ and 3 mol of Fe.

  • So, the the stoichiometric coefficient for aluminum when the chemical equation is balanced is 2.

Which expression could represent theconcentration of a solution?
(1) 3.5 g
(2) 3.5 M
(3) 3.5 mL
(4) 3.5 mol

Answers

There are a couple of ways in which you can express the concentration of a solution, and here they are: gram per liter (g/L), molarity (M), parts per million (ppm.), and percents (%). 
As you can see, only M appears in your answers, which means that the correct option should be (2) 3.5 M.

The expression for representation of concentration of a solution has been 3.5 M. Thus, option 2 is correct.

Concentration has been defined as the amount of substance present in a volume of solution. The concentration has been given by varying units. The concentration has been given by mass per unit volume.

It can be represented by moles/L or g/L. The expression that has been similar to moles/L has been molarity.

Thus, the expression for representation of concentration of a solution has been 3.5 M. Thus, option 2 is correct.

For more information about concentration, refer to the link:

brainly.com/question/3045247

If a shell can hold a maximum of 32 electrons, what is the value of n?

Answers


In my textbook it says that the maximum number of electrons that can fit in any given shell is given by 2n². Which would mean 2 electrons could fit in the first shell, 8 could fit in the second shell, 18 in the third shell, and 32 in the fourth shell. However, I was previously taught that the maximum number of electrons in the first orbit is 2, 8 in the second orbit, 8 in the third shell, 18 in the fourth orbit, 18 in the fifth orbit, 32 in the sixth orbit. I am fairly sure that orbits and shells are the same thing.

Can someone how to do these problems!!

Answers

You can use the follwing equations.
pH=14-pOH
pOH=-log[OH⁻]

a)  pOH=-log10⁻¹²
     pOH=12
     pH=14-12
     pH=2

You can also use these equations:
[H⁺]=K(w)/[OH⁻]    (K(w)=1.01×10⁻¹⁴)
pH=-log[H⁺]

b) [H⁺]=(1.01×10⁻¹⁴)/10⁻²M
    [H⁺]=1.01×10⁻¹²M²
    pH=-log(1.01×10⁻¹²)
    pH=12

You can use either method.  It does not really matter.
I hope this helps.  Let me know if anything is unclear and when you do the calculations for c you should get pH=7.

Which molecule contains a triple covalent
bond?
(1) H2 (3) O2
(2) N2 (4) Cl2

Answers

Answer: The correct answer is Option 2.

Explanation:

Covalent bond is defined as the b which is formed by the sharing of electrons between the atoms forming a bond.

Non-polar covalent bond is defined as the bond which is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example:N_2,O_2 etc..

For the given options:

  • Option 1:  H_2

Hydrogen is the 1st element of the periodic table having electronic configuration 1s^1

This element needs 1 electron to attain stable electronic configuration and will form single covalent bond with another hydrogen atom.

  • Option 2:  N_2

Nitrogen is the 7th element of the periodic table having electronic configuration 1s^22s^22p^3

This element needs 3 electrons to attain stable electronic configuration and will form triple covalent bond with another nitrogen atom.

  • Option 3:  O_2

Oxygen is the 8th element of the periodic table having electronic configuration 1s^22s^22p^4

This element needs 2 electrons to attain stable electronic configuration and will form double covalent bond with another oxygen atom.

  • Option 4:  Cl_2

Chlorine is the 17th element of the periodic table having electronic configuration 1s^22s^22p^63s^23p^5

This element needs 1 electron to attain stable electronic configuration and will form single covalent bond with another chlorine atom.

Hence, the correct answer is Option 2.

N2 because it has 5 valence atoms so it needs 3 to have 8, wich is the octet rule, so three is a triple covalent bond

Explain why the elements of groups 1 and 7 are mostly used in
the form of compound

Answers

Group 1 and group 7 of element group consists of alkali metal, which are generally combined with other elements in nature, so they have properties of compound