What is the temperature of 1.2 moles of Helium gas at 1950 mm Hg if it occupies 15,500 ml of volume?

Answers

Answer 1

Answer:

Answer:

$T=404.16K=13.1^oC$

Explanation:

Hello,

In this case, we use the ideal gas equation to compute the requested temperature as shown below and considering the proper units:

$PV=nRT\nT=(PV)/(nR)=(1950mmHg*(1atm)/(760mmHg)*15500mL*(1L)/(1000mL) )/(1.2mol*0.082 (atm*L)/(mol*K) ) \nT=404.16K=13.1^oC$

Best regards.

Answer 2

Answer:

Replace with

1950

1950mmHg and simplify.

1.2

1950

500

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Answers

Answer:

#2 bro

Explanation:

Answer: protons and electrons

Explanation: :)

Convert 338 L at 3.0 atm to its new volume at standard pressure. 1,014L

Answers

Answer:

1014 L

Explanation:

From the question,

Applying

PV = P'V'.................... Equation 1

Where P = initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume

make V' the subject of the equation

V' = PV/P'........... Euqation 2

Given: P = 3 atm, V = 338L, P' = 1 atm (Standard pressure)

Substitute into equation 2

V' = (3×338)/1

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Reflecting and refracting telescopes are used to gather radiation from space. Which of these statements best explains why a refracting telescope is made smaller than a reflecting telescope?A. Small lenses cause less distortion in images than big lenses.

B. Small lenses cause more distortion in images than big lenses.

C. Small telescopes gather more radiation from space than big telescopes.

D. Small telescopes produce clearer images of distant objects than big telescopes.

* PLEASE ONLY ANSWER THIS QUESTION IF YOU KNOW YOUR ANSWER IS 100% CORRECT * Thank you! :)

-Also- I have heard there is "no right answer" to this question from others, but I still need to answer it, (preferably correctly!)

Answers

I think the correct answer from the choices listed above is option A. A refracting telescope is made smaller than a reflecting telescope because small lenses cause less distortion in images than big lenses. They are not subject to chromatic aberration because reflected light does not disperse according to wavelength.

Answer:A

Explanation:Test

One hundred students were surveyed about who they would vote for. What isthe best way to display the results? Explain your answer.

Answers

Hey hope this helps ⬇️

Exothermic changes: the system ____________ the surroundings. the heat ____________ by the surroundings ____________ the freedom of motion of the particles which ____________ the entropy of the surroundings. therefore qsys ____________ 0, qsurr ____________ 0, and δssurr ____________ 0.

Answers

Let us fill in the blanks: Exothermic changes: the system HEATS the surroundings. the heat IS ABSORBED by the surroundings AND INCREASES the freedom of motion of the particles which INCREASES the entropy of the surroundings. therefore qsys IS LESS THAN 0 (<0), qsurr > 0, and δssurr >0.

The answers are:

Exothermic changes: the system heats the surrounding. the heat absorbed by

the surroundings increase the freedom of motion of the particles which

increases the entropy of the surrounding. therefore qsys < 0 , qsurr > 0

and delt S > 0 .

the explanation:

the exothermic reaction is a chemical reaction which releases heat, and the

heat is one of its products in the reaction. So the system here released heat

and the surroundings will absorb it.

-in the exothermic reaction, the enthalpy in the surroundings will increase,

as ΔSsurr = -ΔH/T and when ΔH in the exothermic reaction has a negative

sign( - ) so, ΔSsurr has to be +Ve ( positive sign) ∴ ΔSsurr > 0 .

-and when the system released the heat and the surroundings absorbed it this affects the freedom of motion of the particles and make it increase and this will affect the entropy and make it increase.

- in exothermic reaction when the system released heat and the surroundings absorbed it will increase the thermal disorder in the surrounding which makes

ΔSsurr >0 and qsys <0 & qsurr >0 as qsurr = - qsys

when ΔSsurr is proportional to the amount of heat transferred

∴ΔSsurr α qsurr and ΔSurr α - q sys

so when ΔSsurr has a positive sign in the exothermic reaction so qsurr >0

and qsys<0.

Which expression could represent theconcentration of a solution?
(1) 3.5 g
(2) 3.5 M
(3) 3.5 mL
(4) 3.5 mol

Answers

There are a couple of ways in which you can express the concentration of a solution, and here they are: gram per liter (g/L), molarity (M), parts per million (ppm.), and percents (%).
As you can see, only M appears in your answers, which means that the correct option should be (2) 3.5 M.

The expression for representation of concentration of a solution has been 3.5 M. Thus, option 2 is correct.

Concentration has been defined as the amount of substance present in a volume of solution. The concentration has been given by varying units. The concentration has been given by mass per unit volume.

It can be represented by moles/L or g/L. The expression that has been similar to moles/L has been molarity.

Thus, the expression for representation of concentration of a solution has been 3.5 M. Thus, option 2 is correct.

For more information about concentration, refer to the link:

brainly.com/question/3045247

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