Explain why ocean temperatures vary by location on Earth’s surface.

Answers

Answer 1
Answer: The sun, mostly. Remember that on one half of Earth, it is day and on the other, it is night. The sun is heating up a portion of the ocean while other parts of it are cooling down because they're not receiving heat from it. As the Earth rotates, sun exposure in the ocean varies and so does its temperature.

Related Questions

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Which statement correctly describes a scientific theory?
Elements abundant in the body are not abundant on Earth. a. Trueb. False
Jose times how long sugar takes to dissolve in warm water. He conducts four trials of his experiment. What should he conclude from his data?Trial Time1 30 seconds2 32 seconds3 10 seconds4 29 secondsSugar does not dissolve in water.The time recorded for Trial 3 may be inaccurate.His experiment has very low precision.

Calculate the pOH of a 0.410 M Ba(OH)2 solution.

Answers

The dissociation of this basic compound is: Ba(OH)_2\ \to\ Ba^(2+) + 2OH^-

There will be the double of OH^- ions than molecules of Ba(OH)_2, therefore, the concentration of OH^- at the end will be 0.820 M.

pOH = -log\ [OH^-] = - log (0.820) = \bf 0.09

The diagram shows the electron arrangement in a molecule of ammonia, showing only outershell electrons.
I
H
(i) State the type of bonding in ammonia.
1
6​

Answers

The diagram shows 5 eletctron in the outermost shell of Nitrogen atom out of which 3 electrons are involved in the bond formation with 3Hydrogen atoms.

The type of bond in ammonia is Covalent.

What is covalent bond ?

Covalent bond is the bond formed by mutual Sharing of electrons by both the atoms taking part in the bond formation.

Nitrogen has 5valence electrons of which only 3 are shares with the 3 atoms of hydrogen (one electron shares with one atom of hydrogen)

Hence, type of  bond in ammonia is covalent.

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Final answer:

Ammonia (NH3) has a covalent bonding type resulting in a tetrahedral electron-pair geometry, but because of the lone pair, the molecular structure is trigonal pyramidal. The bond angle is slightly less than 109.5⁰ due to the lone pair occupying more space.

Explanation:

The type of bonding in ammonia, which has a molecule structure as shown in the question, is covalent bonding. The ammonia molecule, NH3, has one lone pair and three single bonds which gives it a tetrahedral electron-pair geometry, as shown in Figure 7.18. However, because one of these regions is a lone pair that is not counted in the molecular structure, the molecule assumes a trigonal pyramidal shape.

The lone pair occupies more space than the single bonds, which leads to a slight deviation in the actual bond angles from the idealised angles. The angle in the ammonia molecule is slightly less than 109.5⁰ due to this additional electron pair's space occupancy.

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A potassium atom (atomic number 19) and a bromine atom (atomic number 35) can form a chemical bond through a transfer of one electron. The potassium ion that forms has 18 electrons. What best describes the bromide ion that forms?

Answers

Answer:

C. It is a negative ion that has one more valence electron than a neutral bromine atom.

Explanation:

took test

It may have twice as much electrons a the potassium ion.

The chemical equation below shows the photosynthesis reaction. 6CO2 + 6H2O mc010-1.jpg C6H12O6 + 6O2 The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?

Answers

Answer:

12 mol of water

Explanation:

6CO_2 + 6H_2O \longrightarrow C_6H_(12)O_6 + 6O_2

First we must find the moles of CO2.

We know that 1 mole of co2 has a mass of 4.01 g so how many moles will there be in 528 g.

We apply a simple rule of three

44.01 g CO_2\longrightarrow 1 mol CO_2\n 528 g CO_2\longrightarrow x\nx= 528/44.01\nx=12 molCO_2

By stoichiometry we know that for every 6 moles of carbon dioxide 6 moles of water are needed, now if we have 12 moles of carbon dioxide how many moles of water will be needed  

We apply a simple rule of three

6 molCO_2 \longrightarrow 6 mol H_2O\n 12 mol CO_2 \longrightarrow x\nx= ((12).(6))/(6)\n x= 12 mol H_2O

Given:
6CO2 + 6H2O -> C6H12O6 + 6O2
molar mass of carbon dioxide (CO2) is 44.01 g/mol
molar mass of water (H2O) is 18.01 g/mol
528 g of CO2

Required:
moles of water

Solution:

528 g of CO2/ (44.01 g/mol CO2) = 12 moles CO2

12 moles CO2 (6 moles H2O/ 6 moles CO2) = 12 moles H2O

12 moles H2O (18.01 g/mol H2O) = 216.12 grams H2O

If a runner completes a 10 kilometer race in 32.50 minutes, what is the 10.0 km pace in miles per hour? (1.609 km = 1 mile approximately)

Answers

If a runner completes a 10 km race in 32.5 minutes, his pace or speed can be calculated by the equation:

velocity = distance/time = 10km/32.5 mins = 0.3125 km/min

Convert this value to miles per hour using the conversion factors for minutes to hours and kilometers to miles as requested by the problem. This gives an answer of 11.47 miles per hour.

0.3125 km/min x 60 mins./ 1 hour x 1 mile / 1.609 km = 11.47 miles/hour

How many orbitals are in the second shell?
a. 1
b. 2
c. 4
d. 8

Answers

The correct answer is C. 4

There are 4 orbitals in the second shell, and the number increases in further shells.

Answer:

4

Explanation: