Assume f(x) = ax^2+ bx + c Which one is true? f is a parabola that opens sideways to the right. f is a parabola that opens sideways to the left. f is a parabola that opens downward. f is a parabola that opens upward.

Answers

Answer 1

Answer:

Step-by-step explanation:

f is a parabola that opens upward.

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According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest. A random sample of 154 executive officers from these companies was selected. What is the probability that more than 20% of this sample is comprised of female employees?

Answers

Using the normal probability distribution and the central limit theorem, it is found that there is a 0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

Normal Probability Distribution

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{(p(1 - p))/(n)}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

In this problem:

16% of executive officers were women with companies that have company headquarters in the Midwest, hence p = 0.16.

A random sample of 154 executive officers from these companies was selected, hence n = 154.

The mean and the standard error are given by:

$\mu = p = 0.16$

$s = \sqrt{(p(1 - p))/(n)} = \sqrt{(0.16(0.84))/(154)} = 0.0295$

The probability that more than 20% of this sample is comprised of female employees is 1 subtracted by the p-value of Z when X = 0.2, hence:

$Z = (X - \mu)/(\sigma)$

By the Central Limit Theorem

$Z = (X - \mu)/(s)$

$Z = (0.2 - 0.16)/(0.0295)$

$Z = 1.36$

$Z = 1.36$ has a p-value of 0.9131.

1 - 0.9131 = 0.0869.

0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

To learn more about the normal probability distribution and the central limit theorem, you can take a look at brainly.com/question/24663213

Answer: 0.0885

Step-by-step explanation:

Given : According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest.

i.e. p= 0.16

Sample size : n= 154

Now, the probability that more than 20% of this sample is comprised of female employees is given by :-

$P(p>0.20)=P(z>\frac{0.20-0.16}{\sqrt{(0.16(1-0.16))/(154)}})$

[∵ $z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}$ ]

$=P(z>1.35)\approx1-P(z\leq1.35)=1-0.9115=0.0885$ [Using the standard z-value table]

Hence, the required probability = 0.0885

Help me, please lololol

Answers

9/7 > 1

> is more than
7/7 would be 1

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 5 years of the actual mean with a confidence level of 94%, how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 22 years.

Answers

Answer:

The sample size is $n = 68$

Step-by-step explanation:

From the question we are told that

The margin of error is $E = 5 \ years$

The standard deviation is $\sigma = 22$

From the question we are told the confidence level is 94% , hence the level of significance is

$\alpha = (100 - 94 ) \%$

=> $\alpha = 0.06$

Generally from the normal distribution table the critical value of $(\alpha )/(2)$ is

$Z_{(\alpha )/(2) } = 1.881$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{(\alpha )/(2) } * \sigma }{E} ] ^2$

=> $n = [\frac{1.881 } * 22 }{5} ] ^2$

=> $n = 68$

If sally has 90000000 apples and gives her freind sophie 1900 of them , and keeps 900 apples for her self hown many apples did she give to charity?1

Answers

Answer: 89,998,910

Step-by-step explanation: if she gives 1900 away and keeps 900 then I’m assuming she gives the rest away to charity and that would be 89,998,910 apples

Answer:

She gave 89997200 apples to charity

Step-by-step explanation:

90000000 - 1900 - 900 = 89997200

90000000 - (1900 + 900) = 89997200

A bookstore owner wants to collect data to find out customers' opinions of the variety of book genres available at the store. Which group should she survey to get the best random sample?A.
twenty customers who asked to share their opinions of the books available at the bookstore
B.
thirty-five randomly selected customers who purchased books at the bookstore
C.
forty-five randomly selected people at the supermarket next door
D.
fifty randomly selected customers who visited the bookstore

Answers

Answer:

the answer would be D.

Step-by-step explanation:

I am not sure how to explain this but I hope this helped you

True or False: The height is always twice the length of tue base edge of any triangular pyramid.

Answers

Answer:

true

Step-by-step explanation:

3n3n3p0mdo98rueu33

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Assume f(x) = ax^2+ bx + c Which one is true? f is a parabola that opens sideways to the right. f is a parabola that opens sideways to the left. f is a parabola that opens downward. f is a parabola that opens upward.​

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Assume f(x) = ax^2+ bx + c Which one is true? f is a parabola that opens sideways to the right. f is a parabola that opens sideways to the left. f is a parabola that opens downward. f is a parabola that opens upward.