CHEMISTRY COLLEGE

If the amount of dissolved solute in a solution at a given temperature is greater than the amount that can permanently remain in the solution at that temperature, the solution is said to bea.diluted.
b.unsaturated.
c.saturated.
d.supersaturated.

Answers

Answer 1
Answer:

Answer:

d. supersaturated.

Explanation:

A solution naturally contains a solute and a solvent. The solute is the solid substance that dissolves in the solvent, which is usually a liquid substance. A solution has a maximum amount of solute that can dissolve in its constituent solvent.

However, when the amount of dissolved solute in a solution at a given temperature is greater than the amount that can permanently remain in the solution at that temperature, the solution is said to be SUPERSATURATED. This means that the solution contains more than the maximum amount of solute.

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When 2.25 g of sodium hydroxide (NaOH) was dissolved in 150.00 g of water a value of 11.00oC was obtained for ΔT.1. Calculate the molarity of the sodium hydroxide solution.2. Calculate the value (calories) for the heat of solution of 2.25 g of NaOH.3. Calculate the number of calories that would be produced if one mole of sodium hydroxide was dissolved. (ΔHsolnNaOH)
A student adds solid KCl to water in a flask. The flask is sealed with a stopper and thoroughly shaken until no more solid KCl dissolves. Some solid KCl is still visible in the flask. The solution in the flask is A) saturated and is at equilibrium with the solid KCl B) saturated and is not at equilibrium with the solid KCl C) unsaturated and is at equilibrium with the solid KCl D) unsaturated and is not at equilibrium with the solid KCl
Please ignore my answers because they are wrong.
As we drive an automobile, we dont't think about the chemical consumed and produced. Prepare a list of the principal chemicals consumed and produced during the operation of an automobile.

Choose all the answers that apply.Ionic compounds _____.
-do not dissolve in water
-have high melting points
-have low melting points
-dissolve easily in water
-conduct electricity when melted

Answers

Answer:

high melting points, dissolve easily in water, conduct electricity when melted.

Explanation:

I'm pretty sure

For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen, what would be true?

Answers

Final answer:

In a reaction where two moles of C3H8 react with an excess of oxygen, the ∆H would be -4400 kJ, double the ∆H value when only one mole is reacted.

Explanation:

The given reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, has a ∆H of –2200 kJ. This represents the energy change for the reaction involving one mole of C3H8. When two moles of C3H8 react, the ∆H will be double that of the given ∆H. Therefore, when two moles of C3H8 react with excess oxygen, the ∆H would be -4400 kJ. This is because the ∆H for a reaction is directly proportional to the amount of substance reacted, hence when two moles of C3H8 are reacted, the ∆H is doubled.

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A solid that forms from a solution during a chemical reaction is called a(an)

Answers

Answer:

precipitate

Explanation:

Precipitation is the creation of a solid from a solution. When the reaction occurs in a liquid solution, the solid formed is called the 'precipitate'. The chemical that causes the solid to form is called the 'precipitant'.

hope i helped :)

Inside a calorimeter, two solutions are mixed and result in an endothermic reaction. Which of the following best illustrates how this reaction affects the water in the calorimeter? (2 points)Select one:
a. The reaction has no effect on the water. The kinetic energy of the water molecules remains the same.
b. The reaction causes the temperature of the water to increase. The kinetic energy of the water molecules increases.
c. The reaction causes the temperature of the water to decrease. The kinetic energy of the water molecules decreases.
d. The reaction causes the temperature of the water to decrease. Then, the water gains heat from the surroundings and the kinetic energy of the water molecules increases.

Answers

The correct option is C. A calorimeter is an isolated system. In isolated systems there is no exchange whatsoever with the surrounding. In an isolated system, an endothermic reaction results in a decrease in the temperature of the system. This is in contrast to the effect of an endothermic reaction in an open system. The heat of reaction remains a positive quantity.

A student is heating a chemical in a beaker with a Bunsen burner.In a paragraph of at least 150 words, identify the safety equipment that should be used and the purpose of it for the given scenario.

Answers

When a student is warming a chemical in a container using a special burner, it is very important to focus on safety by using the right safety tools.

What is the safety equipment

First, the student needs to wear the right safety clothes like a lab coat, gloves, and goggles to protect themselves from getting splashed or hurt by chemicals. A lab coat stops chemicals from touching the skin, gloves keep the hands safe, and safety goggles protect the eyes from chemicals

and hot things.

Furthermore, using a fume hood is necessary to make sure there is enough fresh air circulating and to remove any dangerous fumes or gases that might be released while heating things up.

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Answer:The student should be wearing a lab coat or maybe an apron to prevent chemicals from spilling or exploding onto their clothes, I do recommend a lab coat better though because it can protect your skin better. Next, make sure while messing with chemicals you are always wearing goggles, if you are not wearing them there is a chance that after touching chemicals you could touch your eyes. And that brings me to washing your hands straight away after messing with chemicals. You could also wear gloves and just take them off when you're done but if you don't have clean hands afterward you could always put the chemicals all over your skin. But in case you do touch your eyes there is always an emergency eyewash station somewhere in the lab room. And if you are to get Chemicals on your skin, in your hair, on your clothes, or to be on fire, there shall be a shower somewhere to get rid of that. But if you read the instructions or listen closely to the teacher you shall have no problem.

Explanation:

I kinda got off topic

Measurements show that unknown compound has the following composition: element mass 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. Write the empirical chemical formula of this compound?(A) Ca2PO4
(B) Ca3PO6
(C) Ca4P2O4
(D) Ca3P2O8 (or Ca3(PO4)2)
(E) CaPO4

Answers

Answer:

D) empirical formula is: C₃P₂O₈

Explanation:

Given:

Mass % Calcium (Ca) = 38.7%

Mass % Phosphorus (P) = 19.9%

Mass % oxygen (O) = 41.2 %

This implies that for a 100 g sample of the unknown compound:

Mass Ca = 38.7 g

Mass P = 19.9 g

Mass O = 41.2 g

Step 1: Calculate the moles of Ca, P, O

Atomic mass Ca = 40.08 g/mol

Atomic mass P = 30.97 g/mol

Atomic mass O = 16.00 g/mol

Moles\ Ca = (38.7g)/(40.08g/mol) =0.966\ mol\n\nMoles\ P = (19.9g)/(30.97g/mol) =0.643\ mol\n\nMoles\ O = (41.2g)/(16.00g/mol) =2.58\ mol

Step 2: Calculate the molar ratio

C = (0.966)/(0.643) =1.50\n\nP = (0.643)/(0.643) = 1.00\n\nO = (2.58)/(0.643) =4.00

Step 3: Calculate the closest whole number ratio

C: P: O = 1.50 : 1.00 : 4.00

C : P : O = 3:2:8

Therefore, the empirical formula is: C₃P₂O₈

Final answer:

The mass percentage composition of a compound can be used to determine its empirical formula. For a compound with 38.7% calcium (Ca), 19.9% phosphorus (P), and 41.2% oxygen (O), the empirical formula is Ca3(PO4)2.

Explanation:

To solve this problem, we're going to use the atomic mass percentages to determine the empirical formula of the compound.

We do this by assuming we have a 100g sample of the compound. Therefore:

The mass of calcium (Ca) is 38.7g.

The mass of phosphorus (P) is 19.9g.

The mass of oxygen (O) is 41.2g.

Next, we calculate how many moles we have of each element:

  • Ca: 38.7g / 40.08g/mol (the atomic mass of calcium) = 0.965 moles
  • P: 19.9g / 30.97g/mol (the atomic mass of phosphorous) = 0.643 moles
  • O: 41.2g / 16.00g/mol (the atomic mass of oxygen) = 2.575 moles

Then, we divide each of these numbers by the smallest number of moles, which is 0.643 (P):

  • Ca: 0.965/0.643 = 1.5 (~1)
  • P: 0.643/0.643 = 1
  • O: 2.575/0.643 = 4

Learn more about Empirical Formula here:

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