Which of the following can be caused by geologic plate movements?

Answers

Answer 1

Answer: Earthquakes can be an effect of thy movements.

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HELP PLEASE I need help with these 2 chem questions asap i would gladly appreciate it :)

Answers

10) You need to find the atomic mass of every element, which you can get from any periodic table.

a) 6.02x10^23 atoms of Mg

Atomic mass of Mg = 24.3 g/mol

# of mols = 6.02 x 10^23 atoms / 6.02 x 10^23 atoms/mol = 1 mol

mass = 1 mol x 24.3 g/mol = 24.3 g

b) 3.01x10^23 formula units of Ca Cl2

Atomic masses

Ca: 40 g/mol
Cl: 35.5 g/mol

Formula mass: 40g/mol + 2x 35.5g/mol = 111 g/mol

# of mols = 3.01 x 10^23 / 6.02 x 10^23 = 0.5 mol

mass = 0.5 mol x 111 g/mol = 55.5 g

c) 12.4 x 10^15 molecules of CH2O

formula mass = 12 g/ mol + 2 g/mol + 16 g/mol = 30 g/mol
# of mols

mass = [12.4 x 10^15 / 6.02 x 10^23]mol x 30 g/mol = 2.1 x 10 ^(-8) g

3)

a) The polar solute is dissolved in water which is a polar solvent, while the non polar solute is not dissolved in water. This is a rule in chemistry: polar solvents dissovle polar soultes and non polar solvents dissolve non polar soluted.

The extremes of the polar molecules are easily solvated by the water molecules.

b) KI is an ionic compound, which implies that it will ioinize (separare in iones) in water, being in this way be dissolved, while the CO2, which is no polar, will not be easily dissolved in water under normal conditions

Sodium(na) is a highly reactive metal and chlorine is a poisonous gas. Which compound do they form when they chemically combine?

Answers

Sodium lose one electron and convert into sodium ion Na+

Chlorine lose one electron and form Cl- ion

When these ions come together they from an ionic compound NaCl,

table salt

The ionic compound which consist ionic bond. The ionic bond is a type of bond which formed between positive and negative ions or metal, sodium and non-metal , chlorine

It would form into NaCl because Na has a +1 charge while Cl has a -1 charge.

What is the density of a block of marble that occupies 287cm3 and has a mass of 869g?

Answers

a REALLY helpful thing when doing physics is something called the DMV triangle. So how it works is you look at what you are trying to find, which in this case is density. So you cover the D and look at the remaining M and V. Everything below the M has to be divided, and if you are just left with the D and V then you x them. It’s really simple and easy to use. So you cover up the D, and are left with M and V. So now you have to do Mass divided by Volume. 869g divided by 287cm3 would be 3.02g/cm3

HClO4+P4O10=H3PO4+Cl2O7 how do you balance this?

Answers

12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇

Explanation

Balance by the conservation of atoms.

Assign coefficient 1 to the species with the largest number of elements and atoms. H₃PO₄ contains three elements. Each of its molecule contains eight atoms, that's two more than the six atoms in a HClO₄ molecule. Start by assigning H₃PO₄ a coefficient of 1.

? HClO₄ + ? P₄O₁₀ → 1 H₃PO₄ + ? Cl₂O₇

There are now three H atoms, one P atom on the product side. H₃PO₄ is the only product that contains H and P atoms. As a result, there should be the same number of H and P atoms on the reactant side.

Among all reactants, only HClO₄ contains H atoms. Each HClO₄ molecule contains one H atom. Three H atoms correspond to three HClO₄ molecule.
Among all reactants, only P₄O₁₀ contains P atoms. Each P₄O₁₀ molecule contains four P atoms. One P atom corresponds to 1/4 of a P₄O₁₀ molecule.

Thus

3 HClO₄ + 1/4 P₄O₁₀ → 1 H₃PO₄ + ? Cl₂O₇

There are three Cl atoms in three HClO₄ molecules. HClO₄ is the only species that contains Cl among all reactants. There are three Cl atoms on the reactant side and shall be the same number of Cl atoms on the product side.

Cl₂O₇ is the only molecule that contains Cl among the products. Each Cl₂O₇ molecule contains two Cl atoms. Three Cl atoms will correspond to 3/2 Cl₂O₇ molecules.

3 HClO₄ + 1/4 P₄O₁₀ → 1 H₃PO₄ + 3/2 Cl₂O₇

Multiply both sides by the least common multiple of the denominators to eliminate the fraction. Theleast common multiple in this case is four.

12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇

3. For the following reaction, calculate how many grams of each product are formed when 4.05 gof water is used.
2 H2O → 2 H2 + O2

Answers

Answer:

$\large \boxed{\text{0.453 g of H$_(2)$; 3.60 g of O$_(2)$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

MM: 2.016 32.00

2H₂O ⟶ 2H₂ + O₂

m/g: 4.05

1. Mass of hydrogen

(a) Moles of H₂O

$\text{Moles of H$_(2)$O} = \text{4.05 g H$_(2)$O}* \frac{\text{1 mol H$_(2)$O}}{\text{18.02 g H$_(2)$O }}= \text{0.2248 mol H$_(2)$O}$

(b) Moles of H₂

$\text{Moles of H$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{2 mol H$_(2)$}}{\text{2 mol H$_(2)$O }} = \text{0.2248 mol H$_(2)$}$

(c) Mass of H₂

$\text{Mass of H$_(2)$} =\text{0.2248 mol H$_(2)$} * \frac{\text{2.016 g H$_(2)$}}{\text{1 mol H$_(2)$}} = \textbf{0.453 g H$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g}}$ of H$_(2)$}$

2. Mass of oxygen

(a) Moles of O₂

$\text{Moles of O$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{1 mol O$_(2)$}}{\text{2 mol H$_(2)$O}} = \text{0.1124 mol O$_(2)$}$

(b) Mass of O₂

$\text{Mass of O$_(2)$} =\text{0.1124 mol O$_(2)$} * \frac{\text{32.00 g O$_(2)$}}{\text{1 mol O$_(2)$}} = \textbf{3.60 g O$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g of H$_(2)$ and 3.60 g of O$_(2)$}}$}$

Mercury is an element. Which of the following would be the same for all atoms of mercury? A. the number of protons

B. the number of neutrons

C. the number of electrons

D. the total number of protons and neutrons

Answers

The number of protons

for all atoms of mercury will remain the same while different isotopes may have different number of neutrons.

Explanation:

Atoms should have equal numbers of protons and electrons. In our example, an atom of thirty six|chemical element, it should contain thirty six electrons since it contains 36 protons. Electrons are organized around atoms in a very special method.

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