Which of the following conversion factors would you use to change 18 kilometers to meters? A.) 1,000 m/1 km
B.) 1 km/1,000 m
C.) 100 m/1 km
D.) 1 km/100 m

Answers

Answer 1
Answer:

Answer:

The answer is A) 1,000 meters = 1 Kilometer.                                                        

Explanation:

To convert 18 Kilometers into meters, one would have to  multiply the figure given in Kilometer by 1000.

Therefore we have 18 x 1000

= 18,000.

So 18 Kilometers is also 18,000 meters when converted.

Cheers!

Answer 2
Answer: use choice B. 1 km / 1000 m 

from what result that 18 km = 18 000 m 

hope helped 

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Which theory states that if you are forced to smile at an event, you will enjoy it? A. The Schachter-Singer theory B. The Lazarus theory C. The facial feedback theory D. The opponent-process theory

Answers

Answer:

C. The facial feedback theory

Explanation:

The facial feedback theory as postulated by William James and connects back to the famous Charles Darwin talks about how facial expressions stimulate our emotional state of being. Based on this theory, the emotional experiences we have are determined by the looks on our faces.

According to the question, smiling at an event makes you enjoy it is an example of what the The facial feedback theory is explaining. Furthermore, smiling, which is a facial expression causes or stimulates an emotional state of enjoyment in that event.

How do summer conditions affect weathering

Answers

weathering is a chemical and a physical  process in the summer it is ussually hot and in the winter it is usually cold  in the spring is a mild temperature during the day warm+cold=mild and at night time during the spring its a little chilli but for some reason in the desert during the day it is really hot and at night in the desert it is really cold.

I hope I helped you

A solid geometric shape formed by a mineral is called

Answers

When a mineral is formed into a geomoetric shaped it is called a crystal

Answer:

Crystal.

Explanation:

Every 4 years we have a leap year on our calander to make up the extra.......

Answers


The Earth takes very nearly (365 and 1/4) days to go around the sun.

If our calendar always had 365 days, then the year would end and re-start
too soon, and the beginning of Spring (and every other season) would
eventually drift into the months after March.

If our calendar always had 366 days, then the year would end and re-start
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We can't make calendars with an extra quarter-day in each year.  But we
keep them lined up with the real year by saving up the quarters, and adding
one full day to the calendar every 4 years.

Recall that the height of an object t seconds after it begins moving when gravity is the only force acting on the object is given. h(t)=-16x^2 + v0t + h0. h(t) is given in feet. v0 = initial velocity of object in ft/sec. ho= initial height of object in feet. If the feather is dropped from the top of the bridge 90 feet above a river, how long does it take the feather to reach the water?

Answers

That's pretty easy, have a look :

h(t)=−16x2=v0t+h0
v0=0 ft/sec
h0=90 ft

The only thing you need to do is to find t and the problem is solved.

Answer:

Time taken, t = 2.37 seconds

Explanation:

It is given that,

Height of an object at time t is given by :

h(t)=-16t^2+v_0t+h_0

Where

v₀ is initial velocity of object

h₀ is initial height of the object

The feather is dropped from the top of the bridge 90 feet above a river. we have to find the time taken by the feather to reach the water.

At the surface of water, h(t) = 0 and v₀t = 0

So, 0=-16t^2+0+90

t = 2.37 seconds

The feather will take 2.37 seconds to reach the water surface.

A thin conducting plate 50.0 cm on a side lies in the xy plane. If a total charge of 4.00 ? 10 ?8 C is placed on the plate, find (a) the charge density on the plate, (b) the electric field just above the plate, and (c) the electric field just below the plate.

Answers

Answer:

a) 8*10^-8C/m²

b) +9.04*10^3N/C

c) = -9.04*10^3N/C

Explanation:

Given

Side length, L = 50cm = 0.5m

Charge on the plate, Q = 4*10^-8C

Surface charge density, σ = Q/A

The surface charge density of each part is then half of the total charge density of the plate. Thus,

σ(face) = 1/2σ

σ(face) = Q/2A

σ(face) = Q/2L²

Now we plug in, since we have Q and L

σ(face) = 4*10^-8 / 2*0.5²

σ(face) = 4*10^-8 / 0.5

σ(face) = 8*10^-8C/m²

Magnitude of electric field above the plate is,

E = σ(face) / E•

E = 8*10^-8 / 8.85*10^-12

E = 9.04*10^3 N/C

If we assume this plate lies on the side of the "xy" plane, the electric field is directed in the positive "z" direction. As such,

E = +9.04*10^3N/C

Electric field below the plate has the same magnitude, but different direction. So, E = -9.04*10^3N/C