And i need help with these problem.An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture.

______ pounds

Answers

Answer 1

Answer: Let the required amount of the second alloy be x, then
0.15 x 20 + 0.1x = 0.12(20 + x)
3 + 0.1x = 2.4 + 0.12x
0.12x - 0.1x = 3 - 2.4
0.02x = 0.6
x = 0.6/0.02 = 30

Therefore, to make a 12% mixture, 30 pounds of the secon mixture should be added.

Answer 2

Answer: Tin from the first alloy: 20*15% = 3

Tin from the second alloy: x*10% = 0.1x

Total tin: (20 + x)*12% = 2.4 + 0.12x

Total tin = tin from the first alloy + tin from the second alloy
2.4 + 0.12x = 3 + 0.1x

Solve for x:

0.12x - 0.1x = 3 - 2.4
0.02x = 0.6
x = 0.6 /0.02
x = 30

Answer: must add 30 pounds of the second alloy.

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Simplify.
A12 over a7

Answers

Answer:

a^5.

Step-by-step explanation:

a^12 / a^7 = a^(12 - 7) = a^5.

Hope this helps!

Kara graphed a system of linear equations. The two lines are parellel and they do not coincide which statement about the number of points that satisfy the system is true? A.no points satisfy both equations B. one point satisfies both equations C.two points satisfy both equations D.An infinite number of points satisfy both equations

Answers

the answer is A thanks for asking

I believe that the answer is (a) no points satisfy both equations. Hope this helped☻

Identify each expression that represents the slope of a tangent to the curve y= -x^3+17x^2-x+3 at any point (x,y).

Answers

This is seriously so long I'm not sure it will even fit on a single line. The formula for the derivative using the limiting process is $\lim_(h \to 0) (f(x+h)-f(x))/(h)$ . And of course this is a problem because if h approaches 0, we would have a 0 in the denominator of that fraction and that is definitely not allowed! Every x in the function will be replaced with (x+h) to give us this: $\lim_(h \to 0) (-(x+h)^3+17(x+h)^2-(x+h)+3)/(h)$ . When we expand that we will get this very long numerator (I'm purposely leaving out the limit as h approaches 0 part to save space): $(-(x^3+2x^2h+xh^2+x^2h+2xh^2+h^3)+17x^2+34xh+17h^2-x-h+3-(-x^3+17x^2-x+3))/(h)$ . Simplifying that leaves us with this: $(-x^3-2x^2h-xh^2-x^2h-2xh^2-h^3+17x^2+34xh+17h^2-x-h+3+x^3-17x^2+x-3)/(h)$ . We have a lot of terms that cancel each other out so when we do that we are left with $\lim_(h \to 0) (-3x^2h-3xh^2-h^3+34xh+17h^2-h)/(h)$ . That is one of your choices for answers, the third one down on the left to be specific. Now we can factor out an h: $\lim_(h \to 0) (h(-3x^2-3xh-h^2+34x+17h-1))/(h)$ . That h on the top outside the parenthesis cancels with the h on the bottom. Now, as h approaches 0 we have no problems! Yay! That means when we now replace h with 0, we have this: $-3x^2-0-0+34x+0-1$ , or simplified we have $-3x^2+34x-1$ which is also a choice for your answers, top one on the right. Those are your 2 answers for that dertivative. It's much simpler when you learn the rules!

What is the percent of increase from 3.7 to 5?Round your answer to the nearest tenth of a percent and include a percent sign (%).

Answers

Answer 35.1%

5/3.7=1.3513

What is the answer to this problem
8x-2=-9+7×

Answers

8x−2=−9+7x

Simplify:

8x−2=−9+7x

8x+−2=−9+7x

8x−2=7x−9

Subtract 7x from both sides.

8x−2−7x=7x−9−7x

x−2=−9

Add 2 to both sides.

x−2+2=−9+2

x=−7

you want like terms on the same side. so you want x on the same side
subtract 7x from 8 x = x
add 2-9 = -7
now you have x= -7

Solve the quadratic equation by completing the square.x^2+4x-6=0

First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation. Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.

Answers

1.16, - 5.16

Working
Take 6 to the other side
x^2+4x = 6
Find the 3rd for the left hand side:
x^2+4x+ (4/2)^2= 6 + (4/2)^2
Factoring the LHS gives
(x+2)^2=10
Finding square roots on both sides:
x+2=square root of 10
x+2= +3.1623 or - 3.1623
x=3.1623-2
=1.16
or
x= -3.1623 - 2
= - 5.16

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And i need help with these problem.An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds

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And i need help with these problem.An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture.

______ pounds