Reaction isCO2(g) + C(s) <=> 2CO(g)
Kp = 5.7, 1200K

Calcualte the total pressure at equilibrium when 4.45g CO2 is introduced into a 10.0L container and heated to 1200K in the presence of 2.00g of graphite

Answers

Answer 1

Answer: According to the task, you are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C
The you go :
$CO2(g) + C(s) \ \textless \ =\ \textgreater \ 2CO(g)$

n1 n2 0
-x -x +2x
$n1-x n2-x 2x Kp=P^2 (CO)/Pco2$
After that you have to use the formula $PV=nRT$
$Kp=(2x)^2/n1-x$
Then you have to solve x, and for that you have to use RT/V
And to find total values: $P(total)=n(total)*R*T/V$
I am absolutely sure that this would be helpful for you.

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Phosphoric acid is a triprotic acid with Ka1 = 6.9 x 10-3, Ka2 = 6.2 x 10-8, and Ka3 = 4.8 x 10-13. Calculate the pH of a solution created by dissolving 23.4 g of KH2PO4(s) and 38.4 g of Na2HPO4(s) in 2 L of water.

Answers

The pH of the solution created is 7.21

Explanation:

Ka1 = 6.9 X 10⁻³

Ka2 = 6.2 X 10⁻⁸

Ka3 = 4.8 X 10⁻¹³

pKa = - log( Ka)

Thus,

pKa1 = - log ( 6.9 X 10⁻³) = 2.16

pKa2 = - log ( 6.2 X 10⁻⁸ ) = 7.21

pKa3 = - log ( 4.8 X 10⁻¹³ ) = 12.3

KH₂PO₄ + Na₂HPO₄ = KH₃PO₄ + Na₂PO₄

Ka2 = [ KH₃PO₄] [Na₂PO₄] / [KH₂PO₄] [Na₂HPO₄]

log (Ka2 ) = log [[ KH₃PO₄] [Na₂PO₄] / [KH₂PO₄] [Na₂HPO₄]]

pH = pKa2 + log [KH₂PO₄] /[Na₂HPO₄] = 7.21

Therefore, the pH of the solution created is 7.21

Complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2)

Answers

the answer to this is 4 Al + 3 O2 = 2 Al2O3 i hope that this helps

2H₂O ----> 2H₂ + O₂How many moles of hydrogen are produced when 6.28 mol of oxygen form?

A.) 3.14 mol
B.) 6.28 mol
C.) 12.6 mol
D.) 25.2 mol

Answers

2 H2O ------------> 2 H2 + 1 O2

2 mol H2 ----> 1 mol O2
x mol H2 -----> 6.28 mol O2

x = 6.28 * 2

x ≈ 12.6 mol

answer C

hope this helps!.

6.28 mol O2* (2 mol H2/ 1 mol O2)= 12.6 mol H2

The correct answer is C. 12.6 mol~

What element has the electron configuration 1s2 2s2 2p6 3s2 3p2?

Answers

The sulfur (S) element of the periodic table is represented by the electron configuration $1s^2 2s^2 2p^6 3s^2 3p^2$ .

The arrangement of electrons within the energy levels or orbitals of an atom is represented by electronic configuration. Sulfur has 16 electrons in its structure. The numbers in the electronic configuration represent the principal energy levels—1, 2, and 3—as well as the orbital—s or p—that the electrons are in.

Detail analysis of electron arrangement:

The first energy level (n = 1) represents the presence of two electrons in the symbol $1s^2$ 1s orbital.
The symbol $2s^2$ indicates the presence of two electrons in the second energy level (n = 2) and the 2s orbital.
The $2p^6$ symbol indicates the presence of 6 electrons in the second energy level (n = 2) and 2p orbitals.
The third energy level, or $3s^2$ , refers to the presence of two electrons in the 3s orbital (n = 3).
$3p^2$ stands for the third energy level (n = 3), and indicates that two of the three p orbitals hold two electrons.

When these electronic configurations are combined, the electron configuration of sulfur (S) is represented by $1s^2 2s^2 2p^6 3s^2 3p^2$ .

Learn more about Electronic configuration, here:

brainly.com/question/29184975

#SPJ6

Count the number of electrons = 2+2+6+2+2= 14

So, it must be SILICON.

What is the mole ratio of NaOH To Al(OH)3

Answers

The Molar ratio identify how many moles of product and reactant. are formed during a reaction.
Here, we have 1 NaOH and 3 Al(OH), which mean that the molar ratio of NaOH to Al(OH)3 is 1:3 (or 1/3)

Therefore, 1.2 moles of NaOH will produce (1/3) * (1.2) = 0.4 Moles of Al(OH)3

Hope this Helps :D

Write balanced complete ionic equation for AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)