CHEMISTRY HIGH SCHOOL

What is the chemical reaction for respiration ​

Answers

Answer 1
Answer:

Respiration is the chemical process by which organic compounds release energy. The compounds change into different ones by exergonic reactions. The hydrolysis of adenosine triphosphate (ATP) to adenosine diphosphate (ADP) and phosphoric acid (Pi) releases energy (it is an exergonic reaction).

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How do the products and reactants of a chemical change compare? The mass of the products is greater than the mass of the reactants because energy is absorbed by the reaction. The mass of the products equals the mass of the reactants because energy is not absorbed or given off by the reaction. The mass of the products is less than the mass of the reactants because energy is given off by the reaction. The mass of the products equals the mass of the reactants because the same atoms are present throughout the reaction

What is the half-life of sodium-24? EXPLAIN how you determined your answer.

Answers

The half life of sodium -24 is 15 hour.

What is half life?

The duration needed for an amount to decrease to half its original is known as the half-life.

What is sodium-24?

Sodium is a kind of element which has atomic number 11. It has three isotopes.

The radioactive isotope sodium-24, which is employed in blood tests in medicine, degrades through beta decay as well as seems to have an of 15.0 hours.

Therefore, the half life of sodium -24 is 15 hour.

To know more about half life.

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half-life is basically how long it takes for a radioactive molecule to get to 1/2 of its original mass.

so if sodium 24 mass was 5g and it's half life was 24years then:

after every 24years 1/2 of 5g would have decayed. so in 48years there will only be 2.5g left.

Given the balanced ionic equation:Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)
Which equation represents the oxidation half reaction?
(1) Zn(s) + 2e– → Zn2+(aq)
(2) Zn(s) → Zn2+(aq) + 2e–
(3) Cu2+(aq) → Cu(s) + 2e–
(4) Cu2+(aq) + 2e– → Cu(s)

Answers

Answer: Option (2) is the correct answer.

Explanation:

Oxidation is the process in which there is loss of electrons or increase in oxidation number of the element.

Whereas reduction is the process in which there is gain of electrons or decrease in oxidation number of the element.

For example, Zn(s) + Cu^(2+) \rightarrow Zn^(2+) + Cu(s)

Oxidation-half reaction: Zn(s) \rightarrow Zn^(2+) + 2e^(-)

Reduction-half reaction: Cu^(2+) + 2e^(-) \rightarrow Cu(s)

Thus, we can conclude that the given equation Zn(s) → Zn2+(aq) + 2e– represents the oxidation half reaction.

The equation that represents the oxidation half reaction is Zn(s) → Zn2+(aq) + 2e–

What is oxidation reaction?

Oxidation reaction is the process in which there is loss of electrons or increase in oxidation number of the element.

From all the given half reaction, there is only one reaction with increase in oxidation number;

Zn(s) → Zn2+(aq) + 2e–

  • Zn(s) - oxidation = 0
  • Zn2+ - oxidation number = +2

Thus, there is increase in oxidation number of 0 to + 2.

Learn more about oxidation number here: brainly.com/question/27239694

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Each molecule of table sugar, C12H22O11, containsa.
0 atoms of carbon.
c.
6 atoms of carbon.
b.
1 atom of carbon.
d.
12 atoms of carbon.

Answers

Answer : The correct option is, (d) 12 atoms of carbon.

Explanation:

The formula of given molecule of table sugar is, C_(12)H_(22)O_(11)

The given molecule is made up of three elements which are, carbon, hydrogen and oxygen.

In the given molecule of table sugar C_(12)H_(22)O_(11), there are 12 number of carbon atoms, 22 number of hydrogen atoms and 11 number of oxygen atoms.

From the given options we conclude that, the option (d) is the correct option. While the other options are incorrect.

Hence, the correct option is, (d) 12 atoms of carbon.
d, because C12 means there's 12 atoms of carbon. 

What name should be used for the ionic compound LiI?

Answers

What name should be used for the ionic compound LiI?

The name that should be used for the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have to take into consideration pairing of two components. 

Answer: The given compound is named as lithium iodide.

Explanation:

LiI is an ionic compound because lithium is a metal and Iodine element is a non-metal.

We know that, a bond which is formed between a metal and a non-metal is always ionic in nature.

Ionic bond is formed when there is a complete transfer of electron from an electropositive element (a metal) to an electronegative element (non-metal).

The nomenclature of ionic compounds is given by:

  1. Positive ion is always written first.
  2. The negative ion is written next with a suffix added at the end of the negative ion. The suffix used is '-ide'.

Hence, the name given to LiI will be lithium iodide.

If the formic acid were replaced with a strong acid such as HCI at the same concentration (2.0 M). how would that change the volume needed to reach the equivalence point? (A) The change would reduce the amount, as the acid now fully dissociates. (B) The change would reduce the amount, because the base will be more strongly attracted to the acid. (C) The change would increase the amount, because the reaction will now go to completion instead of equilibrium. (D) Changing the strength of the acid will not change the volume needed to reach equivalence.

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answer for my di0ck s!ut

What type of bond is this combination most likely to form?

Answers

Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.

Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.

When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.

One sodium and fluorine each totaling 2 atoms are enough to make the bond.

As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.

The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.

The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.

The name of the compound is sodium fluoride with formula NaF.

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