MATHEMATICS HIGH SCHOOL

Find the length of BC.

Answers

Answer 1

Answer:

Answer:

BC = 10 units

Step-by-step explanation:

From the picture attached,

It's given that AD and BE are the parallel sides.

AC and DC are the transversal lines intersecting the parallel lines.

In ΔADC and ΔBEC,

∠DAC ≅ ∠EBC [Corresponding angles]

∠ADC ≅ ∠BEC [Corresponding angles]

ΔADC ~ ΔBEC [By AA property of similar triangles]

By the property of similar triangles,

Corresponding sides of the similar triangles are proportional.

$(AC)/(BC)=(DC)/(EC)$

$(AB+BC)/(BC)=(DE+EC)/(EC)$

$(2.5+BC)/(BC)=(2+8)/(8)$

$(2.5)/(BC)+1=(10)/(8)$

$(2.5)/(BC)=(5)/(4)-1$

$(2.5)/(BC)=(1)/(4)$

BC = 10

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PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

Answers

factor by grouping

x^2(x-7) + 6(x-7) = 0 [took x^2 out of the first two and a 6 out of the last two]
(x-7)(x^2+6) = 0 [moved (x-7) out to the front]
x = -i sqrt(6) , i sqrt(6) , 7

only one real solution of x = 7

$x^(3) -7 x^(2) +6x-42=0$

$(x-7)$ is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.

$(x-7)(a x^(2) +bx+c)=0$

$(x-7)( x^(2) +bx+6)=0$

$-7 x^(2) +b x^(2) =-7 x^(2)$

$-7+b=-7$

$b=0$

$(x-7)( x^(2) +6)=0$

$x-7=0$

$x^(2) +6=0$

$x=7$ (only solution because you can't square root (-6))

Which expression is not equivalent to 6^3/6^6

Answers

The expression that is not equivalent to $6^3/(6^6)$ is $1/6^2$ (option A)

How to find the inequivalent expression?

The expression given is $6^3/(6^6)$

Using the law of exponent:

$(x^4)/(x^2) =x^(^4 ^- ^2^)$

$= x^2$

we can simplify the expression:

$(6^3)/(6^6) = 6^3^-^6$

Simplifying the exponent gives

$6^-^3$

This can also be expressed as a fraction:

$(1)/(6^3)$ or $(1)/(216)$

Comparing the options, we can see that the inequivalent expression is $1/6^2$ (option A)

Learn about equivalent expressions here brainly.com/question/2972832

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Answer:

Step-by-step explanation:

The answer is C

The two box-and-whisker plots below show the scores on a math exam for two classes. What do the interquartile ranges tell you about the two classes?

Answers

Answer:

A box-and-whisker plot shows the scores on a math exam for two classes.

Class A Class B

1) Minimum value 65 56

2) Lower quartile 66 79

3) Median 81 91

4) Upper quartile 89 94

5) Maximum value 95 100

First quartile also known as Lower quartile is the number below which lies the 25 percent of the bottom data.

Second quartile or Median divides the range in the middle and has 50 percent of the data below it.

Third quartile also known as upper quartile has 75 percent of the data below it and the top 25 percent of the data above it.

Interquartile Range = Upper quartile - Lower quartile,

For class A

Interquartile range = 89 -66 = 23

For class B

Interquartile range = 94 -79 = 15

The interquartile ranges tell you about the two classes that Class B has more consistent scores

A box-and-whisker plot shows 5 number summary:

Class A Class B
1) minimum value 65 56
2) 1st quartile 66 79
3) median 81 91
4) 3rd quartile 89 94
5) maximum value 95 100

Interquartile range = 3rd Quartile - 1st Quartile
Class A: 89 - 66 = 23
Class B: 94 - 79 = 15

IQR indicates the spread of the of the scores over the median. Class A has a spread that his more than 50% of the scores of Class B.

A piece of ribbon that is 8 and 1/3 yards long will be cut into 5 equal pieces to make bows. How much ribbon will be used foe each bow?

Answers

Answer:

yes

Step-by-step explanation:

Answer: 1 2/3 yards for each bow

Step-by-step explanation:

8 1/3 divided by 5 = 25/3 * 1/5 = 5/3

A line horizontally drawn from the center of the circle.a. Radius
b. Axiom
c. Circumference
d. Vertex

Answers

A line horizontally drawn from the center of the circle is Radius, the correct option is A.

We are given that;

The statement a line horizontally drawn from the center of the circle

Now,

The tangent theorem of a circle states that a line is said to be tangent if it's perpendicular to the circle drawn to the point of tangency.

A radius is a line segment that joins the center of a circle to any point on its circumference.

A circle has infinitely many radii, and they are all equal in length.

Therefore, by circle the answer will be radius.

Learn more about circle here:

brainly.com/question/17043518

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The answer is the radius

Atraeus is solving the quadratic equation by completing the square. 7x^2 – 14x + 6 = 0 7x^2 – 14x = –6 A(x^2 – 2x) = –6 What is the value of A?

Answers

Hello,

A=7
Indeed
A(x²-2x)=-6
7x²-14x=-6

==>A=7 and -14=-2A==>A=7

Answer: D

Step-by-step explanation:

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