Answers
Answer:
Explanation:
To solve this problem, we must use stoichiometry: the calculation of reactants and products in a chemical reaction using ratios.
1. Analyze the Reaction
Check the coefficients, which indicate the moles required for the reaction. 2 moles of sodium (Na) and 1 mole of chlorine (Cl₂) produces 2 moles of sodium chloride (NaCl).
2. Set Up Ratios.
We are asked to find the grams of NaCl produced when 0.548 moles of Na react with excess chlorine.
We need 2 ratios: 1 for finding the moles of NaCl produced and 1 for converting to grams.
The first ratio is found using the coefficients. Since there is excess chlorine, we only need to focus on the sodium and sodium chloride. According to their coefficients, 2 moles of Na produce 2 moles of NaCl. This is the first ratio.
The second ratio uses the molar mass. Since we are solving for the grams of NaCl, we have to find its molar mass.
First, locate these values on the Periodic Table for the individual elements.
- Na: 22.989769 g/mol
- Cl: 35.45 g/mol
There is 1 of each atom in 1 molecule, so we can add these values.
- NaCl: 58.439769 g/mol
Use this value as the second ratio.
3. Calculate
Make 1 expression using the 2 ratios and the initial value of moles.
Flip the ratios so the correct units cancel out.
Multiply. Note that the moles of Na (units) cancel and the moles of NaCl (units). cancel.
The original value of moles has 3 significant figures, so our answer must have the same. For the number we found, that is the tenth place.
- 32.02499341232
The 2 in the hundredth place tells us to leave the 0.
0.548 moles of sodium react with excess chlorine to produce 32.0 grams of sodium chloride.
Related Questions
What are the conjugate base and conjugate acid for HSO4−? What is the term used to describe species that can behave as either an acid or a base, depending on the chemical environment?
Please match word and definition < electrons and electric current move easily 1. electric current < Prevents electrons from moving 2. insulator flow of an electrical charge in a circuit 3. electric circuit 4. conductor provides a path for electrons to flow
If the crucible originally weighs 3.715 g and 2. 000 g of hydrate are added to it , what is the weight of the water that is lost if the final weight of the crucible and anhydrous salt is 5.022?
The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.
Answers
Answer:
2-Phenylpropane (Cumene)
Explanation:
Famous Friedel Craft Alkylation.
Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.
AlCl3 + CH3CH2CH2Cl --> AlCl4- + CH3CH2CH2+
CH3CH2CH2+ ---> CH3CH(+)CH3
C6H6 + CH3CH(+)CH3 ---> C6H5CH(CH3)2 + H+
AlCl4- + H+ ---> HCl + AlCl3
Answer:
From the given problem statement,he was attempting to prepare n−propylbenzene by alkylation benzene with 1−chloropropane and aluminum chloride,but 1-propyle benze was a major product in result.
Answers
As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being measured.
Why does a voltmeter not accurately read voltage?
because the voltmeter uses some of the main circuit's current. Main present in the circuit diminishes as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.
Why are there two probes on a voltmeter?
Nothing is measured at a specific point by the voltmeter. It gauges the voltage (V) differential between two circuit locations. Thus, a multimeter has two leads rather than one.
To know more about measured visit:
#SPJ1
Answers
Most of the time when nitrogen forms a double bond it will be sp2 hybridised. permalink; embed; save.
Answers
Answer:
Explanation:
Hello,
In this case, with the given by-volume percentage and considering the molarity as:
We assume the solution having 100 mL of volume in total, thus, the volume of ethanol is 27.0 mL, therefore, the moles:
Moreover, the volume of the solution in liters is:
Finally, the molarity is:
Best regards.
If the density of ethanol (c2h6o, molar mass 46.07 g/mol) is 0.790 g/ml, the molarity of the 27.0% (v/v) aqueous ethanol solution is 17.14 M.
Calculate the moles of ethanol contained in the solution, then divide that number by the volume of the solution in litres to determine the molarity of the ethanol solution.
To start, we must ascertain how much ethanol is included in each 100 millilitres of the solution. Given that ethanol has a density of 0.79 g/ml, the amount of ethanol in 100 millilitres is as follows:
Mass of ethanol = density × volume
Mass of ethanol = 0.790 g/ml × 100 ml = 79 g
Now,
Moles of ethanol = mass / molar mass
Moles of ethanol = 79 g / 46.07 g/mol = 1.714 mol
So,
Volume of solution = 100 ml / 1000 ml/L = 0.1 L
We know that:
Molarity = moles of solute / volume of solution
Molarity = 1.714 mol / 0.1 L = 17.14 M
Thus, the molarity is 17.14 M.
For more details regarding molarity, visit:
#SPJ6
Answers
The theoretical yield : = 10.251 g
Further explanation
Given
Reaction
3H₂(g)+N₂(g)→2NH₃(g)
1.81 g H₂
10.2 g N₂
2.19 g NH₃
Required
The theoretical yield
Solution
Find limiting reactant :
H₂ : 1.81 g : 2 g/mol = 0.905 mol
N₂ : 10.2 g : 28 g/mol = 0.364 mol
mol : coefficient
H₂ = 0.905 : 3 = 0.302
N₂ = 0.364 : 1 = 0.364
H₂ as a limiting reactant(smaller ratio)
Moles NH₃ based on H₂, so mol NH₃ :
= 2/3 x mol H₂
= 2/3 x 0.905
=0.603
Mass NH₃ :
= mol x MW
=0.603 x 17 g/mol
= 10.251 g
Answers
When a student is warming a chemical in a container using a special burner, it is very important to focus on safety by using the right safety tools.
What is the safety equipment
First, the student needs to wear the right safety clothes like a lab coat, gloves, and goggles to protect themselves from getting splashed or hurt by chemicals. A lab coat stops chemicals from touching the skin, gloves keep the hands safe, and safety goggles protect the eyes from chemicals
and hot things.
Furthermore, using a fume hood is necessary to make sure there is enough fresh air circulating and to remove any dangerous fumes or gases that might be released while heating things up.
Read more about safety equipment here:
#SPJ3
Answer:The student should be wearing a lab coat or maybe an apron to prevent chemicals from spilling or exploding onto their clothes, I do recommend a lab coat better though because it can protect your skin better. Next, make sure while messing with chemicals you are always wearing goggles, if you are not wearing them there is a chance that after touching chemicals you could touch your eyes. And that brings me to washing your hands straight away after messing with chemicals. You could also wear gloves and just take them off when you're done but if you don't have clean hands afterward you could always put the chemicals all over your skin. But in case you do touch your eyes there is always an emergency eyewash station somewhere in the lab room. And if you are to get Chemicals on your skin, in your hair, on your clothes, or to be on fire, there shall be a shower somewhere to get rid of that. But if you read the instructions or listen closely to the teacher you shall have no problem.
Explanation:
I kinda got off topic