What is this car first to awnser is the brianliest
rja85314 avatar

Answers

Answer 1
Answer:

Answer: Lamborghini

Explanation: Is it yours

Answer 2
Answer: Lamborghini ?????????????

Related Questions

. In Stack we can access elements from both endso Trueo False
Quicksort reaches the worst-case time complexity when:Partition is not implemented in placePicking the largest one of input or partitioned data as pivot valueMedian of input or partitioned data is expensive to calculateData is sorted already and always pick the median as pivotChoose the incorrect statement:When the median is always picked as pivot in input/partitioned data, then quicksort achieves the best-case time complexity.Mergesort has O(N(log(N)) time complexity for its worst case, average case and best caseInsertionsort reaches its best-case time complexity O(N log(N)) when the input data is pre-sortedQuicksort is practically fast and frequently used sorting algorithm.Choose the incorrect statement:In the lower bound analysis by using decision tree, each branch uses one comparison to narrow down possible casesIn the lower bound analysis by using decision tree, he number of required comparisons can be represented by height of decision treeA decision tree to sort N elements must have N^2 leavesO(N log(N)) lower bound means that comparison-based algorithm cannot achieve a time complexity better than O(N log(N))Choose the incorrect statement regarding time complexity of union-find operation:Inverse Ackermann function does not depend on N and is a constant factor.When we use arbitrary union and simple find for union-find operation, the worst-case time complexity is O(MN) for a sequence of M operations and N elementsUnion-by-size and Union-by-rank both improve the time complexity to O(M log(N)) for a sequence of M operations and N elementsTo finish the entire equivalence class computation algorithm, we need to go over each pair of elements, so if we use union-by-rank with path compression for find operation, then the overall time complexity is O(N^2 log*N), where log*N denotes the inverse Ackermann function.Choose the incorrect statement regarding Dijstraâs algorithmDijstraâs algorithm is a greedy algorithmDijstraâs algorithm requires to dynamically update distance/costs/weights of paths.To begin with, Dijstraâs algorithm initializes all distance as INFDijstraâs algorithm can be implemented by heaps, leading to O(|E|+|V| log(|V|)) time complexity, where, particularly, log(|V|) is due to "insert" operation in heaps.
How will you ensure that all of the network's applications and tcp/ip services also support ipv6?
Write code which takes a user input of a String and an integer. The code should print each letter of the String the number of times the user inputted in reverse order. I believe it's supposed to use nested loops, but I can only get it to repeat the whole word backwards x times.ex.Input a String:codeInput an integer:3eeedddoooccc
What is the most important trait of the first pilot project in the AI Transformation Playbook?

Which statement is written correctly?

Answers

Answer:

B.

Explanation:

In Javascript, the if should have a condition attached to it with parenthesis and curly braces.

Which items are placed at the end of adocument
O Header
O Footer
O Foot Note
O End note​

Answers

Answer:

End note, I think plz tell me if im wrong thank you

. How are returnspredicted in modern microprocessors?

Answers

Answer:

Return are predicted in the modern microprocessor as, branch predictor is the modern method for the processor for the prediction. The basic function of the branch predictor is improving in the pipeline instruction. It is basically the important part for implement the execution and the pipe lining. And the return predicted uses the call by reference technique for the data in instruction.

Write a program that can be used to assign seats for a commercial airplane. The airplane has 13 rows, with six seats in each row. Rows 1 and 2 are first class, rows 3 through 7 are business class, and rows 8 through 13 are economy class. Your program must prompt the user to enter the following information: a. Ticket type (first class, business class, or economy class)b. Desired seatSo far the code I have is ... now can I go about finishing to retreive the user input ? (This is for C++)#include #include using namespace std;int main(){ int r, c; char seat_resvr; char tic_type; char availability[13][6], reserved[2]; int row_num, col_num; char seats; cout << "A program that lets you choose your seating arrangement on an airplane"; cout << endl; char A[13][6]; for (int r = 0; r < 13; r++) { for (int c = 0; c < 6; c++) A[r][c] = '*'; } /*int row, seat; cin >> row >> seat; A[row - 1][seat - 1] = 'X';*/ cout << " A B C D E F" << endl; for (int r = 0; r < 13; r++) { cout << "Row" << setw(3) << r + 1 << " "; for (int c = 0; c < 6; c++) cout << A[r][c] << ' '; cout << endl; } cout << endl << "* -- available seat" << endl << "X -- occupied seat" << endl << endl << "Rows 1 and 2 are for first class passengers." << endl << "Rows 3 through 7 are for business class passengers." << endl << "Rows 8 through 13 are for economy class passengers." << endl; cout << "To reserve a seat enter Y/y (Yes), N/n(No):" << endl; cin >> seat_resvr; reserved[2] = 'X'; return 0;}

Answers

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

#include <stdio.h>

#include <cst dlib>

using namespace st d;

int main(int argc, char *argv[])

{

int airplane[13][6];

char airchar[13][6];

string ticket;

int row[2];

char seat;

//--------------------------------------------

for(int i = 0; i < 13; i++)

{

for(int j = 0; j < 6; j++)

{

airchar[i][j] = '*';

airplane[i][j] = 0;

}

}

//--------------------------------------------

for(;;)

{

cout<<"Rows 1 and 2 are first class (F C)"<<endl;

cout<<"Rows 3 through 7 are business class (B C)"<<endl;

cout<<"Rows 8 through 13 are economy class (E C)"<<endl;

cout<<endl;

cout<<"* - Available"<<endl;

cout<<"X - Occupied"<<endl;

cout<<endl;

cout<<" \t A\t B\t C\t D\t E\t F"<<endl;

cout<<"Row 1\t"<<airchar[0][0]<<"\t"<<airchar[0][1]<<"\t"

<<airchar[0][2]<<"\t"<<airchar[0][3]<<"\t"<<airchar[0][4]<<"\t"

<<airchar[0][5]<<endl;

cout<<"Row 2\t"<<airchar[1][0]<<"\t"<<airchar[1][1]<<"\t"

<<airchar[1][2]<<"\t"<<airchar[1][3]<<"\t"<<airchar[1][4]<<"\t"

<<airchar[1][5]<<endl;

cout<<"Row 3\t"<<airchar[2][0]<<"\t"<<airchar[2][1]<<"\t"

<<airchar[2][2]<<"\t"<<airchar[2][3]<<"\t"<<airchar[2][4]<<"\t"

<<airchar[2][5]<<endl;

cout<<"Row 4\t"<<airchar[3][0]<<"\t"<<airchar[3][1]<<"\t"

<<airchar[3][2]<<"\t"<<airchar[3][3]<<"\t"<<airchar[3][4]<<"\t"

<<airchar[3][5]<<endl;

cout<<"Row 5\t"<<airchar[4][0]<<"\t"<<airchar[4][1]<<"\t"

<<airchar[4][2]<<"\t"<<airchar[4][3]<<"\t"<<airchar[4][4]<<"\t"

<<airchar[4][5]<<endl;

cout<<"Row 6\t"<<airchar[5][0]<<"\t"<<airchar[5][1]<<"\t"

<<airchar[5][2]<<"\t"<<airchar[5][3]<<"\t"<<airchar[5][4]<<"\t"

<<airchar[5][5]<<endl;

cout<<"Row 7\t"<<airchar[6][0]<<"\t"<<airchar[6][1]<<"\t"

<<airchar[6][2]<<"\t"<<airchar[6][3]<<"\t"<<airchar[6][4]<<"\t"

<<airchar[6][5]<<endl;

cout<<"Row 8\t"<<airchar[7][0]<<"\t"<<airchar[7][1]<<"\t"

<<airchar[7][2]<<"\t"<<airchar[7][3]<<"\t"<<airchar[7][4]<<"\t"

<<airchar[7][5]<<endl;

cout<<"Row 9\t"<<airchar[8][0]<<"\t"<<airchar[8][1]<<"\t"

<<airchar[8][2]<<"\t"<<airchar[8][3]<<"\t"<<airchar[8][4]<<"\t"

<<airchar[8][5]<<endl;

cout<<"Row 10\t"<<airchar[9][0]<<"\t"<<airchar[9][1]<<"\t"

<<airchar[9][2]<<"\t"<<airchar[9][3]<<"\t"<<airchar[9][4]<<"\t"

<<airchar[9][5]<<endl;

cout<<"Row 11\t"<<airchar[10][0]<<"\t"<<airchar[10][1]<<"\t"

<<airchar[10][2]<<"\t"<<airchar[10][3]<<"\t"<<airchar[10][4]<<"\t"

<<airchar[10][5]<<endl;

cout<<"Row 12\t"<<airchar[11][0]<<"\t"<<airchar[11][1]<<"\t"

<<airchar[11][2]<<"\t"<<airchar[11][3]<<"\t"<<airchar[11][4]<<"\t"

<<airchar[11][5]<<endl;

cout<<"Row 13\t"<<airchar[12][0]<<"\t"<<airchar[12][1]<<"\t"

<<airchar[12][2]<<"\t"<<airchar[12][3]<<"\t"<<airchar[12][4]<<"\t"

<<airchar[12][5]<<endl;

cout<<endl;

cout<<"Enter Ticket type (F C, B C, or E C): ";

cin>>ticket;

cout<<"Desired Row: ";

cin>>row[0];

cout<<"Desired seat (A,B,C,D,E or F): ";

cin>>seat;

switch(seat)

{

case 'A':

case 'a':

row[0] = row[0] - 1;

row[1] = 1;

row[1] = row[1] - 1;

break;

case 'B':

case 'b':

row[0] = row[0] - 1;

row[1] = 2;

row[1] = row[1] - 1;

break;

case 'C':

case 'c':

row[0] = row[0] - 1;

row[1] = 3;

row[1] = row[1] - 1;

break;

case 'D':

case 'd':

row[0] = row[0] - 1;

row[1] = 4;

row[1] = row[1] - 1;

break;

case 'E':

case 'e':

row[0] = row[0] - 1;

row[1] = 5;

row[1] = row[1] - 1;

break;

case 'F':

case 'f':

row[0] = row[0] - 1;

row[1] = 6;

row[1] = row[1] - 1;

break;

}

if(ticket == "F C")

{

if(row[0]+1 == 1 || row[0]+1 == 2)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "B C")

{

if(row[0]+1 == 3 || row[0]+1 == 4 || row[0]+1 == 5

|| row[0]+1 == 6|| row[0]+1 == 7)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "E C")

{

if(row[0]+1 == 8 || row[0]+1 == 9 || row[0]+1 == 10

|| row[0]+1 == 11|| row[0]+1 == 12|| row[0]+1 == 13)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

row[0] = 0;

row[1] = 0;

system("cls");

}

return 0;

}

How do you calculate the total resistance in a series circuit with more than one resistor?

Answers

Resistors are said to be connected in series when they are daisy chained together in a single line. The serial circuit of resistors result  has a common current flowing through the resistors.
The current that flows through one resistor must also flow through the others.

The total equivalent resistance, is given as:

Rtotal = R1 + R2 + R3 , where R1 is the resistance of the first resistor, R2 of the second and R3 f the third

Write a program that takes an integer as input, representing a year in school. Output "Elementary school" for 0-5, "Middle school" for 6-8, "High school" for 9-12, "College" for 13-16, and "Post-secondary" for 17 and higher. Output "Invalid" for negative input. If the input is 7, the output is:

Answers

In python:

year = int(input("Enter the school year: "))

if 0 <= year <= 5:

   print("Elementary school")

elif 6 <= year <= 8:

   print("Middle school")

elif 9 <= year <= 12:

   print("High School")

elif 13 <= year <= 16:

   print("College")

elif year >= 17:

    print("Post-secondary")

else:

   print("Invalid")

I hope this helps!

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