A bill of $424 was paid with $5 bills and $2 bills. A total of 128 bills were used. Howmany of them were fives?

Answers

Answer 1
Answer:

Answer: 56

Step-by-step explanation:

Let the number of $5 be x

Let the number of $2 be y.

Based on the information given, we can form an equation as:

x + y = 128 ........ i

5x + 2y = 424 ....... ii

Multiply equation i by 2

Multiply equation ii by 1

2x + 2y = 256 ...... iii

5x + 2y = 424 ....... iv

Subtract iii from iv

3x = 168

x = 168/3

x = 56.

Therefore, there were 56 $5 bills.


Related Questions

Which addition does the model below represent?3 + (negative 1)3 + 43 + (negative 4)3 + 1
Factor out the GCF 7x+49
Explain the steps necessary for solving the following equation. x^2-8x-20=0
Arthur baked 1 7/12 dozen muffins. Nina baked 1 1/12 dozen muffins. How many dozen muffins did they bake?
Choose the correct name for these sets of numbers.

The Canadian $2 coin has a copper centre surrounded by a ring of nickel. The diameter of the coin is 2.8 cm. The area of the copper centre is 2.0 cm2 . What is the area of the nickel ring

Answers

Answer:

           6.0 cm²

Step-by-step explanation:

Area of the coin:

A_c = d\pi\n\nA_c = 2.8\pi\approx8.8\ cm^2

So area of the ring:

A = 8.8 - 2.0 = 6.0 cm²

Answer:

4.15

Step-by-step explanation:

d = 2.8cm,  a = 1.4cm

a = πr2

a = 3.14 * 1.42

a = 3.14 * 1.96

a = 6.15cm2

6.15 - 2 = 4.15

The area of the nickel ring is 6.15cm2

if the perimeter of the rectangle is 96 feet, what are the length and width of the rectangular section?

Answers

Answer:

length is 39ft

width is 9ft

Step-by-step explanation:

let 6x - 15 be the length and x be the width

the perimeter of a rectangle is 2(L+W)

96 = 2(6x - 15 + x)

96 = 2(7x - 15)

96 = 14x - 30

126 = 14x

x = 9

Length is 6x - 15

6(9) - 15

54 - 15 = 39

Uhmmmmmmmmmmmmmmmmmmmmm

Answers

Step-by-step explanation:

l=✓9²+4²

l=√81+16

l=✓97

If we have 6,000 movies and 3/5 were borrowed . how many movies were borred

Answers

1800 movies were borrowed: 6000 * 3/5=1800

6,000 * 3/5
 = 6,000/5 * 3
 = 1,200 * 3
 = 3,600

Word problem in Algebra - Two boys, Shawn and Curtis, went for a walk, Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For How many seconds had Shawn been walking at the moment when the two boys had walked the same distance?

Answers

So first you should simplify it.
Shawn (S) - 5 ft. per sec
Curtis (C) - 6 ft. per sec
     1 sec        2 s         3 s         4s        5s          6s
S     25 ft       30 ft       35 ft      40 ft      45 ft      50 ft
C     6 ft        12 ft       18 ft      24 ft      30 ft      36 ft
So we keep going on with this table until we find two numbers that match, which is 30. Then we look back at the question. We want to find how many seconds Shawn was at when the hit the same distance as Curtis (30 ft). Yet be sure to keep in mind that Shawn started 20 seconds earlier. So the answer is 2 seconds.

What is the LCD of 1/3 and 1/4?

Answers

Howdy there! :) the answer to your question is 12. 3/12 and 4/12.

Hope I helped! ;)

The lowest common denominator is 12.

1/3 = 4/12
1/4 = 3/12