4. A recipe says that 2 3/5 cups of flour are needed to make 1 batch of biscuits. How many cups of flour are needed to make 2 batches of biscuits? O 43/5 O 51/5 O 26/10 O 6​

Answers

Answer 1
Answer: the answer is the second option, 5 1/5

Related Questions

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Geometry proof help please
The multiplicative inverse of – 1 in the set {-1,1}is
An angle is one-fourth of a circle. How many one-degree angles can be made from this angle?
A triangle has sides with lengths of 8 kilometers, 13 kilometers, and 16kilometers. Is it a right triangle?

Please help please please help

Answers

X=1

3*4=12
x*4=4

Or

12/4=3
4/4=1

Answer:

x=1

Step-by-step explanation:

i did it

 Find 5 consecutive whole numbers if it is known that the sum of the squares of the first 3 numbers is equal to the sum of the squares of the last 2 numbers.

Answers

so... our numbers... let's say the first one is hmmm "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4

there, 5 consecutive whole numbers or integers for that matter

now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two

so \bf \begin{cases}a\na+1\na+2\n\textendash\textendash\textendash\textendash\na+3\na+4\end{cases}\qquad (a)^2+(a+1)^2+(a+2)^2=(a+3)^2+(a+4)^2

do a binomial theorem expansion on those, solve for "a"

2. From the definition of the derivative (definition 5.3), find the derivative for each of the following functions: (a) f(x) = 6x (b) f(x) = 12x – 2 (c) f(x) = kx² for k a constant

Answers

Answer:

a) f'(x)=6

b) f'(x)=12

c) f'(x)=2kx

Step-by-step explanation:

To find :  From the definition of the derivative find the derivative for each of the following functions ?

Solution :

Definition of the derivative is

f'(x)= \lim_(h \to 0)((f(x+h)-f(x))/(h))

Applying in the functions,

a)f(x)=6x

f'(x)= \lim_(h \to 0)((6(x+h)-6x)/(h))

f'(x)= \lim_(h \to 0)((6x+6h-6x)/(h))

f'(x)= \lim_(h \to 0)((6h)/(h))

f'(x)=6

b) f(x)=12x-2

f'(x)= \lim_(h \to 0)((12(x+h)-2-(12x-2))/(h))

f'(x)= \lim_(h \to 0)((12x+12h-2-12x+2)/(h))

f'(x)= \lim_(h \to 0)((12h)/(h))

f'(x)=12

c) f(x)=kx^2 for k a constant

f'(x)= \lim_(h \to 0)((k(x+h)^2-kx^2)/(h))

f'(x)= \lim_(h \to 0)((k(x^2+h^2+2xh-kx^2))/(h))

f'(x)= \lim_(h \to 0)((kx^2+kh^2+2kxh-kx^2)/(h))

f'(x)= \lim_(h \to 0)((h(kh+2kx))/(h))

f'(x)= \lim_(h \to 0)(kh+2kx)

f'(x)=2kx

A movie theater sends out a coupon for 80​% off the price of a ticket. Write an equation for the​ situation, where y is the price of the ticket with the​ coupon, and x is the original price of the ticket. Use pencil and paper. Draw a graph of the equation and explain why the line should only be in the first quadrant.

Answers

Answer:

0.20x

Step-by-step explanation:

Answer:

10x8 80/10 8x10

Step-by-step explanation:

Find the value of y when x = -5

Answers

Answer:

there isn't even a y here

Step-by-step explanation:

Did you not write the while question?

A mother wants to invest $6000 for her children's education. She invests a portion of the money in a bank certificate of deposit (CD account) which earns 4% and the remainder in a savings bond that earns 7%. If the total interest earned after one year is $360, how much money was invested at each rate?

Answers

0.04x+0.07(6000-x)=360
0.04x+420-0.07x=360
0.04x-0.07x=360-420
−0.03x=−60
X=60/0.03=2,000 at 4%
6000-2000=4000 at 7%