Find the value of x.X =
Tell whether the side lengths form a Pythagorean triple.
o yes
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Find the value of x. X = Tell whether the - 1

Answers

Answer 1
Answer:

Answer:

x = √72 and yes, it forms a Pythagorean triple

Step-by-step explanation:

a^2 + b^2 = c^2,

3 is a, x is b, anf 9 is c

3^2 + x^2 = 9^2

9 + x^2 = 81

Subtract 9 from both sides

x^2 = 72

x = √72

a Pythagorean triple is a^2 + b^2 = c^2, and this has it

Answer 2
Answer:

Answer:

X = 9.4

Step-by-step explanation:

Pythagorean Theorem:

Formula: a² + b² = c²

  • 9 x 9 = 81  
  • 3 x 3 = 9
  • 81 + 9 = 90
  • √90 = 9.48 (Rounded 9.5)

- A Pythagorean triple consists of any three positive integers.


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Find the area, olease I’ll give brainlist

Transformation of y=3x^2

Answers

Answer:

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4 An alloy is a mixture of metals. Most of the gold used in jewellery is an alloy of pure gold and other metals which are added to make the gold harder. Pure gold is 24 carats (ct), so 18 carat parts pure gold 18 gold is an alloy of gold and other metals in the ratio 18:6. In other words, 18/24 parts pure gold and 6/24 other metals. a. A jeweller makes an 18 ct gold alloy using three grams of pure gold. What mass of other metals does she add?
b . An 18 ct gold chain contains four grams of pure gold. How much other metal does it contain? c. What is the ratio of gold to other metals in 14 ct gold?
d. What is the ratio of gold to other metals in 9 ct gold? ​

Answers

To calculate the mass of other metals in each scenario, we need to use the given ratios.

Given:

- Pure gold is 24 carats (ct).

- 18 carat gold is an alloy of gold and other metals in the ratio 18:6 (18/24 parts pure gold and 6/24 other metals).

a. A jeweller makes an 18 ct gold alloy using three grams of pure gold. What mass of other metals does she add?

First, let's find the mass of other metals in the 18 ct gold alloy.

18 ct gold contains 18/24 parts pure gold and 6/24 parts other metals. So, if the jeweller uses 3 grams of pure gold, the amount of other metals in the alloy can be calculated as follows:

Mass of other metals = (6/24) * 3 grams

Mass of other metals = (1/4) * 3 grams

Mass of other metals = 3/4 grams

b. An 18 ct gold chain contains four grams of pure gold. How much other metal does it contain?

Similarly, for the 18 ct gold chain containing 4 grams of pure gold:

Mass of other metals = (6/24) * 4 grams

Mass of other metals = (1/4) * 4 grams

Mass of other metals = 4/4 grams

Mass of other metals = 1 gram

c. What is the ratio of gold to other metals in 14 ct gold?

For 14 ct gold, the ratio of gold to other metals is 14:10 (since 14 + 10 = 24, and gold is 14 out of 24 parts, while other metals are 10 out of 24 parts).

d. What is the ratio of gold to other metals in 9 ct gold?

For 9 ct gold, the ratio of gold to other metals is 9:15 (since 9 + 15 = 24, and gold is 9 out of 24 parts, while other metals are 15 out of 24 parts).

Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is

Answers

Answer:

The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is 5/9.

Step-by-step explanation:

As given:  Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.

A pair of dice has 36  possible outcomes.

The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is 20/36 or 5/9

Let 'A' and 'B' be the events that the sum of the numbers rolled is a multiple of 3 and a multiple of 4 respectively.

Set for A = {(1, 2), (1, 5), (2, 1), (2, 4), (3, 3), (3, 6), (4, 2), (4, 5), (5, 1), (5, 4), (6, 3), (6, 6)},  and set for B = {(1, 3), (2, 2), (2, 6), (3, 1), (3, 5), (4, 4), (5, 3), (6, 2), (6, 6)}.

So, together they form 20 sets ((6,6) is repeating so take once)

Hence, we get 20/36=5/9

the multipules of 3 or 4 are 3,4,6
3 out of 6
1/2

probablity is 0.5

Match each point label on the box it to its description.

Answers

Each point label on the box plot should be matched to its description as follows;

Point A ↔ minimum value.

Point B ↔ first quartile.

Point C ↔ median.

Point D ↔ maximum value.

What is a box-and-whisker plot?

In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.

Based on the information provided about the data set, the five-number summary for the given data set include the following:

  1. Minimum (Min) is labelled point A = 4.
  2. First quartile (Q₁) is labelled point B = 8.
  3. Median (Med) is labelled point C = 12.
  4. Third quartile (Q₃) = 14.
  5. Maximum (Max) is labelled point D = 20.

Read more on boxplot here: brainly.com/question/29648407

#SPJ2

A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median. 
The point to the outside of the box is the third quartile.
D is the maximum value.

Hope this helped.

How would you find the value of x is x equals five, in the equation...5x+29=45?

Answers

5x+29 = 45
5x = 16 (subtract 29 from both sides)
x = 16/5.

That is the answer, I don't know where you got the value of 5 but it doesn't make sense. To prove it, let's try put it into the equation:

5x5 + 29 =45
25 + 29 = 45
Wrong! 25 + 29 = 54.

What is the slope of the line that passes through
(1, -19) and (-2, -7)?

Answers

Answer:

i need help

Step-by-step explanation:

for the formula for slope is y=mx+b

and m is the slope

the answer

so the slope

-1