The slope of a position vs time graph is equal to what

Answers

Answer 1

Answer: Since I am not sure what you are asking, I am just going to throw a bunch of information at you and hope that the answer you are seeking is present.

1) The slope is equal to the velocity at a given time. In other words, find the velocity and evaluate at it at that specific value of time.

2) Velocity = acceleration x time, assuming the acceleration is constant.

3) Velocity = area under the curve of acceleration, evaluated from the start time to the end time.

Hope this helps.

Answer 2

Answer:

Final answer:

The slope of a position vs time graph represents the average velocity of the object. The velocity corresponds to the rate of change in the object's position over time. Further analysis reveals that the slope of a velocity vs. time graph signifies the object's acceleration.

Explanation:

In the context of physics, when analyzing a position versus time graph, the slope represents the object's average velocity. The slope is calculated as the rise over run. Rise is the change in position, or displacement, and run is the change in time. For example, Figure 3.9 shows the position (x(t)) versus time graph. The slopes of the tangent lines at specific times (0.25s, 0.5s, and 1s) indicate the object's velocity at the corresponding times. Therefore, the slope of a position vs time graph equals the velocity of the object.

Further analysis of a velocity versus time graph would then show that its slope represents the object's acceleration. This highlights the direct relationship between position, velocity, and acceleration in motion physics.

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A 0.5 kg object, initially at rest, is pulled to the right along a frictionless horizontal surface by a constant horizontal force of 25 N for adistance of 0.5m.
a. What is the work done by the force?
b. What is the change in the kinetic energy of the block?
c. What is the speed of the block after the force is removed?
Help asap plz

Answers

Answer:

A.) 12.5 J

B.) 12.5 J

C.) 7.1 m/s

Explanation:

Given that a 0.5 kg object, initially at rest, is pulled to the right along a frictionless horizontal surface by a constant horizontal force of 25 N for a distance of 0.5m.

a. What is the work done by the force?

Work done = force × distance

Work done = 25 × 0.5

Work done = 12.5 J

b. What is the change in the kinetic energy of the block?

Work done = energy

Change in Kinetic energy = work done

Change in kinetic energy = 12.5 J

c. What is the speed of the block after the force is removed?

Kinetic energy = 1/2mV^2

12.5 = 1/2 × 0.5 × V^2

25 = 0.5V^2

V^2 = 25/0.5

V^2 = 50

V = 7.1 m/s

A mixed dentition usually consists of

Answers

During childhood a mixed dentition refers to the period when a person has both baby) teeth and permanent (adult) teeth in their mouth. This stage occurs as children start losing their baby teeth and new permanent teeth gradually take their place. It's a part of development that lasts for several years until all the primary teeth are replaced by permanent ones.

Kira jogs to a store 72 miles away in a time of 36 seconds. What is Kira's average speed?

Answers

Answer:

Explanation:

Do time divided by miles

36/72 = 0.5

That means for every mile 0.5 seconds is ran

that's pretty fast :)

the resultant resistance of two resistance wires in series combination is 108 ohm and in parallel combination is 24 ohm. find the value of individual resistance

Answers

Call the two resistors 'x' and 'y'.

In series, the resultant resistance is their sum: x + y = 108
Notice that y = 108 - x. I think we'll use that very soon.

In parallel, the resultant resistance is (their product) / (their sum) = xy/108 = 24

Multiply each side by 108:

xy = 2,592

Substitute for 'y' :

x(108 - x) = 2,592

108x - x² = 2,592

-x² + 108x - 2,592 = 0

x² - 108x + 2,592 = 0

Use the quadratic formula to find:

x = 72 . . . then y = 108 - 72 = 36
or
x = 36 . . . then y = 108 - 36 = 72

The individual resistors are 36Ω and 72Ω .

What temperature is required to transfer waste heat to the environment for a heat engine to be 100 percent efficient?

Answers

This can be seen as a trick question because heat engines can typically never be 100 percent efficient. This is due to the presence of inefficiencies such as friction and heat loss to the environment. Even the best heat engines can only go up to around 50% efficiency.

Answer:

An infinite temperature

Explanation:

The efficiency of an engine is defined as:

$\eta=1 -(T_C)/(T_H)$

where

$T_H$ is the temperature at which heat enters the engine

$T_C$ is the temperature of the environment, to which the engine exhausts heat

From the formula, we see that for an engine to be 100% efficient, the fraction

$(T_C)/(T_H)$

must be equal to zero. Since the value of $T_C$ is never zero (the temperature is expressed in Kelvin, and the temperature of the environment can never be exactly 0 K), the only possibility for that to occur is that the temperature at which heat enters the engine ( $T_H$ ) is infinite, so that this fraction becomes zero and the efficiency becomes 1.

You run straight off a high diving board at a speed of 6 m/sec. You hit the water 2 seconds later.a. How far did you travel horizontally during the 2 seconds?
b. How far did you travel vertically during the 2 seconds?
c. How fast were you moving horizontally when you hit the water?
d. How fast were you moving vertically when you hit the water?

Answers

My answers are in the comments. Sorry for the repeated answers on some of them

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