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A balloon has a volume of 7.00 liters at a pressure of 740 mm Hg. If the temperature remains constant, at what pressure will the volume decrease to 2.00 liters?a. 749 mm Hg
b. 52.9 mm Hg
c. 211 mm Hg
d. 2590 mm Hg

Answers

Answer 1

Answer:

Answer:

Explanation:

P1 x V1 = P2 x V2

7.00(740) = x(2.00)

2590 mm Hg

took me a while because i dont know this, hope its right good luck

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At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentration of HI?
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Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 26.34 mL sample of 0.0100 M K I O 3 with a solution of N a 2 S 2 O 3 of unknown concentration. The endpoint was observed to occur at 15.51 mL . How many moles of K I O 3 were titrated

Answers

Answer:

0.1 M

Explanation:

The overall balanced reaction equation for the process is;

IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)

Generally, we must note that;

1 mol of IO3^- require 6 moles of S2O3^2-

Thus;

n (iodate) = n(thiosulfate)/6

C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6

Concentration of iodate C(iodate)= 0.0100 M

Volume of iodate= V(iodate)= 26.34 ml

Concentration of thiosulphate= C(thiosulfate)= the unknown

Volume of thiosulphate=V(thiosulfate)= 15.51 ml

Hence;

C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)

0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M

Final answer:

To determine the moles of KIO_3 titrated, use the balanced equation 2 KIO_3 + 5 Na_2S_2O_3 + 6 HCl → 3 I_2 + 6 NaCl + 6 NaClO + 3 H_2O. Therefore, 0.001551 mol of KIO_3 were titrated.

Explanation:

To determine the moles of KIO3 titrated, we need to use the balanced equation for the reaction:

2 KIO3 + 5 Na2S2O3 + 6 HCl → 3 I2 + 6 NaCl + 6 NaClO + 3 H2O

From the equation, we can see that 2 moles of KIO3 react with 5 moles of Na2S2O3. Therefore, the moles of KIO3 titrated can be calculated using the following proportion:

(0.0100 M KIO3 / 1 L) * (15.51 mL / 1000 mL) * (2 mol KIO3 / 5 mol Na2S2O3) = 0.001551 mol KIO3

Learn more about Moles of KIO_3 titrated here:

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Help me assiment will close after an hour

Answers

Answer :

(a) The molecular equation will be,

$CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)$

(b) The complete ionic equation in separated aqueous solution will be,

$Ca^(2+)(aq)+CO_3^(2-)(aq)+2H^(+)(aq)+2Cl^(-)(aq)\rightarrow Ca^(2+)(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)$

(c) The net ionic equation will be,

$CO_3^(2-)(aq)+2H^(+)(aq)\rightarrow H_2O(l)+CO_2(g)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The molecular equation will be,

$CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)$

(b) The complete ionic equation in separated aqueous solution will be,

$Ca^(2+)(aq)+CO_3^(2-)(aq)+2H^(+)(aq)+2Cl^(-)(aq)\rightarrow Ca^(2+)(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)$

In this equation, $Ca^(2+)\text{ and }Cl^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

(c) The net ionic equation will be,

$CO_3^(2-)(aq)+2H^(+)(aq)\rightarrow H_2O(l)+CO_2(g)$

Which of the following best describe gas particles?SELECT ALL THAT APPLY
a moving randomly
b collide into each other
c move slow
d high kinetic energy
e moving orderly

Answers

The gas particlesmove randomly (a), collide into each other (b) and have high kinetic energy (d).

Which of the following best describe gas particles?

a moving randomly.YES. They move in all directions without a predefined path.

b collide into each other.YES. They collide into each other and against the walls of the container they are in.

c move slow.NO. They move very rapidly.

d high kinetic energy.YES. Their high kinetic energy is a consequence of their fast movement.

e moving orderly.NO. They move in a random fashion.

The gas particlesmove randomly (a), collide into each other (b) and have high kinetic energy (d).

You can learn more about gases here: brainly.com/question/11973814

Answer:

a,b,d

Explanation:

Gas particles fill space and do not move in an orderly fashion, and are constantly bumping into each other due to their high kinetic energy.

Draw the structure of a compound with the molecular formula CgH1002 that exhibits the following spectral data. (a) IR: 3005 cm-1, 1676 cm-1, 1603 cm-1
(b) H NMR: 2.6 ppm (singlet, I = 3H), 3.9 ppm (singlet, I = 3H), 6.9 ppm (doublet, I = 2H), 7.9 ppm (doublet, I = 2H)
(c) 13C NMR: 26.2, 55.4, 113.7, 130.3, 130.5, 163.5, 196.6 ppm ?

Answers

Answer:

The answer you are looking for is A

A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-cells. The reduction potential of Ni2+ is �0.23 V. Calculate the potential of the cell at 25�C if the more dilute Ni2+ solution is in the anode compartment.

Answers

Answer: The cell potential of the cell is +0.118 V

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode): $Ni(s)\rightarrow Ni^(2+)+2e^-$

Reduction half reaction (cathode): $Ni^(2+)+2e^-\rightarrow Ni(s)$

In this case, the cathode and anode both are same. So, $E^o_(cell)$ will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

$E_(cell)=E^o_(cell)-(0.0592)/(n)\log ([Ni^(2+)_(diluted)])/([Ni^(2+)_(concentrated)])$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_(cell)$ = ?

$[Ni^(2+)_(diluted)]$ = $1.00* 10^(-4)M$

$[Ni^(2+)_(concentrated)]$ = 1.0 M

Putting values in above equation, we get:

$E_(cell)=0-(0.0592)/(2)\log (1.00* 10^(-4)M)/(1.0M)$

$E_(cell)=0.118V$

Hence, the cell potential of the cell is +0.118 V

The cell potential for the cell as calculated is 0.118 V.

What is the Nernst equation?

The Nernst equation can be used to obtain the cell potential of a cell under non- standard conditions. The standard cell potential in this case is zero owing to the fact that both cathode and anode are made of nickel.

Hence;

Ecell = E°cell - 0.0592/nlog Q

Ecell = 0 - 0.0592/2 log (1 00 * 10^-4/1)

Ecell = 0.118 V

The cell potential for the cell as calculated is 0.118 V.

Learn more about Nernst equation: brainly.com/question/721749

Organize the following solvents by increasing polarity A. Dichloromethane, ethanol, ethyl acetate, diethyl ether
B. Diethyl ether, dichloromethane, ethyl acetate, ethanol
C. Ethyl acetate, ethanol, dichloromethane, diethyl ether
D. Ethanol, ethyl acetate, diethyl ether, dichloromethane

Answers

Answer:

B. Diethyl ether, dichloromethane, ethyl acetate, ethanol

Explanation:

The polarity of solvents can be determined by their polarity indexes. Polarity index is defined as the measure of the ability of the solvent to interact with various polar test solutes.

Diethyl ether is the least polar with a polarity index of 2.8

Dichloromethane with a polarity index of 3.1

Ethyl acetate with a polarity index of 4.3

Ethanol is the most polar with a polarity index of 5.2

The differences in polarities of these solvents is due to their structure. Polar solvents have large dipole moments because they contain bonds between atoms with very different electronegativities, such as oxygen and hydrogen.

Because of the two non-polar methyl groups in diethyl ether, it is not as polar as dichloromethane which has two electronegative chlorine atoms attached to a carbon atom. Similarly too, because diethyl ether has two strongly electronegative oxygen atoms sharing a bond with carbon, it has a larger dipole moment than dichloromethane. Ethanol has an oxygen hydrogen bond which has the largest dipole moment, thus, it is the most polar of the given solvents.

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