At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentration of HI?

Answers

Answer 1
Answer: Here's The Answer:  K = 50.2 = (2x)^2 / (0.1-x)^2 
x = 0.078
so H2 eq = 0.022 M

Hope this helped! :D

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What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world?

Answers

The principal reason why we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world is:

  • Photons of certain frequencies can be absorbed as the electron changes energy state

According to the given question, we need to state the principal reason why the uncertainty principle is used when discussing electrons and other subatomic particles but not used in our macroscopic world.

As a result of this, we can see that the reason for this is because there are certain frequencies at which the photons can be absorbed during the electron change as energy becomes more random.

Read more here:

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Here is the correct answer of the given question above. The principal reason that we must consider the uncertainty principle when discussing electrons and other subatomic particles, but not when discussing our macroscopic world is that photons of only certain allowed frequencies can be absorbedor emitted as the electron changes energy state. Hope this answer helps.

In which orbitals would the valence electrons for carbon (C) be placed? s orbital and d orbitals s orbital only p orbitals only s orbital and p orbitals

Answers

Answer:

p orbitals only

Explanation:

Carbon has an atomic number of 6 so its electron configuration will be 1s² 2s² 2p². It has two orbitals as indicated with the 2 as its period number with the outer orbital have 4 valence electrons. So carbon is in the p-orbital, period 2 and in group 4.

Final answer:

Carbon's valence electrons reside in the 2s and 2p orbitals. These orbitals hybridize during bond formation to create equivalent sp3 hybrid orbitals, as evidenced in the methane molecule. Carbon's valence electrons are not placed in d orbitals.

Explanation:

Carbon (atomic number 6) has a total of six electrons. Two of these fill the 1s orbital. The next two fill the 2s orbital, and the final two are in the 2p subshell. According to Hund's rule, the most stable configuration for an atom is one with the maximum number of unpaired electrons. Therefore, carbon has two electrons in the 2s subshell and two unpaired electrons in two separate 2p orbitals. When discussing valence electrons, the electrons in the outermost shell are the ones considered, which for carbon are the electrons in the second shell namely 2s and 2p.

The geometry of the methane molecule (CH4) illustrates that in the bonding process, the s and p orbitals hybridize to allow the formation of four equivalent bonds with hydrogen atoms. Without hybridization, we would expect three bonds at right angles (from the p orbitals) and one at a different angle (from the s orbital). Nonetheless, through orbital hybridization, all four bonds in methane are identical, which is explained by the concept of sp3 hybridized orbitals.

Therefore, the valence electrons for carbon would be placed in the s orbital and p orbitals, not in the d orbitals, because carbon does not have electrons in the d subshell in its ground state. Additionally, the s and p orbitals are the only ones involved in bonding for carbon in most of its compounds, such as methane.

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How many moles of H2O are produced from 6.23g of C2H6 in the following reaction? 2C2H6+7O2 -> 4CO2+6H2O

Answers

Answer:

0.623 moles of H₂O.

Explanation:

  • balanced equation: 2C₂H₆ + 7O₂ -> 4CO₂+ 6H₂O

Given:

  • 6.23g of C₂H₆
  • C₂H₆ molar mass is 30

solve for moles of C₂H₆

  • moles = mass/mr
  • moles = 6.23/30
  • moles = 0.2077

solve for moles of H₂O using molar ratio

  • 2C₂H₆ : 6H₂O
  • 2 : 6
  • 0.2077 : 0.623

Therefore, found that 0.623 moles of H₂O is produced.

If 1.20 g of aluminum hydroxide reacts with 3.00 g of sulfuric acid, what is the mass of water produced? Al(OH)3(s)+H2SO4(l)→Al2(SO4)3(aq)+H2O(l)

Answers

 it would be 342 acid

Animal fats tend to be _______________ with hydrogen atoms. (fifth paragraph of this sub-section

Answers

Animal fats tend to be _______________ with hydrogen atoms. Fats are long chain amino acids, mostly carbon and hydrogen. The answer is "Animal fats tend to be single bonded to or surrounded by or saturated with hydrogen atoms." Saturated means the maximum number of hydrogen atoms are bonded to the carbon atom.

Answer:

Saturated.

Explanation:

Hello,

Animal fats are lipids derived from animals which are commonly solid at room temperature and mainly constituted by triglycerides which are strictly chemically saturated with hydrogen, it means  they do not tend to have double or triple bonded carbon atoms but just single-bonded carbons. This fact suggests that animal fats provide more energy than vegetable fats because they have more C-H bonds that when broken increase the total provided energy.

Best regards.

Refer to the example about diatomic gases A and B in the text to do problems 20-28.It was determined that 1 mole of B2 is needed to react with 3 moles of A2.
How many grams in one mole of B2?
__g

Answers

Final answer:

The number of grams in one mole of B2 can be calculated using the atomic mass of element B. This is found on the periodic table and then doubled for B2 since it's diatomic. If B is Oxygen for instance, 1 mole of B2 (O2) weighs 32 grams.

Explanation:

To find the number of grams in one mole of B2, we need to know the atomic mass of element B, which isn't provided in your question. However, you can find this information on the periodic table. Once you have the atomic mass of B, you can calculate the molar mass of B2 (which is two times the atomic mass of B) since 1 mole of a substance corresponds to its molar mass in grams.

For example, if element B is Oxygen (O), its atomic mass is approximately 16 g/mol. Therefore, the molar mass of B2 (O2 in this case) would be 32 g/mol. Hence, 1 mole of B2 (or O2) would weigh 32 grams.

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