What would be the effect on the observed melting point of sample were poorly packed?

Answers

Answer 1
Answer: if a sample is packed poorly, the sample will not heat evenly and will take longer to melt.

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A 6.13 g sample of an unknown salt (MM = 116.82g/mol) is dissolved in 150.00 g water in a coffee cupcalorimeter. Before placing the sample in the water, thetemperature of the salt and water is 23.72°C. After thesalt has completely dissolved, the temperature of thesolution is 28.54°C.If 3.15 x 10J of heat was gained by the solution, whatis the total heat for the dissolution reaction of the 6.13 gof salt?
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Why isn't salt water safe for humans to drink?O A. Salt water has too many water molecules and too few salt molecules.
B. Salt water has too few water molecules and too many salt molecules.
O
C. Salt water contains molecules that are poisonous to humans.
O
D. Salt water contains molecules that are too large for humans to process.

Answers

Answer:

B. Salt water has too few water molecules and too many salt molecules

Explanation:

Seawater is toxic to humans because your body is unable to get rid of the salt that comes from seawater. Your body normally gets rid of excess salt by having the kidneys produce urine, but it needs freshwater to dilute the salt in your body for the kidneys to work properly.

Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21 ∘C∘C. Express the pressures in atmospheres to three significant digits separated by commas.

Answers

The question is incomplete, complete question is ;

A deep-sea diver uses a gas cylinder with a volume of 10.0 L and a content of 51.8 g of O_2 and 33.1 g of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21°C.Express the pressures in atmospheres to three significant digits separated by commas.

Answer:

Partial pressure of the oxygen gas is 3.91 atm.

Partial pressure of the helium gas is 20.0 atm

Total pressure of the gases is 24.0 atm

Explanation:

Moles of oxygen gas = n_1=(51.8)/(32 g/mol)=1.619 mol

Moles of helium gas = n_2=(33.1 g)/(4 g/mol)=8.275 mol

Total moles of gas = n_1+n_2=(1.619 +8.275 ) mole=9.894 mol

Volume of the cylinder = V = 10.0 L

Total pressure in the cylinder = P = ?

Temperature of the gas in cylinder = T = 21°C = 21 + 273 K = 294 K

PV = nRT ( ideal gas equation )

P=(nRT)/(V)

=(9.894 mol* 0.0821 atm L/mol K* 294 K)/(10.0 L)

P = 23.88 atm ≈ 23.9

Partial pressure of the individual gas will be determined by the help of Dalton's law:

partial pressure = Total pressure × mole fraction of gas

Partial pressure of the oxygen gas

p_(1)=P* \chi_(1)=P* (n_1)/(n_1+n_2)

p_1=23.88 atm* (1.619 mol)/(9.894 mol)=3.91 atm

Partial pressure of the helium gas

p_(2)=P* \chi_(2)=P* (n_2)/(n_1+n_2)

p_2=23.88 atm* (8.275 mol)/(9.894 mol)=19.97 atm\approx 20.0 atm

Arrange the following aqueous solutions in order of decreasing freezing points: 0.10 m KNO3, 0.10 m BaCl2, 0.10 m ethylene glycol ​[C2H4(OH)2, antifreeze], and 0.10 m Na3PO4.

Answers

Answer:

The freezing point of a solution is lowered compared to the freezing point of the pure solvent. The amount of depression of the freezing point is proportional to the molality of the solute. The greater the molality of a solution, the lower its freezing point. To compare the freezing points of these solutions, we need to determine which one has the highest molality.

First, we need to determine the number of particles that each solute will produce in solution, as this affects the amount of depression of the freezing point.

KNO3 dissociates into two ions: K+ and NO3-, so it will produce two particles per formula unit.

BaCl2 dissociates into three ions: Ba2+ and two Cl-, so it will produce three particles per formula unit.

Ethylene glycol does not dissociate in solution, so it will produce one particle per molecule.

Na3PO4 dissociates into four ions: three Na+ and one PO43-, so it will produce four particles per formula unit.

Now, we can calculate the molality (moles of solute per kilogram of solvent) for each solution:

For 0.10 m KNO3: molality = 0.10 mol / 1 kg = 0.10 m

For 0.10 m BaCl2: molality = 0.10 mol x 3 particles / 1 kg = 0.30 m

For 0.10 m ethylene glycol: molality = 0.10 mol / 1 kg = 0.10 m

For 0.10 m Na3PO4: molality = 0.10 mol x 4 particles / 1 kg = 0.40 m

So, the solutions in order of decreasing freezing points are:

0.10 m Na3PO4 (highest molality)

0.10 m BaCl2

0.10 m KNO3 and 0.10 m ethylene glycol (same molality, but KNO3 has a smaller van't Hoff factor than ethylene glycol, so it will have a slightly higher freezing point)

Explanation:

A chemist prepares a solution of magnesium fluoride MgF2 by measuring out 0.00598μmol of magnesium fluoride into a 50.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /μmolL of the chemist's magnesium fluoride solution. Round your answer to 2 significant digits.

Answers

Answer:

0,12 μmol/L of MgF₂

Explanation:

Preparation of solutions is a common work in chemist's life.

In this porblem says that you measure 0,00598 μmol of MgF₂ in 50,0 mL of water and you must calculate concentration in  μmol/L

You have 0,00598 μmol but not Liters.

To obtain liters you sholud convert mL to L, knowing 1000mL are 1 L, thus:

50,0 mL (1L/1000mL) = 0,05 L of water.

Thus, concentration in  μmol/L is:

0,00598 μmol / 0,05 L = 0,12 μmol/L -The problem request answer with two significant digits-

I hope it helps!

The metal thallium becomes superconducting at temperatures below 2.39K. Calculate the temperature at which thallium becomes superconducting in degrees Celsius. Round your answer to decimal places.

Answers

Answer:

-270.76°C

Explanation:

Given that metal Thallium becomes superconducting below the temperature of 2.39 kelvin i.e. this temperature is critical temperature for Thallium and below critical temperature a metal offers no resistance to the flow of electric current. Also the metal below its critical temperature expels the magnetic field in such a way that they do not penetrate the metal and pass through its surface only.

We have the relation between kelvin scale and degree Celsius scale of temperature measurement as:

C = K - 273.15

C=2.39-273.15\n C=-270.76^(o)C

True or False: Observations are just things that you see

Answers

Answer:

False

Explanation:

"Observations is the action of observing something or someone carefully or in order to gain information" - google dictionary. This definition does not completely match the definition given, so the answer is false.

I hope this helps!

Answer: true

Explanation: the action or process of observing something or someone carefully or in order to gain information that is the real definition