CHEMISTRY COLLEGE

How many moles of carbondioxide are produced when 0.2mol of sodium carbonate react with excess hydrovhloric acid

Answers

Answer 1

Answer:

Answer:

0.2 moles of CO₂ are produced

Explanation:

Given data:

Moles of CO₂ produced = ?

Moles of Na₂CO₃ react = 0.2 mol

Solution:

Chemical equation:

Na₂CO₃ + 2HCl → 2NaCl + CO₂ + H₂O

Now we will compare the moles of CO₂ with Na₂CO₃ .

Na₂CO₃ : CO₂

1 : 1

0.2 : 0.2

Thus, 0.2 moles of CO₂ are produced.

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Which response gives the products of hydrolysisofNH4Cl?
A. NH4+ + HCl
B. NH3 + OH- + HCl
C. NH3 + H+
D. NH4OH + HCl
E. No hydrolysis occurs.

Answers

Answer : The correct option is, (C) NH₃ + H⁺

Explanation:

Hydrolysis : It is defined as the chemical reaction in which the breakdown of compound takes place due to reaction with water.

As per question:

First ammonium chloride completely dissociates into ion.

$NH_4Cl(aq)\rightarrow NH_4^+(aq)+Cl^-(aq)$

Now ammonium ion react with water to give ammonia and hydronium or hydrogen ion.

The balanced hydrolysis reaction will be:

$NH_4^++H_2O\rightarrow NH_3+H_3O^+$

Hence, the correct option is, (C) NH₃ + H⁺

Answer:

NH₃ and H⁺

Explanation:

The dissociation of NH₄Cl will lead to two ions , i.e. , NH⁴⁺ and Cl⁻ .

Hence , the reaction is -

NH₄Cl → NH⁴⁺ + Cl⁻

We can conclude that NH₄Cl can be formed from the ions , NH⁴⁺ and Cl⁻

Hence ,

According to the reaction ,

NH⁴⁺ + H₂O ⇆ NH₃ + H₃O⁺

Therefore ,

The reactant that will lead to the formation of NH₄Cl are - NH₃ and H⁺

g What is the typical carbon concentration range for medium-carbon steels? 0.50 wt% - 0.75 wt% C 0.05 wt% - 1.00 wt% C 0.10 wt% - 0.50 wt% C 0.25 wt% - 0.60 wt% C 0.25 wt% - 1.00 wt% C

Answers

Answer:

C 0.25 wt% - 0.60 wt%

Explanation:

A proton is a very tiny particle inside an atom. The mass of a proton isestimated to be 0.00000000000000000000000167 g. What is the mass of a
proton in scientific notation?

Answers

Answer:

1.67 ×10^-24g

Explanation:

counting from the first digit after the point till I got to the first non zero digit

Could someone pls help me :)

Answers

liquid 1 and 2 have the same color and mass so the answer would be liquid 1 and 2

Explanation:

hope this is helpful

To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?

Answers

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where: