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Answer:
Which of the following is a possible set of quantum numbers for a 3p orbital?
Since you are dealing with a 3p-orbital, your principal and angular momentum quantum numbers will be n=3 and l=1 .
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Please help me I will give a brainleist to the. first person to answer
What is the poH of a 3.67 x 10-5 M OH solution and is it acidic, basic, or neutral?
b. 1.50 x 1023 atoms Mg
c. 4.50 x 1012 atoms Cl
d. 8.42 x 1018 atoms Br
e. 25 atoms W
f. 1 atom Au
Answers
The mass in grams of 3.011 x 10²³ atoms of F is 9.5 g.
The mass in grams of 1.50 x 10²³ atoms of Mg is 5.98 g.
The mass in grams of 4.50 x 10¹² atoms of Cl is 2.65 x 10⁻¹⁰ g.
The mass in grams of 8.42 x 10¹⁸ atoms of Br is 1.12 x 10⁻³ g.
The mass in grams of 25 atoms of W is 3.1 x 10⁻²¹ g.
The mass in grams of 1 atom of Au is 3.27 x 10⁻²² g.
What is the mass in grams of 3.011 x 10²³ atoms F?
The mass in grams of 3.011 x 10²³ atoms of F is calculated as follows;
6.023 x 10²³ atoms = 19 g of F
3.011 x 10²³ atoms F = ?
= (3.011 x 10²³ x 19 g)/(6.023 x 10²³)
= 9.5 g
The mass in grams of 1.50 x 10²³ atoms of Mg is calculated as follows;
6.023 x 10²³ atoms = 24g of Mg
1.5 x 10²³ atoms F = ?
= (1.5 x 10²³ x 24 g)/(6.023 x 10²³)
= 5.98 g
The mass in grams of 4.50 x 10¹² atoms of Cl is calculated as follows;
6.023 x 10²³ atoms = 35.5 g of Cl
4.5 x 10²³ atoms Cl = ?
= (4.5 x 10¹² x 35.5 g)/(6.023 x 10²³)
= 2.65 x 10⁻¹⁰ g
The mass in grams of 8.42 x 10¹⁸ atoms of Br is calculated as follows;
6.023 x 10²³ atoms = 80 g of Br
8.42 x 10¹⁸ atoms Br = ?
= (8.42 x 10¹⁸ x 80 g)/(6.023 x 10²³)
= 1.12 x 10⁻³ g
The mass in grams of 25 atoms of W is calculated as follows;
6.023 x 10²³ atoms = 74 g of W
25 atoms W = ?
= (25 x 74 g)/(6.023 x 10²³)
= 3.1 x 10⁻²¹ g
The mass in grams of 1 atom of Au is calculated as follows;
6.023 x 10²³ atoms = 197 g of Au
1 atom of Au = ?
= (1 x 197 g)/(6.023 x 10²³)
= 3.27 x 10⁻²² g
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Final answer:
This solution provides the calculations necessary to convert the number of atoms of various elements (smallest particle of an element) to grams. It does so by using the molar mass of each element and Avogadro's number.
Explanation:
The mass of atoms can be determined by using Avogadro's number (6.022 x 1023 atoms/mol) and the molar mass of the specific element (g/mol). We use these to create a conversion factor and multiply by the number of atoms given.
- For F (fluorine), which has a molar mass of about 18.9984 g/mol, 3.011 x 1023 atoms F is 9.00 g F.
- For Mg (magnesium), with molar mass of about 24.3050 g/mol, 1.5 x 1023 atoms Mg is 6.07 g Mg.
- For Cl (chlorine), with molar mass of about 35.453 g/mol, 4.50 x 1012 atoms Cl is 2.67 x 10-10 g Cl.
- For Br (bromine), with molar mass about 79.904 g/mol, 8.42 x 1018 atoms Br is 0.12 g Br.
- For W (tungsten), with molar mass about 183.84 g/mol, 25 atoms W is 7.65 x 10-22 g W.
- For Au (gold), with molar mass about 197.0 g/mol, 1 atom Au is 3.28 x 10-22 g Au.
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The weighted average (Avg) for these values has been 5.35.
The weighted average has been an arithmetic calculation of the mean value for the percent abundance of each value.
Computation for weighted average
The weighted average (Avg) for the values has been given by:
The values have been given,
The weighted average has been given as:
For the given set of values, the weighted average (Avg) has been given as:
The weighted average (Avg) for these values has been 5.35.
Learn more about weighted average, here:
Answer:
5.35
Explanation:
Value 5.00 6.00 7.00
Weight 75.0% 15.0% 10.0 %
We can determine the weighted average of these values using the following expression.
Weighted average = ∑ wi × xi
where,
w: relative weight
x: value
Weighted average = 5.00 × 0.750 + 6.00 × 0.150 + 7.00 × 0.100
Weighted average = 5.35
producers flowing from the bottom level to primary consumers. What
happens to the other 90% of the energy?
О
The remaining 90% is transformed for life activities such as movement, growth, or
released as heat.
The remaining 90% evaporates into the atmosphere.
The remaining 90% transforms into Hydrogen and Oxygen.
The remaining 90% is recombined to maker larger molecules.
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The number which should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation is; 3.
According to the question;
- We are required to determine what number should be placed in front of CaSO4 to give the same number of each side of the equation.
The equation given is;
?CaSO4 + AlCl3 → CaCl2 + Al2(SO4)3
There are 3 moles of SO4 on the right hand side of the equation and as such, there should be the same number of SO4 on the left too.
In essence, the number that should be added in front of CaSO4 is; 3.
Read more:
Answer : The number placed in front of should be, three (3).
Explanation :
Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
The given unbalanced chemical reaction is,
This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.
In order to balanced the chemical reaction, the coefficient 3 is put before the , the coefficient 2 is put before the
and the coefficient 3 is put before the
.
Thus, the balanced chemical reaction will be,
Therefore, the number placed in front of should be, three (3).
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Answer:
4572cm
Explanation: 1ft =30.48cm so you multiply the length value by 30.48