Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of Ni and H+ in the balanced reaction? Ni2+(aq) + NH4+(aq) → Ni(s) + NO3-(aq)

Answers

Answer 1

Answer:

In this case, the problem is asking for the balance of a redox reaction in acidic media, in which nickel is reduced to a metallic way and nitrogen oxidized to an ionic way.

Thus, according to the given information, it turns out possible for us to balance this equation in acidic solution by firstly setting up the half reactions:

$Ni^(2+)+2e^-\rightarrow Ni^0\n\nN^(3-)H_4^++3H_2O\rightarrow N^(5+)O_3^-+8e^-+10H^+$

Next, we cross multiply each half-reaction by the other's carried electrons:

$8Ni^(2+)+16e^-\rightarrow 8Ni^0\n\n2N^(3-)H_4^++6H_2O\rightarrow 2N^(5+)O_3^-+16e^-+20H^+$

Finally, we add them together to obtain:

$8Ni^(2+)+2N^(3-)H_4^++6H_2O\rightarrow 8Ni^0+2N^(5+)O_3^-+20H^+$

Which can be all simplified by a factor of 2 to obtain:

$4Ni^(2+)+N^(3-)H_4^++3H_2O\rightarrow 4Ni^0+N^(5+)O_3^-+10H^+\n\n4Ni^(2+)(aq)+NH_4^+(aq)+3H_2O(l)\rightarrow 4Ni(s)+NO_3^-(aq)+10H^+(aq)$

Hence, the coefficients in front of Ni and H⁺ are 4 and 10 respectively.

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Answer the in under 30 minutes and I will give brainliestAfter which event in Indonesia did one of the worst tsunamis form?

a hurricane

a volcanic eruption

a landslide

an earthquake

Answers

Answer: I believe the answer is an earthquake.

Explanation: Sorry If I am wrong!

Answer:

earthquake

Explanation:

I took the k12 test

The periodic table displaysOA. all of the known elements that exist in the world today.
OB. only the important elements that exist in the world.
OC. only the important compounds that exist in the world.

Answers

OA. all the known elements that exist in the world today.

A chemist designs a galvanic cell that uses these two half-reactions:O2 (g) + 4H+(aq) + 4e− → 2H2O (l) Eo =+1.23V
Zn+2 (aq) + 2e− → Zn(s) Eo=−0.763V

Answer the following questions about this cell.

Write a balanced equation for the half-reaction that happens at the cathode.
Write a balanced equation for the half-reaction that happens at the anode.
Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you have enough information to calculate the cell voltage under standard conditions

Answers

Answer: The reaction is spontaneous and there is not enough information to calculate the cell voltage.

Explanation:

The substance having highest positive $E^o$ reduction potential will always get reduced and will undergo reduction reaction.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

For a:

The half reactions for the cell occurring at cathode follows:

$O_2(g)+4H^+(aq)+4e^-\rightarrow H_2O(l);E^o_(cathode)=+1.23V$

For b:

The half reactions for the cell occurring at anode follows:

$Zn(s)\rightarrow Zn^(2+)+2e^-;E^o_(anode)=-0.763V$ ( × 2)

For c:

The balanced equation for the overall reaction of the cell follows:

$O_2(g)+4H^+(aq)+2Zn(s)\rightarrow H_2O(l)+2Zn^(2+)(aq)$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_(cell)$

For a reaction to be spontaneous, the standard electrode potential must be positive.

To calculate the $E^o_(cell)$ of the reaction, we use the equation:

$E^o_(cell)=E^o_(cathode)-E^o_(anode)$

Putting values in above equation, we get:

$E^o_(cell)=1.23-(-0.763)=1.993V$

As, the standard electrode potential of the cell is coming out to be positive, the reaction is spontaneous in nature.

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_(cell)=E^o_(cell)-(0.059)/(n)\log ([Zn^(2+)]^2)/([H^(+)]^4* p_(O_2))$

As, the concentrations and partial pressures are not given. So, there is not enough information to calculate the cell voltage.

Hence, the reaction is spontaneous and there is not enough information to calculate the cell voltage.

Ocean water is the coldest at

Answers

The bottom of the ocean because it does not get sun light

Two identical sister chromatids are held together at whatregion on a duplicated chromosome?
a Chromatin
b Centromere
C Centriole
Check it

Answers

After DNA duplication, the chromosome becomes composed of two identical structures, called sister chromatids, which are joined at the centromere area.

Final answer:

Sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment. Chromatin and centrioles do not serve this function. The correct option is b) Centromere.

Explanation:

Two identical sister chromatids are held together at the centromere on a duplicated chromosome. The centromere serves as the point of attachment for sister chromatids. During cell division, the spindle fibers attach themselves to the centromere to pull apart the sister chromatids into two separate cells. This process helps ensure that each new cell receives an identical and complete set of chromosomes. Neither chromatin nor centriole holds sister chromatids together. Chromatin refers to the material chromosomes are made up of, which includes DNA and protein, while centrioles are involved in cell division. In summary, the precise answer to your question is option b) Centromere.

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Hydrogen chloride gas and oxygen react to form water vapor and chlorine gas. What volume of chlorine would be produced by this reaction if 7.12 L of oxygen were consumed? Also, be sure your answer has a unit symbol, and is rounded to 3 significant digits.

Answers

Answer:

Explanation:

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