Answers
The percentage yield of the reaction if 23.1 grams of FeCl₃ is created by 10.61g of Fe is 74.9 %.
What is percent yield?
Percent yield of a reaction is the ratio of actual yield to the theoretical yield multiplied by 100.
As per the given balanced reaction, one mole or 55.85 g of Fe is needed to produce 1 mole or 162.2 g of FeCl₃.
Then theoretically, the mass of FeCl₃ which can be produced by 10.61 g of Fe is calculated as follows:
= (10.61 × 162.2) / 55.85
=30.81 g
This is the theoretical yield.
The actual yield is given 23.1. Now the percentage yield is calculated as follows:
Percentage yield = (Actual yield/ heretical yield)×100
= (23.1/30.81)×100
= 74.9 %.
Hence, the percentage yield of the reaction is 74.9 %.
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Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical formulas. Calculate the empirical formulas of the following polymers: (a) Lucite (Plexiglas); 59.9% C, 8.06% H, 32.0% O (b) Saran; 24.8% C, 2.0% H, 73.1% Cl (c) polyethylene; 86% C, 14% H (d) polystyrene; 92.3% C, 7.7% H (e) Orlon; 67.9% C, 5.70% H, 26.4% N
Write the number 4.92 x 10-3 from scientific notation to regular.Please help?????
Scaled Synthesis of Alum. Show your calculations for:a.the experimental scaling factor giving rise to a 15.0 g theoretical yield;b.the corrected volumes of KOH and H2SO4; andc.the theoretical yield of alum based on the actual amount of Al used.Make sure you carefully show each step for these calculations.
Answers
Answer:
1. Bronsted—Lowry acid
2. Bronsted—Lowry Base
3. Lower the pka
4. Lewis acids
Explanation:
Answers
Answer:
The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.
Explanation:
The acidity of a solution depends on the concentration of H⁺ ions ([H⁺]). We can calculate this concentration from the pH using the following expression.
pH = -log ([H⁺])
American Midwest
pH = -log ([H⁺])
5.02 = -log ([H⁺])
[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M
New England
pH = -log ([H⁺])
4.66 = -log ([H⁺])
[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M
The ratio of concentrations is:
The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.
The change in the acidity of the rain falling in New England is mathematically given as
r=2.29
What is the change in the acidity of the rain falling in New England?
Question Parameter(s):
American midwest pH of 5.02
New England pH of 4.66
Generally, the equation for the pH is mathematically given as
pH = -log ([H⁺])
Therefore American midwest
pH = -log ([H⁺])
5.02 = -log ([H⁺])
[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M
and New england
pH = -log ([H⁺])
4.66 = -log ([H⁺])
[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M
In conclusion, the concentration ratio is
r=2.29
Read more about pH value
Answers
Answer:
a) Q = 2047.8 J (ΔH is negative because it's an exothermic reaction)
b) ΔH = -12.7 kJ /mol
Explanation:
Step 1: Data given
Molar mass of X = 78.2 g/mol
In a constant-pressure calorimeter, 12.6 g of X is dissolved in 337 g of water at 23.00 °C.
The temperature rise to 24.40 °C
The specific heat of the solution = 4.184 J/g°C
Step 2: Calculate the total mass
Total mass of the solution is given by
Total mass = 12.6 grams + 337 grams = 349.6 grams
Step 3: Calculate heat
Q = m*c*ΔT
⇒ m = the total mass = 349.6 grams
⇒ c = the specific heat of solution = 4.184 J/g°C
⇒ ΔT = The change of temperature = T2 - T1 = 24.40 - 23.00 = 1.40 °C
Q = 2047.8 J (ΔH is negative because it's an exothermic reaction)
What is the enthalpy of the reaction?
Calculate number of moles = mass/ molar mass
Moles X = 12.6 grams / 78.2 g/mol
Moles X = 0.161 moles
ΔH = -2047.8 J / 0.161 moles
ΔH = -12719.3 J/mol = -12.7 kJ /mol
A solution prepared by dissolving12.6 g of X in 337 g of water, whose temperature increases from 23.00 °C to 24.00 °C, absorbs 2.05 × 10³ J of heat. The enthalpy of the reaction is -12.7 kJ/mol.
We have a solution prepared by dissolving 12.6 g of X (solute) in 337 g of water (solvent). The mass of the solution (m) is:
The temperature of the solution increases from 23.00 °C to 24.40 °C. Assuming that the solution has the same specific heat as water (c = 4.184 J/(g·°C)), we can calculate the heat absorbed (Q) by the solution using the following expression.
According to the law of conservation of energy, the sum of the heat absorbed by the solution and the heat released by the reaction is zero.
The dissolution of 12.6 g of X (molar mass 78.2 g/mol) leads to the release of 2.05 × 10³ J (hence the negative sign). The enthalpy of the reaction is
A solution prepared by dissolving12.6 g of X in 337 g of water, whose temperature increases from 23.00 °C to 24.00 °C, absorbs 2.05 × 10³ J of heat. The enthalpy of the reaction is -12.7 kJ/mol.
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Answers
The chemical equation will be;
(NH4)2S(aq)+SrCl2(aq)→ 2 NH4Cl(aq) + SrSO4(s)
Further Explanation
Chemical equation
- A chemical equation is an equation showing chemical symbols of reactants and those of products. They represent a chemical reactions between reactants to form products.
- For example; (NH4)2S(aq)+SrCl2(aq)→ 2 NH4Cl(aq) + SrSO4(s), where (NH4)2S and SrCl2 are reactants while NH4Cl and SrSO4 are products.
Types of chemical reactions
Precipitation reaction
- Precipitation reactions are reactions which involves the formation of a precipitate as one of the products. A precipitate is a compound that is insoluble in water.
- An example of a precipitation reaction is; (NH4)2S(aq)+SrCl2(aq)→ 2 NH4Cl(aq) + SrSO4(s), where the compound SrSO4 is the precipitate.
Displacement reaction
- Displacement reactions are reactions where ions replace other ions in their compounds.
- For example; ; (NH4)2S(aq)+SrCl2(aq)→ 2 NH4Cl(aq) + SrSO4(s) is an example of a double displacement reaction where NH4+ takes the place of Sr ions in SrCl2 and Sr2+ takes the place of NH4+ in (NH4)2SO4.
Decomposition reaction
- Decomposition reactions are reactions which involves break down of a compound to its constituent’s elements or other compounds by use of a catalyst or heat.
- For example; Decomposition of lead (II) nitrate using heat to get lead (ii) oxide, oxygen and nitrogen (IV) oxide.
Neutralization reaction
- Neutralization reactions are reactions that involve reacting a base or an alkali and an acid to form a salt and water as the only product.
Redox reactions
- Redox reactions are reactions that involve both reduction and oxidation. Some species in reactions undergo reduction while others undergo oxidation.
Keywords: Chemical reactions, precipitation reactions, chemical equations
Learn more about:
- Types of chemical reactions: brainly.com/question/10038840
- Example of precipitation reaction: brainly.com/question/1146642
- Example of single displacement reaction: brainly.com/question/1146642
Level: High school
Subject: Chemistry
Topic: Chemical reactions
Sub-topic: Precipitation reactions
Final answer:
No reaction is expected when (NH4)2S(aq) and SrCl2(aq) are mixed, as solubility rules suggest no insoluble salts will form, leading to NOREACTION.
Explanation:
When (NH4)2S(aq) and SrCl2(aq) are mixed together, we expect a reaction where the cations (NH4+ and Sr2+) and anions (S2- and Cl-) exchange partners if any of them can form an insoluble salt. Looking at solubility rules, we know that most sulfides are insoluble except those of alkali metals and ammonium, and most chlorides are soluble except for Ag+, Pb2+, and Hg22+. Given that neither NH4+ nor Sr2+ forms an insoluble chloride and SrS is not listed as an insoluble sulfide, we can predict that no visible reaction will occur when these solutions are mixed. Therefore, the chemical equation to represent this mixture is NOREACTION.
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Answers
Answer:
Explanation:
From the given information:
The equation for the reaction can be represented as:
The I.C.E table can be represented as:
2SO₂ O₂ 2SO₃
Initial: 14 2.6 0
Change: -2x -x +2x
Equilibrium: 14 - 2x 2.6 - x 2x
However, Since the amount of sulfur trioxide gas to be 1.6 mol.
SO₃ = 2x,
then x = 1.6/2
x = 0.8 mol
For 2SO₂; we have 14 - 2x
= 14 - 2(0.8)
= 14 - 1.6
= 12.4 mol
For O₂; we have 2.6 - x
= 2.6 - 1.6
= 1.0 mol
Thus;
[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,
[O₂] = 1/50 = 0.02 M ,
[SO₃] = 1.6/50 = 0.032 M
Kc = [SO₃]² / [SO₂]² [O₂]
= ( 0.032²) / ( 0.248² x 0.02)
= 0.8325
Recall that; the equilibrium constant for the reaction = 0.8325;
If we want to find:
Then:
Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.
The balanced chemical equation for the reaction between hydrogen sulfide and oxygen is:
2H2S(g) + 3O2(g) =2H2O(l) + 2SO2(g)
We can interpret this to mean:
3moles of oxygen and_______moles of hydrogen sulfide react to produce______moles of water and_______ moles of sulfur dioxide.
Answers
Answer:
1. The coefficients are: 1, 3, 2
2. From the balanced equation, we obtained the following:
3 moles oxygen, O2 reacted.
2 moles of Hydrogen sulfide, H2S reacted.
2 moles of water were produced.
2 moles of sulphur dioxide, SO2 were produced.
Explanation:
1. Determination of the coefficients of the equation.
This is illustrated below:
P2O5(s) + H2O(l) <==> H3PO4(aq)
There are 2 atoms of P on the left side and 1 atom on the right side. It can be balance by putting 2 in front of H3PO4 as shown below:
P2O5(s) + H2O(l) <==> 2H3PO4(aq)
There are 2 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
P2O5(s) + 3H2O(l) <==> 2H3PO4(aq)
Now the equation is balanced.
The coefficients are: 1, 3, 2.
2. We'll begin by writing the balanced equation for the reaction. This is given below:
2H2S(g) + 3O2(g) => 2H2O(l) + 2SO2(g)
From the balanced equation above,
3 moles of oxygen, O2 reacted with 2 moles of Hydrogen sulfide, H2S to produce 2 moles of water, H2O and 2 moles of sulphur dioxide, SO2.
Final answer:
In the balanced chemical equation provided, 3 moles of oxygen react with 2 moles of hydrogen sulfide to produce 2 moles of water and 2 moles of sulfur dioxide.
Explanation:
When the balanced chemical equation 2H2S(g) + 3O2(g) =2H2O(l) + 2SO2(g) is considered, we can deduce that 3 moles of oxygen and 2 moles of hydrogen sulfide react together in this reaction. The products of this chemical reaction are 2 moles of water and 2 moles of sulfur dioxide. Each of these quantities is directly inferred from the coefficients in front of each compound in the balanced chemical equation.