What is the electron pair geometry for a phosphine molecule, PH3? A) tetrahedral B) bent C) linear D) trigonal pyramidal E) none of the above

Answers

Answer 1
Answer:

Final answer:

The electron pair geometry of a phosphine, PH3, molecule is tetrahedral, though the molecule itself takes on a trigonal pyramidal shape due to the presence of a lone pair of electrons on the phosphorus atom.

Explanation:

The electron pair geometry for a phosphine molecule, PH3, is tetrahedral. In PH3, the phosphorus atom is the central atom surrounded by three hydrogen atoms. However, it is important to note that the phosphorus atom also has a lone pair of electrons. The lone pair occupies more space than bonding pairs, causing the molecule to take on a trigonal pyramidal molecular geometry. Despite the molecular geometry, the electron pair geometry is considered tetrahedral because it accounts for all regions of electron density, including lone pairs.

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Answer 2
Answer:

Final answer:

The electron pair geometry for a phosphine molecule (PH3) is tetrahedral. This refers to the spatial arrangement of regions of electron density around the central atom, phosphorus, which is bonded to three hydrogen atoms and has one lone pair of electrons.

Explanation:

The electron pair geometry for a phosphine molecule, PH3, is best described as tetrahedral. Even though the PH3 molecule is not tetrahedral, the electron pair geometry refers to the spatial arrangement of regions of electron density around the central atom, in this case, phosphorus. Phosphorus in the PH3 molecule is bonded to three hydrogen atoms and has one lone pair of electrons. These four regions of electron density adopt a tetrahedral arrangement to minimize electron-electron repulsion. Please note that the molecular structure of PH3 is trigonal pyramidal as lone pairs are not included while determining the molecular geometry.

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The sun warming the surface of a rock is
conduction
convection
radiation

Answers

Radiation..................
Radiation is your answer...

What is shown by a half-reaction?A. oxidation or reduction of an elementB. neutralization of an ion or moleculeC. decomposition of an ion or moleculeD. none of the above

Answers

Answer

A. oxidation or reduction of an element

Explanation

A half reaction can be either oxidation or reduction reaction from a REDOX reaction.

Draw a line-bond structure for CBrN. Explicitly draw all H atoms. You do not have to include lone pairs in your answer. In cases where there is more than one answer, just draw one.

Answers

Answer:

Br - C ≡ N

Explanation:

To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each atom tends to share electrons until it has 8 electrons in its valence shell.

  • C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.
  • Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.
  • N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.

The most stable structure that respects these premises is:

Br - C ≡ N

It does not have any H atom.

How many neutrons does the isotope N-14 have?

Answers

Answer:

7

Explanation:

N-14 has 7

i looked it up ye ur probably gonna get it right

Answer:

7 protons + 7 neutrons!

Explanation:

Identify the sample and analyte in each of the scenarios.(a) Determination of the lead content in paint. lead paint
(b) Analysis of the nitrate content of soil near a local water source. soil nitrate
(c) Measurement of the citric acid found in a lime.

Identify the following as either sample or analyte.
(1) lead
(2) paint chips
(3) soil
(4) nitrate
(5) lime wedge
(6) citric acid

Answers

Answer:

a) Analyte: lead. Sample: paint.

b) Analyte: nitrate. Sample: soil.

c) Analyte: citric acid. Sample: Lime

1) Lead: Analyte.

2) Paint chips: Sample.

3) Soil: Sample.

4) Nitrate: Analyte.

5) Lime wedge: Sample.

6) Citric acid: Analyte.

Explanation:

A sample is a portion of material selected from a larger quantity of material while an analyte is the chemical of the system that will be analysed.

Thus:

a) Analyte is lead while you must take a sample of paint to analyze this lead.

b) Analyte is the nitrate while sample must be soil.

c) Analyte is citric acid and lime is the sample

1) Lead: Analyte.

2) Paint chips: Sample.

3) Soil: Sample.

4) Nitrate: Analyte.

5) Lime wedge: Sample.

6) Citric acid: Analyte.

Consider two aqueous solutions of NaCl. Solution 1 is 4.00 M and solution 2 is 0.10 M. In what ratio (solution 1 to solution 2) must these solutions be mixed in order to produce a 0.86 M solution of NaCl

Answers

Answer:

The ratio of solution 1 to solution 2 is 24.20 to 100.00.

Explanation:

We will mix V₁ (L) of solution 1 with V₂ (L) of solution 2 to get the final solution.

So the mole concentration in the final solution is calculated as below, note that C₁ is the concentration of solution 1, and C₂ is the concentration of solution 2

[M] = (V_(1) C_(1) +V_(2)C_(2))/(V_(1)+V_(2)) = \frac{4 V_(1) + 0.1 V_(2)}_{V_(1)+V_(2)}}=0.86

Then we can calculate for the ratio

(V_(1))/(V_(2))=(0.86-0.10)/(4.00-0.86)  =(0.76)/(3.14) or (24.20)/(100.00)