What are examples of newton's 3 law

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Answer 1
Answer: Newton's First Law Example: Driving a car and hitting something like a tree, the car will stop instantly but you'll keep moving forward. Cars have airbags because of this.

Newton's Second Law Example: It's easier to push a box without anything inside it than a box full of stuff because the box that is full has more mass than the empty one.

Newton's Third Law Example: When air rushes out of a balloon, the opposite reaction is that the balloon will fly around the room.

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A push or pull on an object
If a 2,300 kg car is accelerating at 16 m/s^2, what is the force it is producing?
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Which events are associated with convergent boundaries? Check all that apply. formation of island chains creation of mid-ocean ridges creation of new mountains formation of earthquakes formation of volcanoes

Answers

Answer:

- creation of mid-ocean ridges

-creation of new mountains

-formation of earthquakes

-formation of volcanoes

Convergent boundary plate tectonic involves collisions between oceanic and  continental plates. The thinner and less denser oceanic plate overriden by the thicker and more denser continental plate. The oceanic plate is forced down the mantle, this event is known as subduction. The magma present in the mantle causes melting of subduction plates. The magma enters inside these plates through pores. This magma plate becomes bouyant and moves upwards. The molten magma causes volcanic eruptions along with earthquakes. If the magma solidifies in the subduction zone it creates mid ocean ridges. The mountains are formed near the continents when the magma after volcanic eruption gets cooled and solidified.

All the events are associated with convergent boundaries. Creation of mid-ocean ridges, Creation of new mountains, and formation of earthquakes.

What are convergent boundaries?

A convergent boundary occurs when two or more lithospheric plates clash on Earth. Subduction is the process through which one plate moves beneath the other.

The events are associated with convergent boundaries are;

1 . Creation of mid-ocean ridges

2. Creation of new mountains

3. Formation of earthquakes

4. Formation of volcanoes

Collisions between oceanic and continental plates are involved in convergent boundary plate tectonics. The oceanic plate, which is thinner and less dense, is pushed aside by the continental plate,

Which is thicker and denser. Subduction occurs when an oceanic plate is driven down into the mantle. The melting of subduction plates is caused by magma in the mantle.

The magma seeps into the pores of these plates. This magma plate rises as it gets buoyant. Volcanic eruptions and earthquakes are both caused by molten magma.

Mid-ocean ridges form as magma solidifies in the subduction zone. Mountains are generated near continents as lava cools and solidifies following a volcanic eruption.

To learn more about the convergent boundaries refer to the link;'

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QUESTION IN THE ANSWER!!!!! HELP HELP PLEASE

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Check the combination of the horses, review them, you'll get the answer.

A cat lifting a barbell of 2.5 kg a distance of 3 meters. How much work is done lifting the barbell? How much work is done if the cat holds the barbell over his head for 3 minutes?

Answers


Work = (force) x (distance)

Force = weight of the barbell = (mass) x (gravity) = (2.5 kg) x (9.8 m/s²)

Work = (2.5 x 9.8 newtons) x (3 meters) = 74 newton-meters = 74 joules.

It takes 74 joules to lift the 2.5-kg load 3 meters up off the floor.

After that, as long as the load is held motionless, no more work is done.

5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up aramp inclined to the horizontal by 15.0°. In both cases, you apply a force of 100.N parallel to the
surface (parallel to the floor or parallel to the ramp). Calculate the work done by:
a) the gravitational force as the box is pushed across the flat ground
b) the gravitational force as the box is pushed up the ramp
c) the force you apply as the box is pushed across the flat ground
d) the force you apply as the box is pushed up the ramp

Answers

a) The work done by the gravitational force on the flat surface is zero

b) The work done by the gravitational force on the ramp is -634 J

c) The work done by the applied force on the flat surface is 500 J

d) The work done by the applied force on up along the ramp is 500 J

Explanation:

a)

The work done by a force is given by the equation

W=Fdcos \theta

where

F is the magnitude of the force

d is the dispalcement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.

We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is 90^(\circ); this means that cos 90^(\circ)=0, and therefore, the work done is zero:

W=0

b)

In this case, the box is pushed along the ramp. We have:

F=mg=(50.0)(9.8)=490 N is the magnitude of the force of gravity, where

m = 50.0 kg is the mass of the box

g=9.8 m/s^2 is the acceleration of gravity

d = 5.00 m is the displacement of the box along the ramp

The ramp is inclined to the horizontal by 15.0^(\circ), therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:

\theta=90^(\circ)+15^(\circ)=105^(\circ)

Therefore, the work done by gravity in this case is:

W=(490)(5.00)(cos 105^(\circ))=-634 J

c)

In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.

Here we have:

F = 100.0 N (force applied)

d = 5.00 m (displacement of the box)

\theta=0^(\circ) (the force is applied parallel to the flat surface, therefore force and displacement have same direction)

Therefore, the work done by the force you apply on the flat ground is:

W=(100.0)(5.00)(cos 0^(\circ))=500 J

d)

In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.

This time we have:

F = 100.0 N (force applied is the same)

d = 5.00 m (displacement of the box is also the same)

\theta=0^(\circ) (the force is applied parallel to the ramp, therefore force and displacement have again same direction)

Therefore, the work done by the force you apply while pushing the box along the ramp is:

W=(100.0)(5.00)(cos 0^(\circ))=500 J

Learn more about work:

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Identify and explain the three different ways that charge is built up on an object.

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Answer:

There are three ways to charge an object: friction, conduction and induction. Friction involves rubbing on material with another, resulting in electrons moving from one surface to another. ... Friction is useful for charging insulators, which are materials that aren't good conductors.

Explanation:

How are Newton’s second and third laws of motion important to your everyday life?

Answers

Well, first off, Newtons second law of motion deals with the motion of accelerating and decelerating objects.
 W
e already know that from everyday life examples such as simply pushing a car that if 2 people push a car on a flat road it will accelerate faster than if one person was pushing it... Therefore, there is a relationship between the size of the force and the acceleration.  
 Now onto the third law of motion. First of all, what is the third law of motion? Well, a force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions! According to Newtons third law, whenever one object, and another object interact with each other, they exert forces upon each other. "For every action, there is an equal and opposite reaction."  The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. So, how is this important to everyday life you may ask? 
Well, the action-reaction force pairs are found everywhere in your body.
 For example, right now as I am typing, my tendons are exerting forces on bones, and those bones exert reaction forces on the tendons, as muscles contract, pulling my fingers on the keys. I press on those keys, and they press back on my fingers. See? Since im pressing on the keys, the press back on me. Its opposite from eachother, as stated in the quite above. "
For every action, there is an equal and opposite reaction." 
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 ~I hope this helped :)