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I'm a little bit unsure about this question.

Answers

Answer 1

Answer:

Option C. 4 Hz

Explanation:

To know the correct answer to the question given above, it is important we know the definition of frequency.

Frequency can simply be defined as the number of complete oscillations or circles made in one second.

Considering the diagram given above, the wave passes through the medium over a period of one second.

Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.

From the diagram given above,

The number of circles = 4

Thus,

The frequency is 4 Hz

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The surface tension of a liquid is to be measured using a liquid film suspended on a U-shaped wire frame with an 12-cm-long movable side. If the force needed to move the wire is 0.096 N, determine the surface tension of this liquid in air.

Answers

Answer:

σ = 0.8 N/m

Explanation:

Given that

L = 12 cm

We know that 1 m = 100 cm

L = 0.12 m

The force ,F= 0.096 N

Lets take surface tension = σ

We know that surface tension is given as

$\sigma =(F)/(L)\n\sigma =(F)/(L)\nNow\ by\ putting\ the\ values\n\sigma =(0.096)/(0.12)\ N/m\n\sigma=0.8\ N/m$

Therefore the surface tension σ will be 0.8 N/m .

σ = 0.8 N/m

Final answer:

The surface tension of the liquid in air is 0.8 N/m.

Explanation:

To determine the surface tension of the liquid, we need to use the formula F = yL, where F is the force needed to move the wire, y is the surface tension, and L is the length of the wire. In this case, F = 0.096 N and L = 12 cm. We can rearrange the formula to solve for y: y = F / L. Plugging in the values, we get y = 0.096 N / 0.12 m = 0.8 N/m. So, the surface tension of the liquid in air is 0.8 N/m.

Learn more about Surface tension here:

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When a body falls freely under gravity, then the work done by the gravity is ___________

Answers

Answer: positive

Explanation:

Gravity can be defined as the force with which the body is attracted towards the center of the earth, or towards any other body. If the force acting on the body is in the direction of displacement then the word done by the applicable force is positive. This causes the free fall of the ball under the influence of gravity is also positive.

An ideal gas is at a temperature of 320 K. What is the average translational kinetic energy of one of its molecules

Answers

Answer:

6.624 x 10^-21 J

Explanation:

The temperature of the ideal gas = 320 K

The average translational energy of an ideal gas is gotten as

$K_(ave)$ = $(3)/(2)K_(b)T$

where

$K_(ave)$ is the average translational energy of the molecules

$K_(b)$ = Boltzmann constant = 1.38 × 10^-23 m^2 kg s^-2 K^-1

T is the temperature of the gas = 320 K

substituting value, we have

$K_(ave)$ = $(3)/(2) * 1.38*10^(-23) * 320$ = 6.624 x 10^-21 J

If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

Answers

Answer:

The radius is $R = 0.22 5 \ m$

Explanation:

From the question we are told that

The current is $I = 61 \ A$

The magnetic field is $B = 1.70 *10^(-4) \ T$

Generally the magnetic field produced by a current carrying conductor is mathematically represented as

$B = (\mu_o * I)/(2 * R )$

=> $R = (\mu_o * I )/( 2 * B )$

Here $\mu_o$ is the permeability of free space with value $\mu_o = 4\pi * 10^(-7) N/A^2$

=> $R = ( 4\pi * 10^(-7) * 61 )/( 2 * 1.70 *10^(-4) )$

=> $R = 0.22 5 \ m$

A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats speed relative to the ground

Answers

Answer:

The answer is below

Explanation:

The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:

V² = 56² + 126²

V² = 19012

V = 137.9 m/s

Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.2 s and was brought jarringly back to rest in only 1 s. Calculate his (a) magnitude of acceleration in his direction of motion and (b) magnitude of acceleration opposite to his direction of motion. Express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity. g g

Answers

Answer:

a = 5.53 g , a = -15g

Explanation:

This is an exercise in kinematics.

a) Let's look for the acceleration

as part of rest v₀ = 0

v = v₀ + a t

a = v / t

a = 282 / 5.2

a = 54.23 m / s²

in relation to the acceleration of gravity

a / g = 54.23 / 9.8

a = 5.53 g

b) let's look at the acceleration to stop

va = 0

0 = v₀ -2 a y

a = vi / y

a = 282/2 1

a = 141 m /s²

a / G = 141 / 9.8

a = -15g

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