What is the specific heat value of brass?

Answers

Answer 1
Answer:

Answer:

Nhiệt dung riêng của đồng là  

380

J

/

k

g

.

K

Explanation:

Answer 2
Answer: 0.380 0.092
T4: Specific Heats and Molar Heat Capacities
Substance cp in J/g K cp in cal/g K or Btu/lb F
Aluminum 0.900 0.215
Bismuth 0.123 0.0294
Copper 0.386 0.0923
Brass 0.380 0.092

Related Questions

given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt
Please ignore my answers because they are wrong.
How many molecules are in 4.27 mol of SiH4
How many molecules are in 2.50 moles of co2
15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.60 atm. What is the new volume in liters

Calculate the mass of silver chloride required to plate 265 mg of pure silver.

Answers

Given Mass of pure silver (Ag) = 265 mg

Silver chloride AgCl which is used in plating silver contains 75.27 % Ag

This means that:

A 100 mg of silver chloride contains 75.27 mg of silver

Therefore, the amount of silver chloride required to plate a sample containing 265 mg silver would correspond to:

265 mg Ag * 100 mg AgCl/75.27 mg Ag

= 352.1 mg AgCl

Answer:

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

Explanation:

2AgCl(aq)\rightarrow 2Ag(s)+Cl_2(g)

Mass of silver = 265 mg = 0.265 g

Moles of silver = (0.265 g)/(108 g/mol)=0.002454 mol

According to reaction, 2 moles of silver are obtained from 2 moles of silver chloride.

Then 0.002454 moles of silver will be obtained from :

(2)/(2)* 0.002454 mol=0.002454 mol of silver chloride

Mass of 0.002454 moles of silver chloride:

= 0.002454 mol × 143.5 g/mol = 0.35215 g

0.35215 grams of silver chloride required to plate 265 mg of pure silver.

Given the information about each pair of acids fill in the correct answer. a. Acid A has a lower % ionization than B:_______ is a stronger acid.
b. Acid B has a larger K_a than acid A._______ will have a larger percent ionization.
c. A is a stronger acid than B. Acid B will have________ percent ionization than A.

Answers

Answer:

a. Acid B

b. Acid B

c. lower

Hope this helps you

Jaxson needs to react 16.3 moles of copper (II) nitrate, Cu(NO3)2, in a chemical reaction. How many grams of crystalsdoes he need to weigh out?

Answers

Answer:

3056.25g

Explanation:

Problem here is to find the mass of Cu(NO₃)₂ to weigh out to make for the number of moles.

 Given;

Number of moles  = 16.3moles

Unknown:

Mass of Cu(NO₃)₂ = ?

Solution:

To find the mass of Cu(NO₃)₂, use the expression below;

    Mass of Cu(NO₃)₂ = number of moles x molar mass

Let's find the molar mass;

  Cu(NO₃)₂ = 63.5 + 2[14 + 3(16)]

                    = 63.5 + 2(62)

                    = 187.5g/mol

Mass of  Cu(NO₃)₂ = 16.3 x 187.5  = 3056.25g

One way to experimentally measure the heat capacity of a Styrofoam cup calorimeter would be to melt a known mass of ice in warm water and measure hte temperature change. Use the data below to determine the experimental heat capacity of the calorimeter. Use the literature heat of fusion for ice in your calculations. Assume the ice added is at 0.00 c.Mass of ice added: 17.69gMass of water in calorimeter: 98.67gT-Initial of water: 28.7T-Final of water after melting ice: 12.9C

Answers

Answer:

4.88 Cals per degree celsius

Explanation:

We have taken heat of fusion of ice = 80 cals / g

We have taken speciic heat of water = 1 cal/g per degree celsius

In this experiment ,  let the heat capacity of calorimeter be X.

Heat gained by ice

heat gained in melting + heat gained in getting warmed

= mass x latent heat + mass x specific heat x rise in temperature

= 17.69 x 80 + 17.69 x 1 x ( 12.9 - 0 )

= 1643.4 Cals

Heat lost by water

=  mass x specific heat x fall in temperature

98.67 x 1 x ( 28.77 - 12.9 )

= 1565.89 Cals

Heat lost by calorimeter

heat capacity x fall in temperature

X x ( 28.77 - 12.9 )

Heat gained = heat lost

1643.4 = 1565.89 +15.87X

X = 4.88 Cals per degree celsius

How many subshells in 4s

Answers

Answer:

hhjkjggghjjjjjj

Explanation:

vbjjkkkkkkkj

What is the total number of atoms contained in 2.11 moles of nickel?

Answers

  The  total  number of atoms  contained  in 2.11  moles  of nickel is
1.27 x10^24 atoms

            calculation

By  use of Avogadro  law constant

 
That is   1 mole= 6.02 x10^23  atoms
what  about  2.11  moles of nickel

  by  use of cross  multiplication
[ 2.11  moles  x ( 6.02 x10^23)] / 1 moles = 1.27 x10^24 atoms

1.27 × 10²⁴ atoms of nickel are contained in 2.11 moles of nickel. For every mole of a substance there are 6.022 × 10²³ representative particles of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation

To convert from the number of moles to number of representative particles, the formula below may be used:

\boxed {no. \ of \ particles \ = given \ no. \ of \ moles * (6.022 * 10^(23) \ particles)/(1 \ mole)}

For this problem, the number of nickel atoms can be determined by plugging in the given values in the equation above:

no. \ of \ Ni \ atoms = 2.11 \ mol \ Ni * (6.022 * 10^(23) Ni \ atoms)/(1 \ mol \ Ni)\n\n\boxed {no. \ of \ Ni \ atoms = 1.270642 * 10^(24) \ atoms}

Since the given only has three significant figures, the final answer with the correct number of significant figures is:

\boxed {\boxed {no. \ of \ Ni \ atoms = 1.27 * 10^(24) \ atoms}}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number