Please help me with this im pretty confused ?​
Please help me with this im pretty confused ?​ - 1

Answers

Answer 1
Answer:

Answer:

a=6

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

a^2 + 8^2 = 10^2

a^2 + 64= 100

a^2 +64-64 = 100-64

a^2 = 36

Take the square root of each side

sqrt(a^2) = sqrt(36)

a = 6

Answer 2
Answer:

Answer:

a = 6

  • The length of side a is 6.

Step-by-step explanation:

According to the question,

Using Pythagorean theorem

( a )² + ( b )² = ( c )²

  • Where, a and b are the base and c is the length of hypotenuse.

( a )² + ( 8 )² = ( 10 )²

evaluate the exponent

a ² + 64 = 100

subtract 64 from each side

a ² + 64 - 64 = 100 - 64

a ² = 36

Take the square root of each side

√a² = √36

a = 6


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What is the x-intercept
1/2x - 3y = 8

Answers

so first make it into slope intercept form y=mx+b

1/2x-3y=8
subtract 1/2x from both sides
-3y=8-1/2x
multiply both sides by -1
3y=1/2x-8
divide both sides by 3
y=1/6x-8/3

the x intercept is when y=0
so set y to zero
0=1/6x-8/3
add 8/3 to both sides
8/3=1/6x
multiply both sides by 6
16=x

the x intercept is 16
x intercept is when y = 0
so 1/2 x - 0 = 8
solving for x
1/2 x = 8
multiply both sides by 2
x = 16 is the y intercept

The price of a pair of trousers was decreased by 22% to $30. What was the original price of the trousers?

Answers

Answer:

$38.46

Step-by-step explanation:

It is given that the price of a pair of trousers was decreased by 22% to $30.

Let $x be the original price of the trousers.

22% less of original price is equal to $30.

x-(22)/(100)x=30

x-0.22x=30

0.78x=30

Divide both sides by 0.78.

x=(30)/(0.78)

x\approx 38.46

Therefore, the original price of the trousers is $38.46.

3/4x-2/3=1/6x what number could you multiply both sides of the equation by so that the numbers in the problem are integers and not fractions

Answers

Answer:

12

Step-by-step explanation:

When you multiply both sides of the equation you are multiplying them by the common denominator. In this case, the common denominator is 12. So multiply, then you have the most simplified problem of 2x=9x-8.

I need help with this.

Answers

D
B
A
C
this is the order of what I think is the best answer
Your answer is d. I hope this helped

Two boxes have the same volume. One box has a base that is 5cm by 5cm. The other box has a base that is 10cm by 10 cm. How many times as tall is the box with the smaller base?

Answers

The Box with a smaller base has a height that is 4 times taller than the Box having a larger base.

What is the volume of a cuboid?

We know the volume of a cuboid is the product of its length, breadth, and height or v = l×b×h.

Given, we have two boxes let us denote them by B₁ and B₂ and their respective heights are h₁ and h₂.

To obtain how many times one box is relative to the other we have to equate their respective volumes.

Given, one box has a base that is 10cm by 10 cm and another box has a base that is 5cm by 5cm.

∴ 5×5×h₁ = 10×10×h₂.

25h₁ = 100h₂.

h₁ = 4h₂.

So, h₁ is 4 times taller than h₂.

learn more about cuboid here :

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Answer:

x=4

Step-by-step explanation:

5^2X=10^2X
25X=10X

2X=100/25

Which shows one way to determine the factors of x3 – 9x2 + 5x – 45 by grouping?x2(x – 9) – 5(x – 9)
x2(x + 9) – 5(x + 9)
x(x2 + 5) – 9(x2 + 5)
x(x2 – 5) – 9(x2 – 5)

Answers

x³ - 9x² + 5x - 45

x²(x - 9) - 5(x - 9) ⇒ x³ - 9x² - 5x + 45 INCORRECT
x²(x + 9) - 5(x + 9) ⇒ x³ + 9x² - 5x - 45 INCORRECT

x(x² + 5) - 9(x² + 5) ⇒ x³ + 5x - 9x² - 45 CORRECT
It just needs to be rearranged.

x(x² - 5) - 9(x² - 5) ⇒ x³ - 5x - 9x² + 45 INCORRECT

The answer choice which shows a way to determine the factors by grouping is; x(x² + 5)9(x² + 5).

Which shows one way to determine the factors of x3 – 9x2 + 5x – 45 by grouping?

According to the task content, the factors of the expression are to be determined by grouping.

On this note, one way to group the factors would be;

x³ + 5x - 9x² -45

Upon factorisation;

x(x² + 5) – 9(x² + 5).

Read more on factorisation by grouping;

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