At the local grocery store, you push a 14.5-kg shopping cart. You stop for a moment to add a bag of dog food to your cart. With a force of 12.0 N you now accelerate the cart from rest through a distance of 2.29 m in 3.00 s. What was the mass of the dog food?

Answers

Answer 1
Answer:

Answer:

The mass of the dog food added is 9.03 kg

Explanation:

Given;

mass of the shopping cart, m₁ = 14.5 kg

let the mass of the bag added = m₂

the force applied, F = 12 N

initial velocity of the cart-bag system, u = 0

distance traveled by the system, d = 2.29 m

time of motion of the system, t = 3.0 s

The acceleration of the system is calculated as;

d = ut + (1)/(2) at^2\n\n2.29 = 0 + ((1)/(2) * 3^2)a\n\n2.29 = 4.5 a\n\na = (2.29)/(4.5) \n\na = 0.51 \ m/s^2

The total mass of the system (M) is calculated as follows;

F = Ma

M = F/a

M = (12)/(0.51)

M = 23.53 kg

The mass of the dog food added is calculated as;

m₂ = M - m₁

m₂ = 23.53 kg - 14.5 kg

m₂ = 9.03 kg


Related Questions

If a 78.2 kg kangaroo weighs 6742 N on the planet katar, calculate katar's radius
Which of the following best describes a direct current
If the truck has a mass of 2,000 kilograms, what is its momentum? Express your answer in kg·m/sec.
A 1.0 kg book is lifted 0.5 m above the table , but the table is 1.0 m above the floor , what would be the P.E of the book if the reference level where the floor ?
What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

Which term describes the forces acting on the car? A. inertial B. buoyant C. balanced D. unbalanced

Answers

The answer is unbalanced because the forces actually act on each other.

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary, the tension in the cable was 7000 N {\rm N}. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N {\rm N} drag force.Part AWhat was the tension in the cable when the craft was being lowered to the seafloor?Express your answer to two significant figures and include the appropriate units.Part BWhat was the tension in the cable when the craft was being raised from the seafloor?Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

Explanation:

When the craft was stationary , weight will be balanced by tension

T = mg

T = 7000 N

A)

when the craft was being lowered to the seafloor

drag force will act in upper direction , so

T₁ + 1800 = mg

T₁  = mg - 1800

= 7000 - 1800

= 5200 N

52 X 10² N

B)

when the craft was being raised from the seafloor , Tension will act in downward direction

T₂ = mg+ 1800

T₂  = 7000 - 1800

= 8800N

A ski jumper competing for an Olympic gold medal wants to jump a horizontal distance of 135 meters. Thetakeoff point of the ski jump is at a height of 25 meters. With what horizontal speed must he leave the jump?
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?

Answers

A. We know that the height (h) = 25 m, and the distance (x) = 135 m.

B. We need to find the time flight first (t), then we can find easily the horizontal velocity ( v_(x). )

C. Because this is a projectile motions, so horizontal velocity is constant, but the vertical  velocity is change because of the gravitational acceleration.
So we can use : h = (1)/(2) g t^(2),

Note : Time that will be exist is a time from a land to the takeoff point, that can be called as the time flight.
Then we use, x = v_(x) t, to find the horizontal velocity.

D. We know that :
     h = (1)/(2) g t^(2), so by insert the numbers, and assune that the (g = 10 m/s^(2)), we get that ( t = √(5). )
     After that by using  x = v_(x) t, we can get that v_(x) = 27 √(5)

The centripetal force acting on a satellite in orbit A. acts as an unbalanced force on the satellite.
B. changes the direction of the satellite.
C. is a center-directed force.
D. all of the above

Answers


The centripetal force (of gravity) on a satellite in orbit is an
unbalanced force (because there's no equal force pulling
the satellite away from Earth), changes the direction of the
satellite (into a closed orbit instead of a straight line), and
always acts toward the center of whatever curve the satellite
happens to be on at the moment.

Answer : (D) " all of the above "

Explanation :

The forces acting on a satellite are Earth's gravitational force and centripetal force. The properties of centripetal force acting on a satellite in orbit are as follows :

(1) It acts as an unbalanced force on the satellite. This is due to the reason that there is no same force present which pulls the satellite away from the earth.

(2) It changes the direction of the satellite. The satellite is revolving with a constant speed while the direction is kept on changing (in a circular motion).

(3) Centripetal force always acts towards the center.

So, the correct option is (D) " all of the above "

What type of electron is available to form bonds?

Answers

Answer:

Valence electrons

Explanation:

The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.

The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.

Which of the following is most closely related to the specific heat of a substance?a. its temperature
b. its melting point
c. its amount of heat transferred
d. its rate of change in temperature

Answers

The following that is is most closely related to the specific heat of a substance is its rate of change in temperature. The answer is letter D. The amount of energy required to raise the temperature of 1 kilogram of a substance by 1 Kelvin is called the specific heat. The answer is a. For example, water. Water has a specific heat of 4.18 Joules per kilogram per Kelvin. This means that in order for water to change from one state to the other at one kelvin, it needs 4.18 Joules of energy per one kilogram of water. But it does not apply to changes in phase, because the heat added or removed during a phase change does not change the temperature of a substance.