Study this equation carefully. What classification should this reaction have? Cu + 2AgNO3 Cu(NO3)2 + 2Ag synthesis decomposition single replacement double displacement neutralization

Answers

Answer 1
Answer:

Answer;

-Single replacement

Explanation;

The reaction;

Cu(s) + 2AgNO3= Cu(NO3)2 + 2Ag , is an example of a single replacement reaction.

-It is a type of chemical reaction where an element reacts with a compound and takes the place of another element in that compound.

In the above reaction copper(Cu) takes the place of silver(Ag) in the salt AgNO3 to form Copper (ii) nitrate (CuNO3) and silver metal (Ag).

- Another example of a single replacement reaction occurs when potassium (K) reacts with water (H2O). A colorless solid compound named potassium hydroxide (KOH) forms, and hydrogen gas (H2) is set free.


Answer 2
Answer:

Answer:

single replacement


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The process by which a gas changes to a solid is

Answers

The correct answer to the question is - Deposition i.e the process by which a gas changes to a solid is called deposition.

EXPLANATION:

There are various thermal processes of state or phase change in which matter in one state is converted into matter in another state.

Deposition is the type of thermodynamic process of state or phase change in which a gaseous substance is directly converted into corresponding solid substance without entering into liquid phase.

During this process, the loss of thermal energy from gas is very fast. Hence, the gas directly enters solid phase without undergoing into liquid phase.

This process is just the opposite process of sublimation where a solid is converted into gas directly. That's why this process is also known as desublimation.

For instance, conversion of water vapor into ice.

That process is called deposition.

A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the potential difference across the terminals, (b) the rate Pr of energy dissipation inside the battery and (c) the rate Pemf of energy conversion to chemical form? When the battery is used to supply 56 A to the starter motor, what are (d) V and (e) Pr

Answers

Answer:

Part a)

V = 18.16 V

Part b)

P_r = 345 Watt

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

P_r = 345 Watt

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

\Delta V = E + i r

here we have

E = 12 V

i = 56 A

r = 0.11

now we have

\Delta V = 12 + (0.11)(56) = 18.16 V

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

P_r = i^2 r

P_r = 56^2 (0.11)

P_r = 345 W

Part c)

Rate of energy conversion into EMF is given as

P_(emf) = i E

P_(emf) = (56)(12)

P_(emf) = 672 Watt

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

V = E - i r

V = 12 - (56)(0.11)

V = 12 - 6.16 = 5.84 V

Part e)

now the rate of energy dissipation is given as

P_r = i^2 r

P_r = 56^2 (0.11)

P_r = 345 W

Law of conservation of momentum

Answers

It says that momentum cannot be created or destroyed. Momentum just passes through systems as opposed to just disappearing in thin air. Momentum can be changed to heat or energy.

Hope this helps :)
What is the Law of Conversation of Momentum?
The law of conservation of momentum states that the total momentum of a closed system does not change. This means that when two objects collide the total momentum of the objects before the collision is the same as the total momentum of the objects after the collision. 
Total momentum meansthe momentum of object 1 plus the momentum of object 2.Object 1 might not have the same momentum before and afterthe collisionbut the amount of momentum object 1 gains from the collisionis the same as the amount of momentum object 2 losesso the total momentum remains the same whether the collision is elastic or inelastic.The total momentum is also the same before and after an explosion.

Gamma rays are waves of energy that have no charge.

Answers


Yep.  Just like radio waves, X-rays, and orange light waves.
Gamma rays are exactly the same thing as those, only shorter.

The function ​f(x)equalsnegative 0.25 (x minus 2 )squared plus 8 models the path of a volleyball when the player is 2 feet from the net. The height of the net is 7 ft comma 4 in. Will the ball go over the​ net? What if the player moves back so she is 4 feet from the​ net? Explain.

Answers

Answer:

The ball will go over the net when she's standing 2 feet away from the net, but not at 4 ft from the net

Explanation:

Suppose f(x) = -0.25(x-2)^2 + 8 then when the player is 2ft from the net, we can plug in x = 2:

f(2) = -0.25(2-2)^2 + 8 = 0 + 8ft

As 8 feet > 7 ft 4 in, the ball will go over the net

If the player moves back so that she's 4 feet from the net, plug in x = 4:

f(4) = -0.25(4 - 2)^2 + 8 = -1 + 8 = 7 ft

As 7 ft < 7 ft 4 in, this time the ball will NOT go over the net

Final answer:

The function ​models the path of a volleyball when the player is 2 feet from the net and will the ball go over the net at different distances.

Explanation:

The function f(x) = -0.25(x-2)^2 + 8 models the path of a volleyball when the player is 2 feet from the net. To determine if the ball will go over the net, we need to compare the height of the ball's path with the height of the net.

First, let's convert the height of the net to feet. The height, 7 ft 4 in, is equivalent to 7.33 feet. Now, substitute x = 2 into the function to find the height of the ball when the player is 2 feet from the net. f(2) = -0.25(2-2)^2 + 8 = 8 ft.

The ball will go over the net because the height of the ball, 8 feet, is greater than the height of the net, 7.33 feet.

If the player moves back so she is 4 feet from the net, substitute x = 4 into the function: f(4) = -0.25(4-2)^2 + 8 = 10 ft. The ball would still go over the net, as the height of the ball, 10 feet, is greater than the net's height.

Learn more about volleyball here:

brainly.com/question/18229249

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Describes how a simple machine can make work easier?

Answers

simple machines such as ramps lessen the moment required to do work. if a triangle has a base of 5 and the height  is 7, a ramp would make the hypotenuse of this triangle lessoning the total distance. using a²+b²=c² 25+49=c² 74≈8.6 and it is obvious that 8.6 is less than 12 in every unit. other simple machines such as pulleys make it lighter making it simply easier for an object to be lifted.
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