For the following set of data, find the percentage of data within 2population standard deviations of the mean, to the nearest percent.
58, 77, 31, 54, 58, 54, 56, 58, 56

Answers

Answer 1

Answer:

If the value of the mean is 55.78. Then the standard deviation will be 10.98.

What is a standard deviation?

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The data set is given below.

58, 77, 31, 54, 58, 54, 56, 58, 56.

Then the mean of the data set will be

Mean = (58 + 77 + 31 + 54 + 58 + 54 + 56 + 58 + 56) / 9

Mean = 502 / 9

Mean = 55.78

Then the standard deviation will be

$\rm SD = \sqrt{((58 - 55.78)^2+(77-55.78)^2 + ..... + (56-55.78)^2 )/(9)}\n\nSD = \sqrt { (1085.5)/(9)}\n$

On further solving we have

SD = 10.98

If the value of the mean is 55.78. Then the standard deviation will be 10.98.

More about the standard deviation link is given below.

brainly.com/question/12402189

#SPJ2

Answer 2

Answer:

Answer:

58,+77,+31,+54+,58+,54+,46+,58+,56/9

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