MATHEMATICS COLLEGE

A,B and C are the vertices of a triangle,A has coordinates (4,6)
B has coordinates (2,-2)
C has coordinates (-2,-4)
D is the midpoint of AB.
E is the midpoint of AC.
prove that DE is parallel to BC.

Answers

Answer 1
Answer: SSS (side, side, side)
Answer 2
Answer:

Answer:

SSS (side, side, side)

hope it helps:))!!!

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Cuánto le falta a 3/5para llegar a 9/10

Answers

Answer:

3/10

Step-by-step explanation:

3/5 se puede convertir en 6/10

(3x2)/(5x2).

9/10 - 6/10 = 3/10

le falta 3/10 para llegar a 9/10.

Please help me with this problem

Answers

I think the answer is A. Hope this help
A is the answer
So your welcome

4x<-2 como se desarrolla esta desigualdad

Answers

Answer:

x<-0.5

Step-by-step explanation:

Find the distance between two points A (-2,-3) B (6,8)

Answers

Answer:

√185 units.

Step-by-step explanation:

To find the distance between two points, A (-2, -3) and B (6, 8), you can use the distance formula:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

In this formula:

(x₁, y₁) represents the coordinates of point A (-2, -3).

(x₂, y₂) represents the coordinates of point B (6, 8).

Now, plug the values into the formula:

Distance = √[(6 - (-2))² + (8 - (-3))²]

Distance = √[(6 + 2)² + (8 + 3)²]

Distance = √[(8)² + (11)²]

Distance = √[64 + 121]

Distance = √185

So, the distance between points A (-2, -3) and B (6, 8) is √185 units.

You and a group of friends are going to a five-day outdoor music festival during spring break. You hope it does not rain during the festival, but the weather forecast says there is a 15% chance of rain on the first day, a 10% chance of rain on the second day, a 20% chance of rain on the third day, a 20% chance of rain on the fourth day, and a 60% chance of rain on the fifth day. Assume these probabilities are independent of whether it rained on the previous day or not. What is the probability that it does not rain during the entire festival

Answers

Answer:

Probability that it does not rain during the entire festival = 0.19584

Step-by-step explanation:

We are given that you and a group of friends are going to a five-day outdoor music festival during spring break.

Also, Probability that there may be rain on first day, P(A) = 0.15

Probability that there may be rain on second day, P(B) = 0.10

Probability that there may be rain on third day, P(C) = 0.20

Probability that there may be rain on fourth day, P(D) = 0.20

Probability that there may be rain on fifth day, P(E) = 0.60

It is also provided that these probabilities are independent of whether it rained on the previous day or not.

Now, probability that it does not rain during the entire festival = Probability that there may not be rain on all five days

= (1 - P(A)) * (1 - P(B)) * (1 - P(C)) * (1 - P(D)) * (1 - P(E))

= (1 - 0.15) * (1 - 0.10) * (1 - 0.20) * (1 - 0.20) * (1 - 0.60)

= 0.85 * 0.90 * 0.80 * 0.80 * 0.40 = 0.19584

For a statistics project a community college student at Diablo Valley College decides to investigate cheating in two popular majors at DVC: business and nursing. She selects a random sample of nursing and business courses and convinces the professors to distribute a short anonymous survey in their classes. The question about cheating is one of many other questions about college life. When the student summarizes the data, she finds that 42 of the 50 business students and 38 of the 70 nursing students admitted to cheating in their courses. Can the student proceed with the calculation of the confidence interval for the difference in population proportions?

Answers

Answer:

The student can proceed with the calculation of the confidence interval for the difference in population proportions. This is because, from the data she has, 3/4 of the Business students admitted to cheating while 1/2 of the Nursing students admitted to cheating also.

This is above the average number of students in her given sample size which is valid for extrapolation to the College Majors being investigated.

Step-by-step explanation:
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