18. Given that g(x) = -(x^2)/4, what is the value of g(+8) ?F. -16
G. 4
H. -1
J. 4
K. 16

Answer:

(9,12)

Step-by-step explanation:

Answer:

n = -1                       n = -7

Step-by-step explanation:

5| 2n+8| +3 = 33

Subtract 3 from each side

5| 2n+8| +3-3 = 33-3

5| 2n+8| = 30

Divide by 5

5/5| 2n+8| = 30/5

| 2n+8| = 6

An absolute value equation has two solutions, one positive and one negative

2n+8 = 6              2n+8 = -6

Subtract 8 from each side

2n+8-8=6-8          2n+8-8 = -6-8

2n = -2                    2n = -14

Divide by 2

2n/2 = -2/2            2n/2 = -14/2

n = -1                       n = -7

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Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis

Overall, the steps for algebraically finding the range of a function are:

Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

Find the domain of g(y), and this will be the range of f(x).

If you can't seem to solve for x, then try graphing the function to find the range.

The transformations that took place are;

A: BCDE is rotated 180° counterclockwise to form JKLM.

B: BCDE is rotated 180° clockwise to form PQRS.

What is the transformation that took place?

We can see that the coordinates of Rectangle BCDE are;

B(2, 1); C(2, 2); D(4, 2); E(4, 1)

Now, for Rectangle JKLM, we see that the coordinates are;

J(-2, -1); K(-2, -2); L(-4, -2); M(-4, -1).

Now, for Rectangle PQRS, we see that the coordinates are;

P(-2, 1); Q(-2, 2); R(-4, 2); S(-4, 1).

We see the transformation from BCDE to JKLM as (x, y) → (-x, -y) and this is reflection over the x-axis which is 180° counterclockwise.

Read more about Transformation at; brainly.com/question/4289712

Answer:

actually, its 1 3 and 4 :nerd_emoji:

Step-by-step explanation: