The answer to the question mark the park in a

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Answer 1

Answer: The correct answer is that being a

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for a rankine cycle with one stage of reheat between turbines, there are how many relevant pressures?
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Steam enters a turbine from a 2 inch diameter pipe, at 600 psia, 930 F, with a velocity of 620 ft/s. It leaves the turbine at 12 psia with a quality of 1.0, through an outlet duct 1 ft in diameter. Calculate the turbine power output

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Answer:

$\dot W_(out) = 3374.289\,(BTU)/(s)$

Explanation:

The model for the turbine is given by the First Law of Thermodynamics:

$- \dot W_(out) + \dot m \cdot (h_(in) - h_(out)) = 0$

The turbine power output is:

$\dot W_(out) = \dot m\cdot (h_(in)-h_(out))$

The volumetric flow is:

$\dot V = (\pi)/(4) \cdot \left( (2)/(12)\,ft \right)^(2)\cdot (620\,(ft)/(s) )$

$\dot V \approx 13.526\,(ft^(3))/(s)$

The specific volume of steam at inlet is:

State 1 (Superheated Steam)

$\nu = 1.33490\,(ft^(3))/(lbm)$

The mass flow is:

$\dot m = (\dot V)/(\nu)$

$\dot m = (13.526\,(ft^(3))/(s) )/(1.33490\,(ft^(3))/(lbm) )$

$\dot m = 10.133\,(lbm)/(s)$

Specific enthalpies at inlet and outlet are, respectively:

State 1 (Superheated Steam)

$h = 1479.74\,(BTU)/(lbm)$

State 2 (Saturated Vapor)

$h = 1146.1\,(BTU)/(lbm)$

The turbine power output is:

$\dot W_(out) = (10.133\,(lbm)/(s) )\cdot (1479.1\,(BTU)/(lbm)-1146.1\,(BTU)/(lbm))$

$\dot W_(out) = 3374.289\,(BTU)/(s)$

//This method uses the newly added parameter Club object //to create a CheckBox and add it to a pane created in the constructor //Such check box needs to be linked to its handler class

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Comments on Question

Your questions is incomplete.

I'll provide a general answer to create a checkbox programmatically

Answer:

// Comments are used for explanatory purpose

// Function to create a checkbox programmatically

public class CreateCheckBox extends Application {

// launch the application

public void ClubObject(Stage chk)

{

// Title

chk.setTitle("CheckBox Title");

// Set Tile pane

TilePane tp = new TilePane();

// Add Labels

Label lbl = new Label("Creating a Checkbox Object");

// Create an array to hold 2 checkbox labels

String chklbl[] = { "Checkbox 1", "Checkbox 2" };

// Add checkbox labels

tp.getChildren().add(lbl);

// Add checkbox items

for (int i = 0; i < chklbl.length; i++) {

// Create checkbox object

CheckBox cbk = new CheckBox(chklbl[i]);

// add label

tp.getChildren().add(cbk);

// set IndeterMinate to true

cbk.setIndeterminate(true);

}

// create a scene to accommodate the title pane

Scene sc = new Scene(tp, 150, 200);

// set the scene

chk.setScene(sc);

chk.show();

}

The reservoir pressure of a supersonic wind tunnel is 5 atm. A static pressure probe is moved along the centerline of the nozzle, taking measurements at various stations. For these probe measurements, calculate the local Mach number and area ratio: a. 4 atm; b. 2.64 atm; c. 0.5 atm.

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Answer

Given,

Reservoir pressure of a supersonic wind tunnel = 5 atm

Local Mach number = ?

Area ration = ?

a) 4 atm.

Pressure ratio = $(4)/(5)$

= 0.8

From Isentropic Flow Tables

M = 0.58 A/A* = 1.213

b) 2.64 atm

Pressure ratio = $(2.64)/(5)$

= 0.528

From Isentropic Flow Tables

M = 1 A/A* = 1

c) 0.5 atm

Pressure ratio = $(0.5)/(5)$

= 0.1

From Isentropic Flow Tables

M =2.10 A/A* = 1.8369

An input voltage of 9.2 V is to be converted into its digital counterpart using an analog-to digital converter. The voltage range is 0 to 16 V. The ADC has 4-bit capacity. Determine: (a) What are the number of quantization levels, resolution, and the maximum quantization error of this ADC

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Answer:

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An activated sludge plant is being designed to handle a feed rate of 0.438 m3 /sec. The influent BOD concentration is 150 mg/L and the cell concentration (MLVSS) is 2,200 mg/L. If you wish to operate the plant with a food-to-microorganism ratio of 0.20 day-1 , what volume of aeration tank should you use? Please give your answer in m3 .

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Answer:

Volume of aeration tank = 1.29 x 10^4 m³

Explanation:

Food/Micro- organism Ratio = 0.2/day

Feed Rate (Q) = 0.438 m³/s

Influent BOD = 150 mg/L

MLVSS = 2200 mg/L

The above mentioned parameters are related by the equation

F/M = QS₀/VX

where S₀ is the influent BOD and X is the cell concentration, with V being the Volume of the tank. Re- arranging the above equation for V and putting the values in, we get

V = 0.4380 x 150/0.2 x 2200

V = 0.1493 (m³/s) x day

V = 0.1493 x 24 x 60 x 60

V = 1.29 x 10^4 m³

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Answer:

you too

Explanation:

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