your manager ask you to set up a secure network connection at a remote site which protocol would you use

Answers

Answer 1
Answer:

Answer:

Remote Access Protocols

Explanation:

Considering the situation above, the most appropriate protocol to use is known as the Remote Access Protocol.

This is because Remote Access Protocol is a combination of techniques and sets of instructions that are used in managing the connection between a remote access server and a remote computer. For example, some of the Remote Access Protocols that can be used are Serial Line Internet Protocol, Point-to-Point Protocol, Point-to-Point Protocol over Ethernet, etc.

Hence, given that a trusted Remote Access Protocol allows people to access a steady, secure connection between desktop sharing and remote access for help desk activities.

Therefore, the Remote Access Protocol can be utilized in setting up a secure network connection at a remote site


Related Questions

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How does abstraction help us write programs

Answers

Answer:

Abstraction refines concepts to their core values, stripping away ideas to the fundamentals of the abstract idea. It leaves the common details of an idea. Abstractions make it easier to understand code because it concentrates on core features/actions and not on the small details.

This is only to be used for studying purposes.

Hope it helps!

Selector Next we will write a function that will help us select an output for the chatbot, based on the input it got.
The overall goal of this function is to take a list of words that we got as input, a list of words to check for if they appear in the input outputs to return if something from the list to check is in the input list.
Define a function, called selector.
This function should have the following inputs, outputs and internal procedures:
Input(s)
input_list - list of string
check_list - list of string
return_list - list of string
Output(s):
output - string, or None
Procedure(s):
Initialize output to None
Loop through each element in input_list
Use a conditional to check if the current element is in check_list
If it is, assign output as the returned value of calling the random.choice function on return_list
Also, break out of the loop
At the end of the function, return output Note that if we don't find any words from input_list that are in check_list, output will be returned as None.

Answers

Answer:

See explaination

Explanation:

# Import required the module.

import random

# Define a function selector() which accepts the

# input_list, check_list, and return_list and

# returns a string named output.

def selector(input_list,check_list,return_list):

# Assign None to string variable output.

output=None

# Use for loop to traverse through input_list.

for i in range(len(input_list)):

# Check if element of an input_list is present

# in check_list.

if input_list[i] in check_list:

# Assign a random value from return_list

# to output.

output=random.choice(return_list)

# break out of the loop if input_list

# element is present in check_list.

break

#

return output

# Use assert statement to test a condition.

# If the condition is true, then program continues to

# execute, otherwise raises an AssertionError.

assert callable(selector)

assert selector(['is','in','of'],['of'], ['Yes']) == 'Yes'

assert selector(['is','in'],['of'], ['Yes','No']) == None

# Display the output.

print(selector(['is','in','of'],['of'], ['Yes']))

print(selector(['is','in'],['of'], ['Yes','No']))

Manufactured computers and cell phones are part of which industry? Electronics Chemicals Machinery Metal products

Answers

Answer:

The correct answer is the electronic industry

Hope this helps

Answer:

Electronics

Explanation:

)Which of following can be thrown using the throwstatement?? Error

? Throwable

? Exception

? RuntimeException

? All of Given

? None of given

Answers

Answer:

All of Given

Explanation:

The throw keywords can be used to throw any Throwable object. The syntax is :

throw <Throwable instance>

Note that Error and Exception are subclasses of Throwable while RuntimeException is a subclass of Exception. So the hierarchy is as follows:

Throwable

-- Error

-- Exception

   -- RuntimeException

And all of these are valid throwable entities. As a result "All of Given" is the most appropriate option for this question.

Answer:

The answer is B: throwable

Explanation:

Throwable is the super class of all exceptions

When forced distribution is used to reduce leniency bias, this can cause __________ if a pfp system is in place?

Answers

When forced distribution is used to reduce leniency bias, this can cause <decreased trust> between employees if a pfp system is in place.

Answer:

When forced distribution is used to reduce leniency bias, this can cause (decreased trust between employees) if a pfp system is in place.

Explanation:

Please give me Brainlest!

/* ELEN 1301 Programming Assignment #5. Name : Your name. Student ID : Your student ID #. Due date : Due date Purpose of the program : Finding the average, minimum and maximum values of seven entered numbers. Use iomanip library to show 3 digits below decimal point. Section 1 : Enter the first number. Set min and max variables to the entered number. Section 2 : Enter the next number. If it is smaller than min, replace the min with the entered number. If it is bigger than max, replace the max with the entered number. Section 3 : Repeat section 2 five more times, so that you have seven numbers. Section 4 : Calculate the average of the seven numbers and show the result with 3 digits below decimal point. (2 points) Section 5 : Show the minimum number. (2 points) Section 6 : Show the maximum number. (2 points) */ #include #include using namespace std; int main() { int n1, n2, n3, n4, n5, n6, n7, min, max; double sum = 0; // Write the rest of the program. return 0; } // main

Answers

Answer:

Here is the C++ program:

#include<iostream> //to use input output functions

#include<iomanip> //to use setprecision

using namespace std; //to identify objects cin cout

int main() { //start of main function

     int n1, n2, n3, n4, n5, n6, n7, min, max;  // declare variables for 7 numbers, minimum value and maximum value

     double sum= 0; //declare variable to hold sum of 7 numbers

     double average;  //declare variable to hold average of 7 numbers

     cout<<"Enter first number: "; //prompts user to enter 1st number

     cin>>n1; //reads first number from user

     max = n1; //sets the first number to maximum

     min=n1; //sets the first number to minimum

     cout<<"Enter second number: "; //prompts user to enter 2nd number

     cin>>n2; //reads second number from user

     if(n2<min){ //if second number is less than min

          min=n2;      } //sets min to n2

     if(n2>max){ //if n2 is greater than max

          max = n2;      } //sets max to n2

     cout<<"Enter third number: ";  //prompts user to enter 3rd number

     cin>>n3; //reads third number from user

     if(n3<min){ //checks if n3 is greater than min

          min=n3;      } //sets n3 to min

     if(n3>max){ //checks if n3 is greater than max

          max = n3;      }      //sets max to n3

    cout<<"Enter fourth number: ";//prompts user to enter 4th number

     cin>>n4; //reads fourth number from user

     if(n4<min){  //if n4 is less than min

          min=n4;      }  //sets min to n4

     if(n4>max){  //if n4 is greater than max

          max = n4;      }  //sets max to n4

     cout<<"Enter fifth number: "; //prompts user to enter 5th number

     cin>>n5; //reads fifth number from user

     if(n5<min){  //if n5 is less than min

          min=n5;     }  //sets min to n5

     if(n5>max){  //if n5 is greater than max

          max = n5;      }  //sets max to n5

     cout<<"Enter sixth number: "; //prompts user to enter 6th number

     cin>>n6; //reads sixth number from user

     if(n6<min){ // if n6 is less than min

          min=n6;      }  //sets min to n6

     if(n6>max){  //if n6 is greater than max

          max = n6;      }  //sets max to n6

     cout<<"Enter seventh number: ";//prompts user to enter 7th number

     cin>>n7; //reads seventh number from user

     if(n7<min){  //if n7 is less than minimum number

          min=n7;      }  //assigns n7 to min

     if(n7>max){  //if n7 is greater than the maximum number

          max = n7;      }  //assigns n7 to max

     sum = n1+n2+n3+n4+n5+n6+n7;  //adds 7 numbers

     average = sum/7;  //computes average of 7 numbers

     cout<<"The average is: "<<fixed<<setprecision(3)<<average<<endl; //displays average value up to show 3 digits below decimal point using setprecision method of iomanip library

     cout<<"The maximum number is: "<<max<<endl; //displays maximum number of 7 numbers

     cout<<"The minimum number is: "<<min<<endl;  //displays miimum number of 7 numbers    

     return 0; }

Explanation:

The program is well explained in the comments attached to each statement of program. For example if

n1 = 3

n2 = 9

n3 = 7

n4 = 6

n5 = 2

n6 = 5

n7 = 4

When n1 is read using cin then this number is set to max and min as:

min = 9

max = 3

Now when n2 is read, the first if condition checks if n2 is less than min and second if condition checks if n2 is greater than max. As n2 = 9 so it is not less than min so this if condition is false and n2 is greater than max i.e. 3 so this condition is true. So 9 is assigned to max.

min = 9

max = 9

Now when n3 is read the values of min and max become:

min = 7

max = 9

Now when n4 is read the values of min and max become:

min = 6

max = 9

Now when n5 is read the values of min and max become:

min = 2

max = 9

Now when n6 is read the values of min and max become:

min = 2

max = 9

Now when n7 is read the values of min and max become:

min = 2

max = 9

Now the statement       sum = n1+n2+n3+n4+n5+n6+n7;

executes which becomes:

sum = 3 + 9 + 7 + 6 + 2 + 5 + 4

sum = 36.0

Next program control moves to statement:

average = sum/7;

this becomes

average = 36/7

5.142857

Since this is to be displayed up to 3 decimal places so average = 5.143

the complete output of the program is attached.