A ball is dropped form a height of 100 inches. The ball bounces, each time reaching a lower and lower height. The height of each bounce is 75% of the previous bounce. What height will the ball reach after bouncing four times? How many bounces does it take for the ball to reach a height of less than one inch?

Answers

Answer 1
Answer: After the 'n'th bounce, the ball returns to a maximum height of

               (100) times (0.75)^n .

-- After 4 bounces, the maximum height is (100) (0.75)^4 = 31.64 inches.

-- To look for the maximum height of 1 inch,     (100) (0.75)^x = 1

Let's take the log of each side:    log(100) + x log(0.75) = 0

Subtract  log(100)  from each side:      x log(0.75) = -log(100)

Divide each side by  log(0.75) :            x  =  -log(100) / log(0.75).

log(100) = 2 .  So ...    x = -2 / log(0.75)  =  -2 / -0.124939  =  16.00785    

So the ball returns to a slim hair more than 1 inch high on the 16th bounce,
and returns to definitely less than 1 inch high on the 17th bounce.
Answer 2
Answer: 75% of a number is as much as 3/4 of the same number, so:

1st bounce: 3/4 * 100 = 75
2nd bounce: 3/4 * 75 = 56,25
3rd bounce: 3/4 * 56,25 = 42,1875
4th bounce: 3/4 * 42,1875 = 31,640625
5th bounce: 3/4 * 31,640625 = 23,73046875
6th bounce: 3/4 * 23,73046875 = 17,7978515625
7th bounce: 3/4 * 17,7978515625 = 13,348388671875
8th bounce: 3/4 * 13,348388671875 = 10,01129150390625
9th bounce: 3/4 * 10,01129150390625 = 7,508468627929688
10th bounce: 3/4 * 7,508468627929688 = 5,631351470947266
11th bounce: 3/4 * 5,631351470947266 = 4,223513603210449
12th bounce: 3/4 * 4,223513603210449 = 3,167635202407837
13th bounce: 3/4 * 3,167635202407837 = 2,375726401805878
14th bounce: 3/4 * 2,375726401805878 = 1,781794801354408
15th bounce: 3/4 * 1,781794801354408 = 1,336346101015806
16th bounce: 3/4 * 1,336346101015806 = 1,002259575761855
17th bounce: 3/4 * 1,002259575761855 = 0,7516946818213909

Answers:
 
After bouncing four times, the ball will reach a height of 31,640625 inches.
The ball will reach a height of less than one inch after 17 bounces.

PS: I know it's kind of a walk-around, by it still gives us the answer :)

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Answers

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A fruit company delivers its fruit in two types of boxes : large and small. A delivery of 6 large boxes and 5 small boxes has a total weight of 190 kilograms. A delivery of 2 large boxes and 3 small boxes has a total of 84 kilograms. How much does each type of boxes weigh ?

Answers

4 large and 8 small weigh 113kg 
so 
2 large and 4 small weigh 56.5 kg 
but 
2 large and 3 small weigh 50 kg 
so taking the difference 
1 small weighs 56.5 - 50 = 6.5 kg. 

Substitute : 
2 large and 3 small weight 50 kg 
2 large weigh 50 - 3*6.5 = 50 - 19.5 = 30.5 kg 
1 large weighs 15.25 kg

We  have  this  system

6L  +  5S   =  190       (1)

2L  +  3S   =   84     multiply  through  by -3  ⇒ -6L  - 9S   = -252   (2)

Add  (1)  and (2)    and  we  get  that

-4S   =  -62

S = -62  / -4     =   15.5  kilos  for  a small box  

And

2L  +  3S  =  84

2L  + 3 (15.5)  =  84

2L  =  46.5   =  84

2L  =  84  - 46.5

2L  = 37.5

L = 37.5 /2    =  18.75  kilos  for a large box

Which is bigger 31/100 or 5/10

Answers

♥ Solve:
31/100
50/100
50 is larger than 31
Therefore 5/10 is larger than 31/100
31/100
5/10=50/100

Is 50 bigger than 31? Yes.

5/10>31/100

2x+5y=16 -5x-2y=2
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Answers

Answer:

(x,y) = (-2,4)

Step-by-step explanation:

We have two equations:

(1).\:2x+5y=16\n(2).-5x-2y=2

Now let us us multiply equation (1) by 5, and equation (2) by 2:

(1).\:5(2x+5y=16)\rightarrow\:10x+25y=80\n\n(2).2(-5x-2y=2)\rightarrow\:-10x-4y=4

and add the two equations to get:

21y=84

\boxed{y=4}

Now we put this value of y into equation(1) and solve for x :

2x+5(4)=16

2x=-4

\boxed{x=-2}

Thus the solution to our system of equations is

\boxed{(x,y)=(-2,4)}

Answer:

Make sure that you enter just (-2,4)

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Answers

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8
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Part B
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Answers

Given:
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2/8 cups of blueberries * 6 drinks = 2/8 * 6 = (2*6)/8 = 12/8 cups of blueberries

30/8 + 12/8 = 42/8 cups of banana slices and blueberries

Part B
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