a sample of copper wire with a mass of 1.659 g is heated with excess powdered sulfur until the copper has combined with the sulfur, and all the extra sulfur has been burned off. The final product (a sulfide of copper ) has a mass of 2.080 g. Calculate the empirical formula of the product, and name it.

Answers

Answer 1
Answer: Copper mass = 1.659
Copper moles = 1.659 / 64 = 0.0259

Sulfur mass = 2.08 - 1.659 = 0.421
Sulfur moles = 0.421  / 32 = 0.0131

Ratio Copper : Sulfur = 2 : 1

Empirical formula: Cu ₂ S
Name: Copper (I) sulfide

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When the pressure exerted on a confined gas at constant temperature is doubled, the volume of the gas is

Answers

When the pressure exerted on a confined gas at a constant temperature is doubled, the volume of the gas is halved. I answer to your question is 'halved'. I hope this helps you on your assignment.

Answer: When the pressure exerted on a confined gas at constant temperature is doubled, the volume of the gas is halved.

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas = p

V_1 =  initial volume of gas = v

P_2 = final pressure of gas= 2p

V_2 = final volume of gas = ?

Putting values in above equation, we get:

p* v=2p* V_2

V_2=(v)/(2)

Thus the final volume of the gas is half of the initial volume.

A sample of gas confined in a cylinder with a movable piston is kept at constant pressure. The volume of the gas doubles when the temperature of the gas is changed from(1) 400. K to 200. K (3) 400.°C to 200.°C
(2) 200. K to 400. K (4) 200.°C to 400.°C

Answers

When the pressure is constant, the temperature and volume of the gas has ratio relationship: V1/T1= V2/T2. And the temperature using unit of K. Then we can get the answer is (2) 200 K to 400 K.

The chemical equation for the combustion of acetylene (C2H2) is given below.mc021-1.jpg

What volume of oxygen at STP is required for the complete combustion of 100.50 mL of C2H2?
201 mL
201.00 mL
251 mL
251.25 mL

Answers

Answer:

                251.25 mL of O

Solution:

The balance chemical equation is as follow,

                             2 C₂H₂  +  5 O₂     →     4 CO₂  +  2 H₂O

As we know if the gas is acting ideally then 1 mole of any gas at standard temperature and pressure it will occupy exactly 22.4 L or  22400 mL of volume.

Keeping this in mind according to equation,

     44800 mL (2 mol) of C₂H₂ required  =  112000 mL (5 mol) of O₂

So,

                    100.50 mL of C₂H₂ will require  =  X mL of O₂

Solving for X,

                      X =  (100.5 mL × 112000 mL) ÷ 44800 mL

                      X  =  251.25 mL of O

The balanced reaction would be:

C2H2 + 5/2O2 = 2CO2 + H2O

We are given the amount of acetylene in the reaction. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(.1005 L) / (0.08206 atm L/mol K ) 273.15 K
n= 4.4837 x 10^-3 mol C2H2

4.4837 x 10^-3 mol C2H2 (5/2 mol O2/ 1 mol C2H2) = 0.0112 mol O2

V = nRT/P = 
0.0112 mol O2 x 273.15 K x 0.08206 atm L/mol K / 1 atm
V=0.25125 L or 251.25 mL

Distillation is used to separate _____.a. heterogeneous mixtures
b. suspensions
c. colloids
d. solutions

Answers

Distillation is the process of separating homogeneous mixtures -and  a solution is a homogenous mixture, so this is the correct answer!

A homoogeneous mixture is a mixture in which the elements are mixed so well, that the mixture has a similar composition in all its parts. A heat can be applied to this mixture then to separate the parts - this is destination!

The answer is A) heterogeneous mixtures, look up how a heterogeneous mixture is separated and it will tell you distillation. Have a nice day and good luck on the rest of your work

Which statement best describes the process of making a solution by diluting a stock solution?

Answers

A concentrated solution

Which two characteristics are associated with metals?(1) low first ionization energy and low electronegativity
(2) low first ionization energy and high electronegativity
(3) high first ionization energy and low electronegativity
(4) high first ionization energy and high electronegativity

Answers

Answer:

low first ionization energy and low electronegativity

Explanation:

Final answer:

Metals are typically characterized by low first ionization energy and low electronegativity. This is because metals can easily lose electrons to become positive ions and do not attract electrons strongly.

Explanation:

Two properties that are typically associated with metals are low first ionization energy and low electronegativity. Therefore, the correct option is (1).

Ionization energy is the energy required to remove an electron from an atom. Metals have low first ionization energy because they can easily lose an electron to become positive ions. Electronegativity is a measure of the ability of an atom to attract electrons. Metals have low electronegativity because they do not attract electrons strongly.

Learn more about Metals here:

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