What forms when iron-53 decays?

Answers

Answer 1

Answer:

Iron-53 is a radioactive isotope of iron. It undergoes radioactive decay in order to become more stable. The process of radioactive decay involves the emission of particles or radiation from an unstable nucleus, resulting in a more stable form of the original element.

What happens when it goes through the radioactive decay ?

When iron-53 undergoes radioactive decay, it is transformed into an isotope of manganese. Specifically, it decays into manganese-53, which is a stable isotope of manganese.

This process of decay is known as beta decay, and it involves the emission of an electron (a beta particle) and a neutrino from the nucleus of the iron-53 atom. This causes the iron-53 atom to become a manganese-53 atom, which is more stable than the original iron-53 atom.

The process of radioactive decay is an important part of the natural decay of elements. It is a natural process that occurs in nature and is not caused by human activity.

Radioactive decay is responsible for the formation of many elements in nature, and it is also responsible for the formation of many of the elements that are used in everyday life.

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Answer 2

Answer: It depends on the type of decay that is taking place if its a β+ it will decay into Mn-52 β- decays into Co-59

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State and explain the trends in the atomic radius and ionization energy for elements Li to Cs.

Answers

Explanation:

ionisation energy decrease down the group as the atomic radius increases. Nuclear charge increases. Number of shell increases so the electron will experience more shielding so it would be easier for the atom to loss electron.

Final answer:

The atomic radius increases as you move down a group from Li to Cs, while the atomic radius generally decreases as you move across a period from Li to Cs. The ionization energy decreases down a group and increases across a period.

Explanation:

The atomic radius is the size of an atom, while ionization energy is the energy required to remove an electron from an atom. In general, as we move down a group from Li to Cs, the atomic radius increases due to the addition of more energy levels. This is because the electrons occupy higher energy orbitals farther away from the nucleus. On the other hand, as we move across a period from Li to Cs, the atomic radius generally decreases. This is because the effective nuclear charge increases, pulling the electrons closer to the nucleus.

Regarding ionization energy, it generally decreases down a group from Li to Cs. This is because the atomic radius increases, therefore making it easier to remove an electron from a larger, higher energy orbital. Conversely, as we move across a period, the ionization energy generally increases. This is because the atomic radius decreases, and the electrons are held more tightly by the increasing nuclear charge.

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How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol.4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)

Answers

First, convert the amount of KNO3 to moles using the molar mass:
58.6 g / 101.11 g/mol = 0.5796 mol KNO3

Next, using the given balanced reaction, use the stoichoimetric ratio to calculate the number of mole of oxygen that will be produced. From the reaction, for every 4 moles of KNO3 that decomposes, there are 5 moles of O2 formed. So,
0.5796 mol KNO3 x (5/4) = 0.7254 moles O2

Therefore, when 58.6 g of KNO3 decomposes, there are 0.7254 moles of O2 that will be formed.

The moles of oxygen formed when 58.6 g of KNO3 decomposes is $\boxed{{\text{0}}{\text{.7245moles}}}$

Further Explanation:

Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between the reactants and products. It can be used to determine the moles of a chemical species when the moles of other chemical species present in the reaction is given.

Consider the general reaction,

${\text{A}}+2{\text{B}}\to3{\text{C}}$

Here,

A and B are reactants.

C is the product.

One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.

The given reaction is,

${\text{4KN}}{{\text{O}}_3}\left(s\right)\to2{{\text{K}}_2}{\text{O}}\left(s\right)+2{{\text{N}}_2}\left(g\right)+5{{\text{O}}_2}\left(g\right)$

 On reactant side,

Number of potassium atoms is 4.

Number of nitrogen atom is 4.

Number of oxygen atoms is 12.

 On the product side,

Number of potassium atoms is 4.

Number of nitrogen atom is 4.

Number of oxygen atoms is 12.

The number of atoms of all the species in both the reactant and the product side is the same. So above reaction is balanced. The stoichiometry of the balanced reaction indicates that 4 moles of ${\text{KN}}{{\text{O}}_3}$ decompose to give 2 moles of ${{\text{K}}_2}{\text{O}}$ to form 2 moles of ${{\text{N}}_2}$ and 5 moles of ${{\text{O}}_2}$ .

The formula to calculate the number of moles of ${\mathbf{KN}}{{\mathbf{O}}_{\mathbf{3}}}$ is as follows:

${\text{Moles of KN}}{{\text{O}}_3}=\frac{{{\text{Given mass of KN}}{{\text{O}}_3}}}{{{\text{Molar mass of KN}}{{\text{O}}_3}}}$ …… (1)

The given mass of is 58.6 g.

The molar mass of is 101.11 g/mol.

Substitute these values in equation (1)

$\begin{gathered}{\text{Moles of KN}}{{\text{O}}_3}{\mathbf{=}}\left({58.6\;{\text{g}}}\right)\left({\frac{{{\text{1}}\;{\text{mol}}}}{{{\text{101}}{\text{.11}}\;{\text{g}}}}}\right)\n=0.5796\;{\text{mol}}\n\end{gathered}$

According to the stoichiometry, 4 moles of ${\text{KN}}{{\text{O}}_3}$ decompose to give 2 moles of ${{\text{K}}_2}{\text{O}}$ , 2 moles of {{\text{N}}_2} and 5 moles of ${{\text{O}}_2}$ .

So the number of moles of {{\mathbf{O}}_{\mathbf{2}}} formed by 0.5796 moles of ${\mathbf{KN}}{{\mathbf{O}}_{\mathbf{3}}}$ is calculated as follows:

$\begin{gathered}{\text{Moles of }}{{\text{O}}_2}{\mathbf{=}}\left({\frac{{5\;{\text{mol}}}}{{4\;{\text{mol}}}}}\right)*\left({0.5796\;{\text{mol}}}\right)\n=0.7245\;{\text{mol}}\n\end{gathered}$

Hence, the moles of ${{\mathbf{O}}_{\mathbf{2}}}$ produced is 0.7245 moles.

Learn more:

1. Bond energy of H-H bond in the given reaction: brainly.com/question/7213980

2. What coefficients are required to balance equation: brainly.com/question/1971314

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mole concept

Keywords: stoichiometry, KNO3, K2O, O2, N2, moles, A, B, C, molar mass, reactants, products, 0.5796 moles, 0.7245 moles, potassium, oxygen and nitrogen.

The _____ agent is the substance in a redox reaction that accepts electrons.B. oxidizing
C. buffering
D. half-reaction

Answers

B. oxidizing

In the reaction the oxidizing agent is reduced.

the answer is oxidizing look it up

Also i took the test

What was the main reason the Federalists wantedto replace the Articles of Confederation?
(1) The president did not have the power to veto
legislation.
(2) The legislative branch enacted an unfair tax
program.
(3) The Supreme Court refused to pay
Revolutionary War debts.
(4) The national government was too weak to
solve the nation’s problems.

Answers

Answer : Option 4) The national government was too weak tosolve the nation’s problems.

Explanation : The main reason for the Federalists wanted to replace the Articles of Confederation because they believed that the structure the Articles which were laid out did not provided enough power for the federal government to effectively solve the nation's problems. It projected the image of the federal government being weak for solving nation's problem.

The national government was too weak to solve the nation's problems.

The Articles of Confederation were only meant to be temporary, like a stand in, until a better document, eventually known as the constitution, could be created.

Why should hypothesis be testable?

Answers

Answer:

D. It must be testable in order to be found true or false.

APEX

When a hypothesis is testable, it means that it's possible to see whether the prediction is true or not. Testing a hypothesis can include conducting experiments, collecting data and making observations.

Why aliminium is use in manufacturing aeroplanes

Answers

Answer: Aluminum is ideal for aircraft manufacture because it's lightweight and strong.

Explanation:

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