A pole that is 2.9m tall casts a shadow that is 1.32m long. at the same time, a nearby tower casts a shadow that is 37.75m long. how tall is the tower? round your answer to the nearest meter.

Answers

Answer 1
Answer: (2.9)/(1.32)   = (x)/(37.75)

x = 82.93 m

Nothing to deal with physics.
Maths. Scale factor. Year 9.

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An "E" tuning fork with a frequency of 329 Hz is used to test the "E" note of a piano. Four beats are heard. This means _____.The piano key is in tune.
The piano key is out of tune and has a frequency of 333 Hz.
The piano key is out of tune and has a frequency of 325 Hz.
The piano key is out of tune and has a frequency of either 325 or 333 Hz

Answers

The correct choice is

The piano key is out of tune and has a frequency of either 325 or 333 Hz

Beat frequency has been given as 4 Hz. hence the frequency must be above or below the given frequency of 329 Hz by 4 Hz. To get the upper level of frequency we add the beat frequency to the given frequency. To get the lower level, we subtract the beat frequency from the given frequency

f' = 329 + 4 = 333 Hz

and

f'' = 329 - 4 = 325 Hz

The piano key is out of tune and has a frequency of either 325 or 333 Hz

What alternative source of energy do people in your locality use write the purpose of that source

Answers

Answer:

the sun is the main sourse of energy

Explanation:

it can be use to save eco system

there will be no pollution

there will be no harmful gases

What is the wobble method primarily used for in astronomy? A) Detecting comets B) Detecting asteroids C) Detecting extrasolar planets D) Detecting black holes

Answers

The answer is D) detecting extrasolar planets

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length λCalculate the electric field
(a) At any point between the cylinders a distance r from the axis and
(b) At any point outside the outer cylinder.
(c) Graph the magnitude of the electric field as a function of the distance r from the axis of the cable, from r = 0 to r = 2c.
(d) Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.

Answers

Answer:

Part a)

E = (\lambda)/(2\pi \epsilon_0 r)

Part b)

E = (\lambda)/(2\pi \epsilon_0 r)

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

\int E. dA = (q)/(\epsilon_0)

E. 2\pi rL = (\lambda L)/(\epsilon_0)

E = (\lambda)/(2\pi \epsilon_0 r)

Part b)

Outside the outer cylinder we will again use Guass law

\int E. dA = (q)/(\epsilon_0)

E. 2\pi rL = (\lambda L)/(\epsilon_0)

E = (\lambda)/(2\pi \epsilon_0 r)

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Final answer:

The electric field between the cylinders is given by E = λ / (2πε₀r). The electric field outside the outer cylinder is zero due to the absence of net charge. Graph the electric field magnitude using the equation E = λ / (2πε₀r). The inner surface charge of the outer cylinder is -λ and the outer surface charge is 0.

Explanation:

To calculate the electric field between the cylinders at a distance r from the axis, you can use Gauss's Law. Since the charging is uniform, the electric field will also be uniform. Therefore, the electric field at any point between the cylinders is given by E = λ / (2πε₀r), where ε₀ is the permittivity of free space.

To calculate the electric field at any point outside the outer cylinder, you can use the principle of superposition. The electric field due to the outer cylinder is zero because it has no net charge. The electric field due to the inner cylinder can be calculated using the same formula as before.

To graph the magnitude of the electric field as a function of the distance r from the axis, you can plot the equation E = λ / (2πε₀r) for values of r ranging from 0 to 2c.

The charge per unit length on the inner surface of the outer cylinder is -λ, while the charge per unit length on the outer surface of the outer cylinder is 0. This is because the outer cylinder has no net charge and the inner cylinder has a uniform positive charge per unit length λ.

Learn more about Electric Field here:

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calculate the area that will experience a force of 6000N from liquid exerting pressure of 300Pa. 1kPa=1000Pa​

Answers

Answer:

A=20\ m^2

Explanation:

Pressure

Is a measure of how much force is applied perpendicular over a given area.

It is calculated by dividing the amount of force being applied F by the area over which it is being applied A:

\displaystyle P=(F)/(A)

The SI unit for pressure is the Pascal (Pa), equivalent to 1\ Nw/m^2

A pressure of 300 Pa is being exerted over an area that experiences a force of 6000 N. We are required to calculate the value of the area.

If we know the pressure and the force, we solve the above equation for A;

\displaystyle A=(F)/(P)

Substituting the given values:

\displaystyle A=(6000)/(300)

\mathbf{A=20\ m^2}

What is the largest speed this projectile can have without causing the cable to break?

Answers

What projectile ?
What cable ?