WHAT IS THE SLOPE OF THE LINE6X + 3Y = 18?
Can anyone actually help me work it out please
Answers
Answer:
3y=6x=18 the equation must look like this y=mx+b where m is the slope in this case it is 2 and b is the y-intercept 18 hope it helps
just divide every term by 3 to isolate y
Related Questions
Find the quotient and remainder using long division.x + x - 13 x - 2 The quotient is The remainder is
Which best describes her prediction?
The lines shown below are parallel. If the green line has a slope of -1/2, what is the slope of the red line? A.2B.-C.-2D.
Off the production line, there is a 4.6% chance that a candle is defective. If the company selected 50 candles off the line, what is the standard deviation of the number of defective candles in the group?
7°F. By the next morning, the temperature had risen to
–
1°F.
What was the change in temperature during the sleepover?
Answers
The change in temperature during Lena's sleepover was 6°F. It can therefore be said that the temperature rose by 6°F during the sleepover.
How do we calculate the change in temperature?
To find the change in temperature, subtract the initial temperature from the final temperature, in other words, Subtract the temperature on Friday night from the temperature on Saturday morning.
Change in temperature = Final temperature - Initial temperature
Change in temperature = (−1°F) - (−7°F)
Change in temperature = −1 + 7
Change in temperature = 6°F
So, the temperature rose by 6°F during the sleepover.
Find more exercises on temperature change;
#SPJ3
Answer:
6F
Step-by-step explanation:
Answers
Answer:
a. The biomass weighs 2.30 * 10^7 kg after a year
b. It'll take 2.56 years to get to 4*10^7kg
Step-by-step explanation:
a.
k = 0.78,K = 6E7 kg
Given
dy/dt = ky(1- y/K)
Make ky dt the subject of formula
ky dt = dy/(1-y/K) --- make k dt the subject of formula
k dt = dy/(y(1-y/K))
k dt = K dy / y(K-y)
k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides
kt + c = ln(y/(K-y))
Ce^(kt) = y/(K-y)
Substitute the values of k and K
Ce^(0.78t) = y/(6*10^7 - y) ----- (1)
Given that y(0) = 2 * 10^7kg
(1) becomes
Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)
Ce° = (2*10^7)/(4*10^7
C = 2/7
Substitute 2/7 for C in (1)
2/7e^0.78t = y/(6*10^7 - y) ---(2)
We're to find the biomass a year later
So, t = 1
2/7e^0.78 = y/(6*10^7 - y)
0.62 = y/(6*10^7 - y)
y = 0.62(6*10^7 - y)
y = 0.62*6*10^7 - 0.62y
y + 0.62y = 0.62*6*10^7
1.62y = 0.62*6*10^7
1.62y = 3.72 * 10^7
y = 2.30 * 10^7kg.
Hence, the biomass weighs 2.30 * 10^7 kg after a year
b.
Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg
Substitute 4*10^7 for y in (2)
2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)
2/7e^0.78t = 4*10^7/2*10^7
2/7e^0.78t = 2
e^0.78t = (2*7)/2
e^0.78t = 2
t = 2 * 1/0.78
t = 2.56 years
Hence, it'll take 2.56 years to get to 4*10^7kg
Answers
Answer:
Hope you understand my writing!
rolling a multiple of 3
rolling an odd number
rolling a number greater than 6
Find each probability of
P(5)
P(# less than 3)
P(odd)
P(13)
Answers
Answer:
1/12 , 1/3 , 1/2 , 1/2
Step-by-step explanation:
P(x) = favorable of x / total
plug in your conditions and you get the probablility
Answer:
1/12 for rolling a 5.
4/12 for multiples of 3. (3,6,9,12)
6/12 for rolling an odd number.(1,3,5,7,9,11)
6/12 for rolling a number greater than 6. (7,8,9,10,11,12)
Step-by-step explanation:
take for the tub to overflow if both the faucet and drain were open at the
same time?
Answers
Answer:
20
Step-by-step explanation:
Knowing that it is a 30-gallon bathtub.
And it fills at a rate of 3 gallons per minute.
But also drains 1.5 gallons per minute.
So this is for the first minute.
3 - 1.5 = 1.5
So there will be 1.5 gallons of water in the tub after the first minute.
Now do,
30 ÷ 1.5 = 20
It will take 20 full minutes for the bathtub to fill up.
Answers
Answer:
10
Step-by-step explanation: