The reaction below demonstrates which characteristic of a base?CuSO4(aq)+2NaOH(aq)->Cu(OH)2(s)+Na2SO4
the ability of bases to release sodium ions into solution
the ability of bases to release hydrogen ions into solution
the ability of a base to react with carbonate or bicarbonate
the ability of a base to react with a soluble metal salt

Answers

Answer 1
Answer: I think the correct answer from the choices listed above is the last option. The reaction below demonstrates a characteristic of base which is the ability of a base to react with a soluble metal salt. Hope this answers the question. Have a nice day.
Answer 2
Answer: In the reaction of the type: 
           CuSO4(aq)   +   2NaOH(aq)  ->   Cu(OH)2(s)   +   Na2SO4

Herein, base (NaOH) reacts with water soluble metal salt (CuSO4) to form metal hydroxide.

This displays 
ability of a base to react with a soluble metal salt. Hence correct answer is option D

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Which of the following species has the greatestnumber of electrons?
1. Cl1−
2. Co4+
3. Fe2+
4. V
5. Sc2−

Answers

Answer: Option (3) is the correct answer.

Explanation:

When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.

Atomic number of chlorine is 17. So, number of electrons present in Cl^(-) is 17 + 1 = 18 electrons.

Atomic number of cobalt is 27. So, number of electrons present in Co^(4+) is 27 - 4 = 23 electrons.

Atomic number of iron is 26. So, number of electrons present in Fe^(2+) is 26 - 2 = 24 electrons.

Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.

Atomic number of scandium is 21. So, number of electrons present in Sc^(2-) is 21 + 2 = 23 electrons.

Thus, we can conclude that out of the given species, Fe^(2+) has the greatest  number of electrons.

Among the given species, \boxed{3.{\text{ F}}{{\text{e}}^(2 + )}} has the greatest number of electrons.

Further Explanation:

The arrangement of electrons in various shells and sub-shells of an atom is called electronic distribution. The electron filling is done by keeping following rules and principles in mind:

(i). Aufbau principle

According to this, electron filling takes place in orbitals in the increasing order of their respective energies. The energy order of orbitals is as follows:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p

 

(ii) Hund’s rule

No electron will b epaired until each orbital is singly occupied.

(iii) Pauli’s exclusion principle

It states that two electrons can never have all the four quantum numbers same. The value of spin quantum number for both electrons must b edifferent.

1. According to the periodic table, the atomic number of Cl is 17 so its electronic configuration is 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^7}4{s^2}. It gains an electron to form {\text{C}}{{\text{o}}^(4 + )} ion and its configuration becomes 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^5}. So it has a total of 18 electrons.

2. According to the periodic table, the atomic number of Co is 27 so its electronic configuration is 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^7}4{s^2}. It loses four electrons, two 4s electrons and two 3d electrons to form   ion and its configuration becomes 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^5}. So it has a total of 23 electrons.

3. According to the periodic table, the atomic number of Fe is 26 so its electronic configuration is 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^6}4{s^2}. It loses two 4s electrons to form {\text{F}}{{\text{e}}^(2 + )} ion and its configuration becomes 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^6}. So it has a total of 24 electrons.

4. According to the periodic table, the atomic number of V is 23 so its electronic configuration is 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^3}4{s^2}. So it has a total of 23 electrons.

5. According to the periodic table, the atomic number of Sc is 21 so its electronic configuration is 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^1}4{s^2}. It gains two electrons to form {\text{S}}{{\text{c}}^(2 - )} ion and its configuration becomes 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^3}4{s^2}. So it has a total of 23 electrons.

Therefore, the maximum number of electrons is present in {\text{F}}{{\text{e}}^(2 + )} (24).

Learn more:

  1. Determine the ion with configuration  : brainly.com/question/7599542
  2. Identification of element which has electron configuration  :brainly.com/question/9616334

Answer details:

Grade: High School

Chapter: Electronic configuration of the elements

Subject: Chemistry

Keywords: electrons, Cl-, Co4+, Fe2+, V, Sc2-, 17, 27, 26, 21, 23, electronic configuration.

State charles's law. If a balloon occupies 885 cm3 volume at 20°C and 794 cm3 at - 10°C , prove that this is according to charles's law.

Answers

find the distance between

the following points:

a) AC0₂0) and B(5, 2)

A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius? Show your work

Answers

Formula

V/T = V1/T1

Givens

V = 430 L

T = - 42 °C = - 42 + 273 = 231°K

V1 = ??

T1 = 18°C + 273 = 291°K

The pressure is a constant.

Solution

420/231 = V1/291         Multiply by 291

420*291 / 231 = V1

V1 = 122220 / 231

V1 = 521.1 L  

Imagine our class has discovered a new element and named it Berkmarium. Berkmarium is known to have 3 naturally occurring isotopes. In nature, 70% of the element is Berkmarium-95, 28% is Berkmarium-97, and 2% is Berkmarium-94. Which isotope will the average atomic mass of Berkmarum be closest to, and why? Support your answer with a calculation.

Answers

Answer:

Detail is given below.

Explanation:

Given data;

Abundance of Berkmarium-95 = 70%

Abundance of Berkmarium-97 = 28%

Abundance of Berkmarium-94 = 2%

Average atomic mass closer to which isotope = ?

Solution:

1st of all we will calculate the average atomic mass of Berkmarium.

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass  = (70×95)+(28×97)+(2×94) /100

Average atomic mass =  6650 + 2716+ 188 / 100

Average atomic mass= 9554 / 100

Average atomic mass = 95.54 amu

The average atomic mass is closer to the isotope Berkmarium-95  because it is present in abundance as compared to the other two isotope. So this isotope constitute most of the part of Berkmarium.

Explain what happens to a fixed sample of gas when its temperature changes.

Answers

The Ideal gas law: pV=nRT

n=const.
R=const.

V~T, it means If temperature increase than volume of gas increase.
                          if temperature decrease than volume of gas decrease.

Rank standard molar entropy without a data table? Without referring to a data table, rank the following compounds by standard molar entropy (highest to lowest). I can do it with a data table but not sure how to proceed without. Thank you for your help. N2(g) H2(g) C2H4(g)

Answers

I think the correct order from most entropy to least entropy is C2H4, N2, and H2. My reasoning is that C2H4 has the biggest number of microstates which means that it will have the most entropy since it. I then based N2 and H2 from there weights (which indicates size) since the larger something is the more microstates it is likely to have. I hope that helps. Let me know if anything is unclear or if you want me to add more detail.