Which transformation changes triangle ABC to triangle A'B'C'? (1 point)3
-6 -5 -4 -3 -2 -1
2 3 4 5 6

A) Reflection about the y-axis followed by translation up by 8 units

B) Reflection about the X-axis followed by translation left by 4 units

C) Rotation 90 degrees clockwise about the origin

D) Rotation 180 degrees counterclockwise about the origin
Which transformation changes triangle ABC to triangle A'B'C'? (1 point) - 1

Answers

Answer 1
Answer: hm j think its b lmk if its correct

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A scientist suggests keeping indoor air relatively clean as follows: provide 2 or 3 pots of flowers for every 100 square feet of floor space under a ceiling of 8 ft. If your classroom has an 8 ft ceiling and measures 35 ft by 40 ft, how many pots should it have?

Answers

First we calculate classroom surface:
35*40=1400 square ft
we know that for every 100 square ft 2 or 3 pots can be put
so 1400/100=14
14*2=28
14*3=42
we need 28 or 42 pots

Jon paid $20 towards the cost of an $80 sweater. Write a numeric equation to show how much he still owes on the sweater.

Answers

Answer:

$80 - $20 = $60 left.

Step-by-step explanation:

Can you help me with any of these please (not lazy don't understand )

Answers

I believe the first one is h becuase there is a y on the left side.
for the second one just find the slope for the points and see which one doesn't fit in the groups (I would use tables)
and for the last one try writing equations for them.

but idk tho that's just what I would do.

One side of an isosceles triangle has a length of 19 m. The lengths of the other two sides are equal to one another, but are unknown. If the perimeter of the triangle is 51 m, what is the length of each unknown side?

Answers

Let x= side 1= 19
Let y= side 2=unknown
Let z= side 3=unknown
Since it is an isosceles triangle, two sides are equal, which happen to be y and z
Hence y=z

Perimeter of a triangle = Sum of all three sides
= x+y+z
51=19+2y [since we know x=19 and y=z, we know the perimeter is 51]
Solve now
32=2y
16=y
Since y=z
z= 16
Hence the unknown side's length is 16m
So the perimeter is 51. The base is 19. Subtract 19 from 51. 51 - 19 = 32. So 32 is the total length of the two equal unknown sides added together. Because the two sides must be equal, you can just divide 32 by 2. 32/2 = 16. Each of the two congruent sides are 16 m.

204 thousand of rename the number

Answers

two thousand four or twenty four thousand or two hundred and four thousand

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer. y = x³, y = √ x about the x-axis V= ?

Answers

Answer:

Step-by-step explanation:

To find the volume of the solid obtained by rotating the region bounded by the curves y=x3y=x3 and y=xy=x

​ about the x-axis, we'll use the method of cylindrical shells.

First, let's sketch the region bounded by these curves to better understand the shape. The intersection points of y=x3y=x3 and y=xy=x

​ are the points where x3=xx3=x

​, which gives x=0x=0 and x=1x=1.

Now, we'll set up the integral to find the volume using cylindrical shells:

The volume VV can be calculated using the formula:

V=2π∫abx⋅(f(x)−g(x)) dxV=2π∫ab​x⋅(f(x)−g(x))dx

Where aa and bb are the bounds of integration (in this case, 00 and 11), and f(x)f(x) and g(x)g(x) are the heights of the shells. In this case, f(x)=x3f(x)=x3 and g(x)=xg(x)=x

​.

So, the volume can be calculated as:

V=2π∫01x⋅(x3−x) dxV=2π∫01​x⋅(x3−x

​)dx

Now, simplify the integrand:

V=2π∫01(x4−xx) dxV=2π∫01​(x4−xx

​)dx

Split the integral into two parts:

V=2π∫01x4 dx−2π∫01xx dxV=2π∫01​x4dx−2π∫01​xx

​dx

Evaluate each integral separately:

V=2π[x55]01−2π[2x5/25/2]01V=2π[5x5​]01​−2π[5/22x5/2​]01​

V=2π(15)−2π(25)=2π5V=2π(51​)−2π(52​)=52π​

So, the volume of the solid obtained by rotating the region bounded by y=x3y=x3 and y=xy=x

​ about the x-axis is 2π552π​ cubic units.

The volume (V) of the solid obtained by rotating the region bounded by the curves \(y = x^3\) and \(y = √(x)\) about the x-axis is \(V = (8)/(15)\) cubic units.

To find the volume of the solid using the disk method, we integrate the cross-sectional area of each infinitesimally thin disk perpendicular to the x-axis.

The bounds of integration are determined by finding the x-values where the two curves intersect:

\[x^3 = √(x) \implies x^6 = x \implies x^5 = 1 \implies x = 1.\]

The radius of each disk is  \(r = x^3 - √(x)\), and the area of each disk is\(A = \pi r^2 = \pi \left((x^3 - √(x))\right)^2\).

The integral for the volume becomes:

\[V = \int_(0)^(1) \pi \left((x^3 - √(x))\right)^2 \, dx.\]

Evaluating this integral gives \(V = (8)/(15)\) cubic units.

In summary, the volume of the solid obtained by rotating the region bounded by \(y = x^3\) and \(y = √(x)\) about the x-axis is  \(V = (8)/(15)\) cubic units. The volume is calculated by integrating the cross-sectional areas of infinitesimally thin disks formed by rotating the region.

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