Find the area of
12d^6e^7

Answers

Answer 1

Answer: Simplifying
12d6e7 = 0

Solving
12d6e7 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '12'.
d6e7 = 0

Simplifying
d6e7 = 0

The solution to this equation could not be determined. -geteasysolution.com

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Use the functions f(x) = 3x – 4 and g(x) = x2 – 2 to answer the following questions. Complete the tables.

x f(x)–3–1 0 2 5

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For what value of the what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) {–3, –1, 0, 2, 5} does f(x) = g(x)? Answer:

consider the relation {(–4, 3), (–1, 0), (0, –2), (2, 1), (4, 3)}.Graph the relation.
State the domain of the relation. State the range of the relation. Is the relation a function? How do you know? Answer:

2. graph the function f(x) = |x + 2|.

Answer:

consider the following expression. Rewrite the expression so that the first denominator is in factored form. Determine the LCD. (Write it in factored form.) Rewrite the expression so that both fractions are written with the LCD. Subtract and simplify.

Answer:

Answers

$1)\nf(x)=3x-4\n|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\n=========================\n|\ f(x)\ |\ \ -13\ \ |\ \ -7\ \ |\ -4\ \ |\ \ \ 2\ \ \ |\ \ \ 11\ \ |\n\nf(-3)=3\cdot(-3)-4=-9-4=-13\nf(-1)=3\cdot(-1)-4=-3-4=-7\nf(0)=3\cdot0-4=0-4=-4\nf(2)=3\cdot2-4=6-4=2\nf(5)=3\cdot5-4=15-4=11$

$g(x)=x^2-2\n|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\n=========================\n|\ g(x)\ |\ \ \ \ \ 7\ \ \ \ |\ \ -1\ \ \ |\ -2\ \ |\ \ \ 2\ \ |\ \ \ 23\ \ |\n\ng(-3)=(-3)^2-2=9-2=7\ng(-1)=(-1)^2-2=1-2=-1\ng(0)=0^2-2=0-2=-2\ng(2)=2^2-2=4-2=2\ng(5)=5^2-2=25-2=23\n\nf(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x=2,\ \ \ \ because\ \ \ \ f(2)=2\ \ \ and\ \ \ g(2)=2$

$2)\nthe\ relation:\ \{(-4, 3), (-1, 0), (0, -2), (2,1), (4, 3)\}.\n\nthe\ domain:\ D=\{-4,-1,0,2,4\}\nthe\ range:\ R=\{3,0,-2,1\}\n\nThis\ relation\ is\ the\ function,\ because\ \ each\ number\n of\ the\ domain\ D\ has\ exactly\ one\ value\ in\ the\ range\ R.$

$3)\nf(x)=|x+2|\n\n|x+2|= \left \{ {\big{x+2\ \ \ \ \ if\ \ \ x \geq -2} \atop \big{-x-2\ \ \ if\ \ \ x<-2}} \right.$

Answer:

-11 and 0 for EDGE2020

f(4)= -11

If g(x)=2, x= 0

Step-by-step explanation:

For 100 births, P(exactly 55 girls)equals0.0485 and P(55 or more girls)equals0.184. Is 55 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less

Answers

Answer: 55 can not be considered a significantly high number of girls.

The probability is relevant to answering that question = $\text{P(55 or more girls)}=0.184$ .

Step-by-step explanation:

Given : For 100 births, $\text{P(exactly 55 girls)}=0.0485$

and $\text{P(55 or more girls)}=0.184$ .

Also it is said that consider a number of girls to be significantly high if the appropriate probability is 0.05 or less

To check :- If 55 girls in 100 births a significantly high number of girls .

We can see that $\text{P(exactly 55 girls)}=0.0485<0.05$

and $\text{P(55 or more girls)}=0.184>0.05$ , it means it is likely to occur 55 or more girls .

So 55 can not be considered a significantly high number of girls.

What value of x will make 2x-6=3x+1-x-7 true?

Answers

2x-6=3x=3x+1-x-7
2x-6=(3-1)x+7
2x-6=2x+8
2x-6-2x+6=2x-2x+8+6
0=0+14
No Solution

Hi there

2x - 6 = 3x + 1 - x - 7
First we need to combine like terms
2x - 6 = (3x - x) + (1 - 7)
2x - 6 = 2x - 6
2x - 2x = -6 + 6
0 = 0
Answer : All real numbers are solutions.

If you have any further questions please let me know :)

Perform the indicated operation and write and standard form. -7i(6i-3)

Answers

-7i (6i - 3)

Perform the distributed multiplication to eliminate the parentheses:

-7i (6i) - 7i (-3) = -42i² + 21i

IF i = √-1 , then the expression is equal to (42 + 21i) or 21(2 + i) .

$-7i(6i-3)=\n -42\cdot(-1)+21i=\n 42+21i$

The sum of two numbers is 30 and their difference is 2. Find the two numbers by writing and solving asystem of equations

Answers

The numbers are 14 & 16.

The equations you need to solve are:

x + y = 30
x - y = 2 ==> (redefine in terms of y) y = x - 2

substitute into first equation

x + x - 2 = 30
2x = 30 + 2
x = 32/2 = 16

16 + y = 30
30 - 16 = y = 14

x = 16
y = 14

And that's how that is done.

The correct answer is:

The numbers are 14 and 16.

Explanation:

Let x and y represent the numbers. Since the sum of the numbers is 30, this gives us the equation

x+y = 30.

Since the difference of the numbers is 2, this gives us the equation

x-y = 2.

This gives us the system

$\left \{ {{x+y=30} \atop {x-y=2}} \right.$

To solve this, we will eliminate one variable. Since the coefficients are all the same, but the y-variables have different signs, we will eliminate them by adding the equations together:

Divide both sides by 2:

2x/2 = 32/2

x = 16.

Substitute this back into our first equation:

16+y=30

Subtract 16 from each side:

16+y-16=30-16

y=14

Verify the identify. Justify each step.

tan ⊖ + cot ⊖ = 1/sin⊖cos⊖

Answers

tan ⊖ + cot ⊖ = 1/sin⊖cos⊖

sin ⊖ / cos ⊖ + cos ⊖/sin ⊖ = 1/sin⊖cos⊖

(sin ⊖*sin ⊖ + cos ⊖*cos ⊖)/sin⊖cos⊖ = 1/sin⊖cos⊖

[(sin ⊖)^2 + (cos ⊖)^2 ] /sin⊖cos⊖ = 1/sin⊖cos⊖

1/sin⊖cos⊖ =1/sin⊖cos⊖

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Find the area of 12d^6e^7

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Find the area of
12d^6e^7