The amplitude of a sound wave determines itsloudness
pitch
frequency
wavelength

Answers

Answer 1

Answer: The Loudness i believe.

Related Questions

Which action will result in a product with new chemical properties?A. shredding a newspaperB. breaking a mirrorC. cutting woodD. popping popcornThanks :)
The weather patterns seen on Earth are influenced greatly by the
A skater increases her speed from 5.0 m/s to 10 m/s in 5 seconds. What is the acceleration of the skater?
What is the process by which light energy from the sun is converted to food?
Please explain the method of making electricity from non renewable sources like coal?

How do the circulatory system and the respiratory system work together?

Answers

The circulatory system tends to pump blood around the whole body, while the respiratory system tend to facilitate the exchange of gas in the body so then the blood will look totally fresh. In simpler terms, the heart is connected to the lungs through the means of arteries and veins.

Answer:

Explanation:

In both transverse and longitudinal waves, the energy of the wave travels through but the particles do not move permanently.True

False

Answers

the correct answer is true

Earth has a mass of 5.97 x 1024kg, and a mean radius of 6.38 x 10m. What would be the orbitasatellite in orbit 1.44 x 108 m above Earth?
a. v, = 630m/s,
c. v, - 1630m/s,
T = 2.78 x 10 s
T=5.78 x 10s
b. V = 1820m/s,
d. V, - 1260m/s,
T = 6.78 x 106 s
T=5.78 x 10's
Please select the best answer from the choices provid

Answers

Answer:

v = 1630 m/s

T = 5.78 x 10^5 s

Explanation:

The tangential speed of the satellite can be found by requiring that the gravitational force on the satellite is equal to the centripetal force:

$G(Mm)/((R+h)^2)=m(v^2)/(R+h)$

where

G is the gravitational constant

M=5.97 x 1024kg is the Earth's mass

m is the satellite's mass

$R=6.38 \cdot 10^6 m$ is the Earth's radius

$h=1.44\cdot 10^8 m$ is the altitude of the satellite

v is the speed of the satellite

Solving for v,

$v=\sqrt{(GM)/(R+h)}=\sqrt{((6.67\cdot 10^(-11))(5.97\cdot 10^(24)kg))/(6.38\cdot 10^6 m+1.44\cdot 10^8 m)}=1627 m/s \sim 1630 m/s$

And the period of the orbit is equal to the ratio between the distance covered during one revolution (the circumference of the orbit) and the speed:

$T=(2 \pi (R+h))/(v)=(2\pi (6.38\cdot 10^6 m+1.44\cdot 10^8 m))/(1630 m/s)=5.79\cdot 10^5 s$

So the correct answer is

v = 1630 m/s

T = 5.78 x 10^5 s

3.why does energy as heat move away from the tropics and toward the pole in the global weather system? 5. A student is reading about predicted upcoming El Niño event. In what way could the student expect to see the global weather patterns change?

Answers

There are three types of heat transfer or heat propagation; conduction, convection and radiation. Heat transfer is the process by which heat projects externally however, depending on the temperature and pressure. Also called the movement of heat from a low temperatured state which increases as heat progresses.
Conduction is the heat transfer by contact, immediate contact.
Convection is the transfer of heat through air and water.
Radiation is the transfer of heat regardless of the presence of atoms or particles.

Answer:

Well since this question was asked years ago, I do believe that there is more solar energy at the equater and less at the poles.

Explanation:

You must exert a force of 4.5 N on a book to slide it across a table. If you do 2.7J of work in the process, how far have you moved the book?

Answers

Answer: 0.6m

Explanation:

Given that:

force = 4.5 N

Work done = 2.7J

Distance moved by the book = ?

Since work is done when force is applied on an object over a distance, apply the formula:

work = force x distance

2.7J = 4.5N x distance

Distance = (2.7J / 4.5N)

Distance = 0.6 m

Thus, the book was moved 0.6 metres far

A straight horizontal line on a speed-time graph means the speedis constant. This means the speed is not changing over time.
How is this different from a distance-time graph?

Answers

Answer:

its devavtion is different from the distance changes process

Explanation:

Final answer:

A speed-time graph and a distance-time graph represent different aspects of motion. A horizontal line on the former indicates a constant speed (zero acceleration), while a straight, upward-diagonal line on the latter shows constant speed. A flat horizontal line on a distance-time graph shows no movement.

Explanation:

A speed-time graph and a distance-time graph each depict different aspects of motion. A horizontal line on a speed-time graph does indeed indicate constant speed or zero acceleration; the object is moving at a constant speed. However, a distance-time graph shows how the position of the object changes over time.

Let's take an example. If a car is traveling at a constant speed, on a speed-time graph, this would be represented by a horizontal line. The height of the line above the time axis represents the constant speed.

On a distance-time graph, a car moving at constant speed will be represented by a straight line with a positive slope. This is because the position of the car is continuously changing (it's covering distance), and at a constant rate. The slope of the distance-time graph gives us the speed of the car.

So, while a flat horizontal line in a speed-time graph indicates constant speed, a flat horizontal line in a distance-time graph would indicate no change in position, i.e., the object is not moving at all.