PHYSICS MIDDLE SCHOOL

Which action will result in a product with new chemical properties?A. shredding a newspaper

B. breaking a mirror

C. cutting wood

D. popping popcorn

Thanks :)

Answers

Answer 1
Answer:

Popping popcorn action will result in a product with new chemical properties, therefore the correct answer for the given problem is option D.

What is a chemical reaction?

In a chemical reaction, one or more components referred to as reactants—are changed into one or more other substances—also referred to as byproducts.

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

The energy of the reactant is greater than the energy of the product because the extra energy is released during an exothermic reaction.

Popcorn would be the best choice since it would transform the pre-popped kernels into something else whereas the other options would merely change their outward look.

Thus, popping popcorn action will result in a product with new chemical properties, therefore the correct answer for the given problem is option D

Learn more about chemical reactions here,refer to the link ;

brainly.com/question/22817140

#SPJ6

Answer 2
Answer: the answer would be popping popcorn because while you are changing the physical appearance in the rest of the choices only popping the popcorn would turn the prepopped kernels into something else

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​

Answers

Answer:

AB: decreasing acceleration

BC: constant acceleration

CD: constant acceleration.

Explanation:

(1) Here is the plot of velocity and time.

There is no information of distance.

=>  There are two options that will be eliminated.

Moving backwards at constant speed.

Moving forward at constant speed.

(2) Only for remaining options will be considered:

Constant acceleration.

Decreasing acceleration.

Increasing acceleration.

Stationary.

(3) The formula for calculating final velocity:

v_final = v_initial + acceleration x time

Let's see BC: (this is a segment straight line)

v_C = v_B + acceleration x time

v_C = v _B = 40 (km/h)

time > 0

=> acceleration a = 0 (km/h^2) => constant acceleration

Let's see CD: (this is also a segment straight line)

v_D = v_C + acceleration x time

v_D = 0 (km/h)

v_C = 40 (km/h)

time > 0

=> acceleration = -40/time (km/h^2) < 0 => constant (negative) acceleration

Let's see AB (a segment straight line + a right curve)

On the segment straight line:

Using the same way we considered CD,

the acceleration is constant (positive) acceleration

On the right curve (with direction from A to B), its slope started to decrease. This slope is the change of acceleration.

=> Generally on AB (considering both segment straight line and the right curve), the acceleration is decreasing acceleration

P.S: Take the derivative of v_final with respect to acceleration a, plot a as a function of time , then you will see what really happened ^^.

Hope this helps!
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