A 12-volt car battery uses about 660 amps. How much power does it use?a) 7,920 watts

b) 672 watts

c) 648 watts

d) 55 watts

Answers

Answer 1
Answer: We know, Power = Voltage * Current
P = 660 * 12 = 7920 watt

In short, Your Answer would be Option A

Hope this helps!
Answer 2
Answer:

Answer:

7,920

Explanation:


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What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water?

Answers

Considering the definition of percentage by mass, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percent by mass= (mass of solute)/(mass of solution)x100

In this case, you know:

  • mass of solute= 5 g
  • mass of water= 75 g
  • mass of solution= mass of solute + mass of water= 5 + 75 g= 80 g

Replacing:

percent by mass= (5 g)/(80 g)x100

Solving:

percent by mass= 6.25 %

Finally, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

Learn more:

Hello!

What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

We have the following data:

m1 (solute mass - iron II sulfate) = 5.0 g

m2 (solvent mass - water) = 75.0 g

m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g

%m/m (percent mass by mass) = ?

We apply the data to the formula

\%\:m/m = (m_1)/(m)*100

\%\:m/m = (5)/(80)*100

\%\:m/m = 0.0625*100

\boxed{\boxed{\%\:m/m = 6.25}}\Longleftarrow(solute\:in\:percent)\:\:\:\:\:\:\bf\blue{\checkmark}

Answer:  

The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%  

_______________________  

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

You are sitting in a car that isn't moving; suddenly, the car quickly accelerates. your body seems to be pushed back against the seat. which word best explains why your body seemed to be pushed backward against the seat?

Answers

Explanation :

When the car accelerates, our body pushed backward against the seat. This effect is due to inertia.

When the car starts suddenly, our feet also comes in motion. But the rest body is still at rest.

Inertia is the property of a body which opposes its state of rest or state of motion.

In this case, the inertia of the passenger resists the motion of the car. So, he pushed backwards as the car started.  

According to the Law of Inertia, our upper body was in rest and it wanted to remain in that condition.....

75 Centimeters to decameters and Kilometer​

Answers

Answer - 75cm=0.075 decametre (divide the length value by 1000.)

75cm=0.00075 kilometer (divide the length value by 100000).

Driving home from school one day, you spot a ball rolling out into the street (Figure 5-21). You brake for 1.20 s, slowing your 950-kg car from 16.0 m/s to 9.50 m/s.a) What was the average force exerted on your car during braking?
b) How far did you travel while braking?

Answers

a ) v = v o + a t  ( the acceleration will be negative )
9.50 = 16.0 + a * 1.2
a * 1.2 = -16.0 + 9.50
a * 1.2 = - 6.5 
a = - 6.5 : 1.2
a = - 5.4167 m/s²
F = m * a = 950 kg * 5.4167 m/s²
F = 5,145.8 N ( the average force exerted on a car during braking )
b ) d = v o - a t² / 2
d = 16.0 * 1.2 - ( 5.4167 * 1.2² / 2 ) =
= 19.20 - 3.90 = 15.30 m

Ted William drops a ball from 14.5 meter to a desk that is 1.9 meters tall. What is the final speed of the ball right before it hits the desk.

Answers

Answer:

15.7m/s

Explanation:

To solve this problem, we use the right motion equation.

 Here, we have been given the height through which the ball drops;

 Height of drop = 14.5m - 1.9m  = 12.6m

The right motion equation is;

      V²  = U² + 2gh

V is the final velocity

U is the initial velocity  = 0

g is the acceleration due to gravity  = 9.8m/s²

h is the height

  Now insert the parameters and solve;

       V² = 0² + 2 x 9.8 x 12.6

      V²  = 246.96

       V = √246.96  = 15.7m/s

An individual center of gravity can usually be found __________?A.
just above the belly button
B.
just above the knees
C.
just below the neck
D.
just below the hips

Answers

An individual center of gravity can usually be found just below the hips. The correct option is D.

Usually, a person's centre of gravity is situated just below the hips. The location where the body's mass is equally distributed in all directions is referred to as the center of gravity.

The centre of gravity in a standard standingposition is below the hips, specifically in the area of the pelvis. This position gives the body stability and balance, enabling effective movement and control.

Thus, the correct option is D.

For more details regarding gravity, visit:

brainly.com/question/31321801

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The answer is A. Just above the belly button.