If a frilled lizard is 90 centimeters long and it's tail is 2/3 of the body's length. how long is the tail

Answers

Answer 1
Answer: 2/3 of 90=2/3 times 90=180/3=60

tail is 60cm long
Answer 2
Answer: The tail of the Frilled Lizard is 60 centameters

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the area of a triangle is 41 yards to the second power with a base of 5 yard what is the height in yard

Answers

okay here's a example
area = 1/2 base x height

area = 1/2 (7/5 yd) x 5/8 yd

area = 7/10 yd x 5/8 yd

area = 35/80 yd

area = 7/16 yd^2

Answer:

8

Step-by-step explanation:

A=41

41/5=8

h=8

If f(x)=x^2-5 and g(x)=6x then g(f(x)) is equal to

Answers

g(x) = 6x 

g(f(x)) 
= 6((x^2) - 5) 
= (6x^2) - 30 

so its equal to
(6x^2) - 30
Plug f(x) as x in g(x) and you get 6(x^2-5), which is g(f(x)) = 6x^2-30.

What is 1/6 + 1/4 anwer for 10 points

Answers

answer:

To solve the expression 1/6 + 1/4, we need to find a common denominator for the fractions. The common denominator is the smallest multiple that both denominators (6 and 4) share. In this case, the least common denominator (LCD) is 12.

To convert 1/6 into a fraction with a denominator of 12, we multiply both the numerator and denominator by 2. This gives us 2/12.

To convert 1/4 into a fraction with a denominator of 12, we multiply both the numerator and denominator by 3. This gives us 3/12.

Now that we have both fractions with the same denominator, we can add them together.

2/12 + 3/12 equals 5/12.

So, 1/6 + 1/4 equals 5/12.

In conclusion, when you add 1/6 and 1/4 together, the sum is 5/12.

alli <3

What are the domain, range, and asymptote of h(x) = 6x – 4?

Answers

The domain is x = 1, 2, 3, 4, 5...... ∈ R (set of real number).

Range:  (0,∞)

Asymptote: y=0.

What is Domain, Range and Asymptote?

The range of a function is the set of output values for the dependent variable.

The range, however, is bounded by the horizontal asymptote of the graph of f(x).

A straightline that continuously approaches a certain curve without ever meeting it is an asymptote.

Given:

h(x) = 6x – 4

Now, the domain is the input value as

x = 1, 2, 3, 4, 5...... ∈ R (set of real number)

So, h(1) = 6-4 =2

and, h(2) = 12-4 = 8

and, the range is (0,∞)

Now, the asymptote h(x)= 0

6x-4 = 0

x= 2/3.

Learn more about Domain and Range here:

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h(x)=6x−4  or  h(x)=6x−4 
If the former, the domain is all real numbers, often denoted by the symbol R
the range is (0,∞) 
asymptote is y = 0

Two dice are tossed together. What is the probability of getting an odd number on the second die and a total of five?1/18

11/18

7/18

4/9

Answers


Probability = (number of ways to succeed) / (total possible outcomes) .

The total possible results of rolling two dice is

   (6 on the first cube) x (6 on the second one) = 36 possibilities.

How many are successful ?  I need you to clarify something first.
You said that the 'second die' shows an odd number.  When a pair
of dice is rolled, the problem usually doesn't distinguish between them. 
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
unless they were, say, painted different colors, and we wouldn't know
which one is the second one.

Oh well, I'll just work it both ways:

First way: 
Two identical dice are tossed.
The total is 5 and ONE cube shows an odd number.

How can that happen ?

1 ... 4
4 ... 1
3 ... 2
2 ... 3         

Four possibilities.  Probability = 4/36 = 1/9 = 11.1% .

=======================================

Second way:
 
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.

How can that happen:

B ... W
4 .... 1
2 .... 3

Only two possibilities.  Probability = 2/36 = 1/18 = 5.6% .

How do i find the fourth side of quadrilateral if three sides are given?

Answers

The length of a fourth side of a quadrilateral cannot be directly calculated from just the lengths of the other three sides. Additional information like the quadrilateral type, or types of angles within the quadrilateral, would be needed to calculate the length of the fourth side.

In mathematics, specifically geometry, the length of the fourth side of a quadrilateral (a shape with four sides) cannot be directly determined just by knowing the lengths of the three other sides. This is because a quadrilateral can be of multiple shapes such as squares, rectangles, parallelograms, trapezoids, etc., each having different properties.

However, if you have additional information like the types of angles within the quadrilateral or if it's a specific type of quadrilateral (rectangle, square, etc.), then you could possibly calculate the length of the fourth side.

For example, in a rectangle, opposite sides are equal so if you know three sides and know it's a rectangle, then the fourth side would be equal to the opposite side.

Without any additional information, there isn't a simple formula that can be used to directly calculate the length of the fourth side of any arbitrary quadrilateral.

Learn more about the topic of Quadrilateral here:

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Answer:

\mathrm{Well,\ just\ by\ knowing\ the\ length\ of\ sides,\ you\ won't\ be\ able\ to\ calculate\ the}\n\mathrm{fourth\ side,\ unless\ you\ know\ that\ is\ an\ especial\ type\ of\ quadrilateral\ (for}\n\mathrm{example:\ rectangle,\ parallelogram,\ rhombus,\ square,\ etc).\ You\ will\ also\ need}\n\mathrm{the\ two\ unknown\ angles\ between\ those\ three\ sides.\ You\ will\ get\ what\ I\ mean\ if}\n\mathrm{you\ look\ the\ below\ diagram:}

\mathrm{Of\ course,\ you\ won't\ know\ how\ far\ the\ points\ A\ and\ D\ are\ unless\ you\ know}\n\mathrm{\angle B\ and\ \angle\ C.\ }

\mathrm{This\ concept\ works\ for\ triangles\ too.\ You\ can't\ find\ the\ third\ side\ of}\n\mathrm{a\ triangle\ only\ by\ knowing\ the\ length\ of\ the\ other\ two\ sides.\ You\ need\ to\ know}\n\mathrm{the\ angles\ between\ the\ two\ given\ sides.}