If the light ray hits a mirror at a 40 degree angle what angle will the ray of light be reflected

Answers

Answer 1
Answer:

The angle will also be 40 degrees because the reflected ray has the same angle as the incident ray.

What is the reflection of light?

When light rays reflect off a surface, migrate from one transparent medium to another, or travel through a medium whose composition is constantly changing, they change direction.

The angle of the reflected ray is equal to the angle of the incident beam when reflected off a flat surface, according to the law of reflection. (By convention, all angles in geometrical optics are measured with respect to the surface's normal, i.e. a line perpendicular to the surface.)

The reflected ray always falls in the plane specified by the incident light and the surface normal. To comprehend the pictures formed by planar and curved mirrors, the law of reflection can be applied.

As per the question, the light ray hits a mirror at a 40-degree angle.

Thus, the angle will also be 40 degrees because the reflected ray has the same angle as the incident ray.

To learn more about the reflections click here:

brainly.com/question/15487308

#SPJ2

Answer 2
Answer: It will be also 40 degrees as reflected ray has an equal angle to incident ray. 

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Find the standard equation of the circle that satisfies the conditions.Center (-1,-3), passing through the point (3,0)

Write the equation of the line that contains the given point and has the given slope. (–1, 4), slope is –3

Answers

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})~\hspace{10em}slope = m\implies -3\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-4=-3[x-(-1)]\n\n\ny-4=-3(x+1)\implies y-4=-3x-3\implies y=-3x+1

Y = -3x + 4. This is because the y value is -4 so that would be the y intercept and -3 is the slope as said in the question

How do you find the derivative of h(t)=sqrt(t)(1-t^2)

Answers

Answer:

Step-by-step explanation:

h(t)=√((t)(1-t^2))\nh^(2)(t)=t(1-t^2)=t-t^3\n diff. w.r.t.,\n2 h(t)h'(t)=1-3t^2\nh'(t)=(1-3t^2)/(2 h(t)) \nh'(t)=(1-3t^2)/(2√((t)(1-t^2)) )

Pls help Zoey is trying to write an equation in slope intercept form. She knows slope intercept form is y=mx+b. She is given the slope is 3 and the y intercept is 10. When she plugs it in she gets 10=3x+b. What mistake did zoey make and how can she fix it?

Answers

Answer:

the mistake that zoey had made while writing the equation was putting the y-intercept in the wrong place.in the slope intercept from the equation is y=mx+b.y is the product or the line, m is the slope, b is the y-intercept, the actual equation should be y=3x+10,instead what zoey had which was 10=3x+b. she guessd by pairing the y-intercept with y instead of b.

Step-by-step explanation:

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A map is drawn to scale 1 Cm 10km .
Find the actual distance represented by 54 mm

Answers

It's a simple proportion. 1cm = 10mm, so 54mm = 5.4 cm. 1/10=5.4/x, where x is equal to 54 (10 x 5.4).

The sum of the roots of the equation (1/2)x^2-(5/4)x-3=0

a.5/2
b.2
c.1/2

Answers

(1/2)x² - (5/4)x - 3 = 0

0.5x² - 1.25x - 3 = 0

Comparing to the quadratic function, ax² + bx + c = 0,    
a = 0.5,  b = -1.2,  c = -3.

Sum of roots = -b/a   =    -(-1.25)/0.5 =    1.25/0.5 = 2.5

2.5 = 5/2  Option (a)
A)5/2 is the answer.

Can you help? Thanks!​

Answers

Answer:

(7, 2).

Step-by-step explanation:

The median from A intersects BC at it's midpoint.

To find the midpoint of BC:

This is (x1, y1) where x1 = (sum of the x_values of B and C) / 2)  and where y1

= (sum of the y_values of B and C) / 2)

This is (2+12)/2,  (1 + 3)/2

= (7, 2).